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CONVERSION AND REACTOR SIZING

CONVERSION AND REACTOR SIZING

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Sizing in PFR<br />

Example: Determine the volume in PFR to achieve a 80 % conversion.<br />

dX<br />

For PFR : FA0<br />

⋅ = −rA<br />

dV<br />

0 0.<br />

8 0 0.<br />

8<br />

dX F FA0<br />

Re arranging : V = FA0<br />

⋅ ∫ = ⋅ dX<br />

− r ∫ − r<br />

Let’s numerically evaluate the integral with trapezoidal rule<br />

0.<br />

8<br />

∫<br />

0<br />

FA0<br />

⋅ dX<br />

− r<br />

A<br />

⇒<br />

FA0<br />

f ( X ) = =<br />

− r<br />

0<br />

A X = 0<br />

FA0<br />

f ( X ) = =<br />

− r<br />

A<br />

A X = 0.<br />

8<br />

0<br />

0.<br />

89<br />

8.<br />

0<br />

0.<br />

8<br />

3<br />

V = ⋅(<br />

0.<br />

89 + 8.<br />

0)<br />

= 8.<br />

89⋅<br />

0.<br />

4 = 3.<br />

556m<br />

2<br />

With five point quadrature V = 2.165 m3 Comparing CSTR & PFR Sizing<br />

V CSTR > V PFR for the same conversion and rxn conditions.<br />

The reason is that CSTR always operates at lowest rxn rate. PFR starts at a high<br />

y p g<br />

rate, then gradually decreases to the exit rate.<br />

A<br />

12

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