EXAM P SAMPLE SOLUTIONS
EXAM P SAMPLE SOLUTIONS
EXAM P SAMPLE SOLUTIONS
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74. Solution: E<br />
First note R = 10/T . Then<br />
⎡10 ⎤ ⎡ 10⎤ ⎛10<br />
⎞<br />
F R (r) = P[R ≤ r] = P<br />
⎢<br />
≤ r = P T ≥ = 1−FT⎜ ⎣T ⎥<br />
⎦<br />
⎢<br />
⎣ r ⎥<br />
⎟ . Differentiating with respect to<br />
⎦ ⎝ r ⎠<br />
⎛ ⎛10 ⎞⎞ ⎛ d ⎞⎛−10<br />
⎞<br />
r f R(r) = F′ R(r)<br />
= d/dr ⎜1− FT ⎜ ⎟ =−⎜<br />
FT () t ⎟⎜ 2<br />
r<br />
⎟<br />
⎟⎠<br />
⎝ ⎝ ⎠⎠ ⎝dt ⎠⎝ r<br />
d 1<br />
FT() t = fT() t = since T is uniformly distributed on [8, 12] .<br />
dt<br />
4<br />
−1⎛−10⎞ 5<br />
Therefore f R(r)<br />
= ⎜ = 2 ⎟ . 2<br />
4 ⎝ r ⎠ 2r<br />
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75. Solution: A<br />
Let X and Y be the monthly profits of Company I and Company II, respectively. We are<br />
given that the pdf of X is f . Let us also take g to be the pdf of Y and take F and G to be<br />
the distribution functions corresponding to f and g . Then G(y) = Pr[Y ≤ y] = P[2X ≤ y]<br />
= P[X ≤ y/2] = F(y/2) and g(y) = G′(y) = d/dy F(y/2) = ½ F′(y/2) = ½ f(y/2) .<br />
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76. Solution: A<br />
First, observe that the distribution function of X is given by<br />
x 3 1 x 1<br />
F ( x) = ∫ dt =− | 4 3 1 = 1 − , x><br />
1<br />
1<br />
3<br />
t t x<br />
Next, let X1, X 2, and X3<br />
denote the three claims made that have this distribution. Then if<br />
Y denotes the largest of these three claims, it follows that the distribution function of Y is<br />
given by<br />
G y = Pr X ≤ y Pr X ≤ y Pr X ≤ y<br />
( ) [ ] [ ] [ ]<br />
1 2 3<br />
⎛ 1 ⎞<br />
= ⎜1 − , y 1<br />
3 ⎟ ><br />
⎝ y ⎠<br />
while the density function of Y is given by<br />
3<br />
2 2<br />
⎛ 1 ⎞ ⎛ 3 ⎞ ⎛ 9 ⎞⎛ 1 ⎞<br />
g( y) = G'( y) = 3⎜1− 1 , y 1<br />
3 ⎟ ⎜ 4 ⎟= ⎜ − 4 ⎟⎜ 3 ⎟ ><br />
⎝ y ⎠ ⎝ y ⎠ ⎝ y ⎠⎝ y ⎠<br />
Therefore,<br />
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