Medium Voltage technical guide - Schneider Electric
Medium Voltage technical guide - Schneider Electric
Medium Voltage technical guide - Schneider Electric
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
Design rules Busbar calculation<br />
Calculation of θt must be<br />
looked at in more detail because the<br />
required busbars have to withstand<br />
Ir = 2500 A at most<br />
and not 2689 A.<br />
For the short-time withstand current (lth)<br />
b We assume that for the whole duration (3 seconds):<br />
v all the heat that is given off is used to increase the<br />
temperature of the conductor<br />
v radiation effects are negligible.<br />
The equation below can be used to calculate<br />
the short-circuit temperature rise:<br />
With:<br />
∆θsc = 0.24 • ρ 20 • Ith 2 • tk<br />
(n • S) 2 • c • δ<br />
c Specific heat of the metal: copper 0.091 kcal/kg °C<br />
S Bar cross-section 10 cm 2<br />
n Number of bar(s) per phase 2<br />
Ith Short-time withstand current:<br />
(maximum short-circuit current, r ms value) 31 500 A r ms<br />
tk<br />
Short-time withstand current<br />
duration (1 to 3 s)<br />
3 in s<br />
δ Density of the metal: copper 8.9 g/cm3 ρ20 Conductor resistivity at 20°C: copper 1.83 µΩ cm<br />
(θ - θn) Permissible temperature rise 50 K<br />
v<br />
The temperature rise due to the short-circuit is:<br />
∆θsc =<br />
∆θsc = 4 K<br />
0.24 • 1.83 10 - 6 • ( 31500 ) 2 • 3<br />
( 2 • 10 ) 2 • 0.091 • 8.9<br />
The temperature, θt of the conductor after<br />
the short-circuit will be:<br />
θ t = θn + (θ – θn) + ∆θsc<br />
θ t = 40 + 50 + 4 = 94 °C<br />
For I = 2689 A (see calculation in the previous pages)<br />
36 AMTED300014EN.indd