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Medium Voltage technical guide - Schneider Electric

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Design rules Busbar calculation<br />

Calculation of θt must be<br />

looked at in more detail because the<br />

required busbars have to withstand<br />

Ir = 2500 A at most<br />

and not 2689 A.<br />

For the short-time withstand current (lth)<br />

b We assume that for the whole duration (3 seconds):<br />

v all the heat that is given off is used to increase the<br />

temperature of the conductor<br />

v radiation effects are negligible.<br />

The equation below can be used to calculate<br />

the short-circuit temperature rise:<br />

With:<br />

∆θsc = 0.24 • ρ 20 • Ith 2 • tk<br />

(n • S) 2 • c • δ<br />

c Specific heat of the metal: copper 0.091 kcal/kg °C<br />

S Bar cross-section 10 cm 2<br />

n Number of bar(s) per phase 2<br />

Ith Short-time withstand current:<br />

(maximum short-circuit current, r ms value) 31 500 A r ms<br />

tk<br />

Short-time withstand current<br />

duration (1 to 3 s)<br />

3 in s<br />

δ Density of the metal: copper 8.9 g/cm3 ρ20 Conductor resistivity at 20°C: copper 1.83 µΩ cm<br />

(θ - θn) Permissible temperature rise 50 K<br />

v<br />

The temperature rise due to the short-circuit is:<br />

∆θsc =<br />

∆θsc = 4 K<br />

0.24 • 1.83 10 - 6 • ( 31500 ) 2 • 3<br />

( 2 • 10 ) 2 • 0.091 • 8.9<br />

The temperature, θt of the conductor after<br />

the short-circuit will be:<br />

θ t = θn + (θ – θn) + ∆θsc<br />

θ t = 40 + 50 + 4 = 94 °C<br />

For I = 2689 A (see calculation in the previous pages)<br />

36 AMTED300014EN.indd

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