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EXAM P SAMPLE SOLUTIONS

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120. Solution: A<br />

We are given that X denotes loss. In addition, denote the time required to process a claim<br />

by T.<br />

⎧3<br />

2 1 3<br />

⎪ x ⋅ = x, x< t < 2 x,0≤ x≤<br />

2<br />

Then the joint pdf of X and T is f( x, t) = ⎨8 x 8<br />

⎪⎩ 0, otherwise.<br />

Now we can find P[T ≥ 3] =<br />

4 2 4 2<br />

3 ⎡ 3 2⎤ ∫∫ xdxdt =<br />

8 ∫⎢ x<br />

16 3 t /2 3⎣ ⎥<br />

⎦t/2 = 11/64 = 0.17 .<br />

4<br />

4<br />

⎛12 3 2⎞ ⎡1213⎤ dt = ∫⎜<br />

− t ⎟dt= − t<br />

16 64 16 64 3⎝<br />

⎠ ⎣<br />

⎢<br />

⎦<br />

⎥<br />

3<br />

12 ⎛36<br />

27 ⎞<br />

= −1−⎜ − ⎟<br />

4 ⎝16<br />

64 ⎠<br />

t t=2x<br />

4<br />

3<br />

2<br />

1<br />

1 2<br />

t=x<br />

x<br />

--------------------------------------------------------------------------------------------------------<br />

121. Solution: C<br />

The marginal density of X is given by<br />

1<br />

3<br />

1 1 1<br />

1<br />

2 ⎛ xy ⎞ ⎛ x⎞<br />

fx( x) = ∫ ( 10 − xy ) dy = ⎜10y− ⎟ = 10<br />

0<br />

⎜ − ⎟<br />

64 64 ⎝ 3 ⎠ 64 ⎝ 3 ⎠<br />

Then<br />

2<br />

10 10 1 ⎛ x ⎞<br />

∫2 x ∫ ⎜ ⎟ x<br />

2<br />

E( X) = xf ( x) dx= 10x−<br />

d<br />

64 ⎝ 3 ⎠<br />

= 1 1000 8<br />

⎡⎛ ⎞ ⎛ ⎞⎤<br />

500 20<br />

64<br />

⎢⎜ − ⎟−⎜ − ⎟<br />

9 9<br />

⎥ = 5.778<br />

⎣⎝ ⎠ ⎝ ⎠ ⎦<br />

0<br />

Page 53 of 55<br />

10<br />

3<br />

⎛ 2 x ⎞<br />

1<br />

= ⎜5x−⎟ 64 ⎝ 9 ⎠<br />

2

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