tesi R. Valiante.pdf - EleA@UniSA
tesi R. Valiante.pdf - EleA@UniSA
tesi R. Valiante.pdf - EleA@UniSA
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30<br />
⎛<br />
⎜<br />
⎜−<br />
k<br />
⎝<br />
2<br />
−<br />
K<br />
F<br />
2<br />
ω ⎞<br />
+ 2 ⎟<br />
⎟e<br />
c0<br />
⎠<br />
( kx−ωt<br />
)<br />
i<br />
= 0<br />
(1.20)<br />
This equation must fulfill Eq.1.21 in order to admit non-trivial solutions<br />
2 ⎛<br />
= c0<br />
⎜k<br />
⎝<br />
or, alternatively, Eq.1.22.<br />
K ⎞<br />
+ ⎟<br />
F ⎠<br />
2<br />
2<br />
ω ω(<br />
k)<br />
2<br />
2 ω<br />
k = − 2<br />
c<br />
0<br />
K<br />
F<br />
Here the phase velocity, p<br />
ω = (1.21)<br />
( ω)<br />
c , is different from the 0<br />
k = k (1.22)<br />
c of the taut string. Indeed,<br />
substituting ω = kc p in Eq.1.21 or Eq.1.22, the result of Eq.1.23 is obtained.<br />
⎛ K<br />
⎜1+<br />
⎝ Fk<br />
2 2<br />
= c0<br />
2<br />
⎞<br />
⎟<br />
⎠<br />
c p c ( k)<br />
c p p<br />
Alternatively, one can obtain the results in Eq.1.24.<br />
k<br />
2<br />
=<br />
K<br />
F<br />
2 2 ( c c ) −1<br />
p<br />
0<br />
= (1.23)<br />
( c )<br />
k = k (1.24)<br />
Another set of relations can be obtained by eliminating k from Eq.1.22 or ω<br />
from Eq.1.24, to give Eq.1.25<br />
and Eq. 1.26<br />
K<br />
Fc<br />
2<br />
p<br />
ω =<br />
ω(<br />
c<br />
2 2<br />
p )<br />
( c c ) −1<br />
p<br />
0<br />
2<br />
p<br />
ω = (1.25)