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10-RLC krugovi.pdf

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1=LCRt2− ⎡ 1 R ⎤2Lcos ⎢2⎥q = qme t −⎢⎣LCSlučaj 2:R4L224L⎥⎦Naboj više ne oscilira, nema titranja.Naboj monotono pada prema: 2q = q e −Struja pada po istom zakonu.mRtLTzv. KRITIČNO APERIODIČNO izbijanje.Q = Q e −0Rt2L

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