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Similary, we also get<br />

vec( ̂B<br />

{<br />

n ̂Σεn ̂Bn − B 0 Σ ε B 0 ) = I m ⊗ ( ̂B<br />

}<br />

n ̂Σεn ) + ((B 0 Σ ε ) ⊗ I m ) vec( ̂B n − B 0 )<br />

+ (B 0 ⊗ ̂B n )D m vech( ̂Σ εn − Σ ε )<br />

and<br />

vec(Ĉn ̂Σ xn Ĉ ′ n − C 0 Σ x0 C ′ 0) =<br />

{I m ⊗ (Ĉn ̂Σ<br />

}<br />

xn ) + ((C 0 Σ x ) ⊗ I m )M mr vec(Ĉ′ n − C ′ 0)<br />

+ (C 0 ⊗ Ĉn)D r vech( ̂Σ xn − Σ x ).<br />

Let<br />

{<br />

 ∗ n = −P m I m ⊗ (Ân ̂Σ<br />

}<br />

εn ) + ((A 0 Σ ε0 ) ⊗ I m )M mm ,<br />

{<br />

̂B ∗ n = −P m I m ⊗ ( ̂B<br />

}<br />

n ̂Σεn ) + (B 0 Σ ε0 ) ⊗ I m ,<br />

{<br />

Ĉ ∗ n = −P m I m ⊗ (Ĉn ̂Σ<br />

}<br />

xn ) + ((C 0 Σ x0 ) ⊗ I m )M mr ,<br />

Ê ∗ n = P m (I m 2 − B 0 ⊗ ̂B n − A 0 ⊗ Ân)D m ,<br />

̂X∗ n = −P m (C 0 ⊗ Ĉn)D r .<br />

We then have<br />

√ n(̂ωn − ω 0 ) =<br />

(<br />

Â∗ n<br />

̂B ∗ n<br />

Ĉ ∗ n<br />

Ê ∗ n<br />

̂X ∗ n<br />

⎛<br />

) √n ⎜<br />

⎝<br />

⎞<br />

â n − a 0<br />

̂bn − b 0<br />

ĉ n − c 0<br />

, (32)<br />

̂γ εn − γ ε0<br />

⎟<br />

⎠<br />

̂γ xn − γ x0<br />

where â n = vec(Â′ n), ̂b n = vec( ̂B n ) and ĉ n = vec(Ĉ′ n) are the estimators of a 0 =<br />

vec(A ′ 0), b 0 = vec(B 0 ) and c 0 = vec(C ′ 0) respectively. Note that<br />

⎛<br />

⎞<br />

â n − a 0<br />

⎛<br />

⎞<br />

̂bn − b 0<br />

̂θ n − θ 0<br />

ĉ n − c 0<br />

= Ψ ⎜ ̂γ ⎝ εn − γ ε0<br />

⎟<br />

⎠ , (33)<br />

⎜ ̂γ<br />

⎝ εn − γ ε0<br />

⎟ ̂γ<br />

⎠<br />

xn − γ x0<br />

̂γ xn − γ x0<br />

25

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