Chapter 9 - University of Dayton Academic Webserver

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$MATH 219 - Differential Equations Quiz 3 Name Solutions Date ...$

324 SF 6 Chapter 9: Molecular Structures 6 + 6(7) = 48 . . . .. . .. .. . . F F. F S F .. F . . . F. . . . .. . . AX 6E 0 octahedral octahedral 93. (a) Molecules of liquid methanol (CH 3 OH) interact via dipole-dipole interactions and hydrogen bonding. These intermolecular forces must be overcome to evaporate liquid methanol. H H C H O H H O H C H H sp 3 d 2 (b) Decomposing molecules into other molecules requires breaking covalent bonds, so the forces that must be overcome are the intramolecular (covalent) forces. The reactant molecule looks like this: H O O H and the product molecules look like this: H O H and O O . So, all the polar covalent bonds in the reactants have to be broken to make some of the new bonds in the products: H 2 O O 2 H H O H + O O (c) Molecules of solid urea (H 2 NCONH 2 ) interact via dipole-dipole interactions and hydrogen bonding. Some of these intermolecular forces must be overcome to melt solid urea. H H N C O N H H H H N C O N H H H H N C O N H H
Chapter 9: Molecular Structures 325 (d) Molecules of liquid HCl interact via dipole-dipole interactions. These intermolecular forces must be overcome to boil liquid HCl. + H Cl 94. The answers given here are not the only correct answers. They are only examples. (a) XH 3 would have a central atom with one lone pair of electrons, if X = N. (b) XCl 3 would have no lone pairs on the central atom, if X = B. H . .. .. H . N H + .. . Cl . Cl H .. .. . B Cl Cl (c) XF 5 would have no lone pairs on the central atom, if X = P. .. . F.. . . . F. . . . . F P . . F. . . . F . . . (d) XCl 3 would have two lone pairs on the central atom, if X = I. . . . Cl .. . I . Cl . . . . . Cl . . . 95. (a) XCl 2 would have a central atom with no lone pair of electrons, if X = Be. .. . Cl .. .. .. . Be Cl (b) XH 2 would have two lone pairs on the central atom, if X = O. H . . . . O H (c) XF 4 would have one lone pair on the central atom, if X = S. .. . F.. . . . F. . . . . F S . . . F. .
Page 1 and 2: Review Questions Chapter 9: Molecul
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Page 7 and 8: . . . . O . . . .. .. . Cl O Chapte
Page 9 and 10: Chapter 9: Molecular Structures 291
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Page 21 and 22: ΔENC-Cl = ENCl - ENC = 3.0 - 2.5 =
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Page 29 and 30: H CH 3 CH 2 C C OH NH 2 Chapter 9:
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Page 39 and 40: I 3 - ICl 3 91. continued Molecule
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Page 51 and 52: C O H C None of the other bonds cha

Chapter 9 - University of Dayton Academic Webserver

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