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Chapter 9 - University of Dayton Academic Webserver

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324<br />

SF 6<br />

<strong>Chapter</strong> 9: Molecular Structures<br />

6 + 6(7)<br />

= 48<br />

. . .<br />

..<br />

. ..<br />

..<br />

. .<br />

F<br />

F. F<br />

S<br />

F<br />

.. F<br />

. .<br />

. F.<br />

.<br />

. .<br />

.. .<br />

.<br />

AX 6E 0<br />

octahedral<br />

octahedral<br />

93. (a) Molecules <strong>of</strong> liquid methanol (CH 3 OH) interact via dipole-dipole interactions and hydrogen bonding.<br />

These intermolecular forces must be overcome to evaporate liquid methanol.<br />

H<br />

H C<br />

H<br />

O<br />

H<br />

H<br />

O<br />

H<br />

C<br />

H<br />

H<br />

sp 3 d 2<br />

(b) Decomposing molecules into other molecules requires breaking covalent bonds, so the forces that must<br />

be overcome are the intramolecular (covalent) forces. The reactant molecule looks like this:<br />

H<br />

O O<br />

H<br />

and the product molecules look like this:<br />

H O<br />

H and O O .<br />

So, all the polar covalent bonds in the reactants have to be broken to make some <strong>of</strong> the new bonds in<br />

the products:<br />

H<br />

2 O O<br />

2<br />

H<br />

H O<br />

H<br />

+<br />

O O<br />

(c) Molecules <strong>of</strong> solid urea (H 2 NCONH 2 ) interact via dipole-dipole interactions and hydrogen bonding.<br />

Some <strong>of</strong> these intermolecular forces must be overcome to melt solid urea.<br />

H<br />

H<br />

N C<br />

O<br />

N<br />

H H<br />

H<br />

H<br />

N C<br />

O<br />

N<br />

H H<br />

H<br />

H<br />

N C<br />

O<br />

N<br />

H H

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