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Atomic Structure Theory

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52 2 Central-Field Schrödinger Equation<br />

where N is the number of bound electrons in the atom.<br />

In the Thomas-Fermi theory, the electronic potential is given by the classical<br />

potential of a spherically symmetric charge distribution,<br />

R<br />

1<br />

Ve(r) = 4πr ′2 ρ(r ′ )dr ′ , (2.99)<br />

0<br />

r><br />

where r> = max (r, r ′ ). The total energy of the atom in the Thomas-Fermi<br />

theory is obtained by combining (2.97) for the kinetic energy density with the<br />

classical expressions for the electron-nucleus potential energy and the electronelectron<br />

potential energy to give the following semi-classical expression for the<br />

energy of the atom:<br />

<br />

R<br />

3<br />

E =<br />

0 10 (3π2 ) 2/3 ρ 2/3 − Z<br />

R<br />

1 1<br />

+ 4πr<br />

r 2 0 r><br />

′2 ρ(r ′ )dr ′<br />

<br />

4πr 2 ρ(r)dr .<br />

(2.100)<br />

The density is determined from a variational principle; the energy is required<br />

to be a minimum with respect to variations of the density, with the<br />

constraint that the number of electrons is N. Introducing a Lagrange multiplier<br />

λ, the variational principal δ(E − λN) =0gives<br />

<br />

R<br />

1<br />

0 2 (3π2 ) 2/3 ρ 2/3 − Z<br />

r +<br />

R<br />

1<br />

4πr<br />

0 r><br />

′2 ρ(r ′ )dr ′ <br />

− λ 4πr 2 δρ(r)dr =0.<br />

(2.101)<br />

Requiring that this condition be satisfied for arbitrary variations δρ(r) leads<br />

to the following integral equation for ρ(r):<br />

1<br />

2 (3π2 ) 2/3 ρ 2/3 − Z<br />

r +<br />

R<br />

1<br />

4πr<br />

0 r><br />

′2 ρ(r ′ )dr ′ = λ. (2.102)<br />

Evaluating this equation at the point r = R, whereρ(R) = 0, we obtain<br />

λ = − Z<br />

R<br />

1<br />

+ 4πr<br />

R R 0<br />

′2 ρ(r ′ )dr ′ Z − N<br />

= − = V (R) , (2.103)<br />

R<br />

where V (r) is the sum of the nuclear and atomic potentials at r. Combining<br />

(2.103) and (2.102) leads to the relation between the density and potential,<br />

1<br />

2 (3π2 ) 2/3 ρ 2/3 = V (R) − V (r) . (2.104)<br />

Since V (r) is a spherically symmetric potential obtained from purely classical<br />

arguments, it satisfies the radial Laplace equation,<br />

which can be rewritten<br />

1<br />

r<br />

d 2<br />

rV (r) =−4πρ(r) , (2.105)<br />

dr2

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