EXAM P SAMPLE SOLUTIONS
EXAM P SAMPLE SOLUTIONS
EXAM P SAMPLE SOLUTIONS
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120. Solution: A<br />
We are given that X denotes loss. In addition, denote the time required to process a claim<br />
by T.<br />
⎧3<br />
2 1 3<br />
⎪ x ⋅ = x, x< t < 2 x,0≤ x≤<br />
2<br />
Then the joint pdf of X and T is f( x, t) = ⎨8 x 8<br />
⎪⎩ 0, otherwise.<br />
Now we can find P[T ≥ 3] =<br />
4 2 4 2<br />
3 ⎡ 3 2⎤ ∫∫ xdxdt =<br />
8 ∫⎢ x<br />
16 3 t /2 3⎣ ⎥<br />
⎦t/2 = 11/64 = 0.17 .<br />
4<br />
4<br />
⎛12 3 2⎞ ⎡1213⎤ dt = ∫⎜<br />
− t ⎟dt= − t<br />
16 64 16 64 3⎝<br />
⎠ ⎣<br />
⎢<br />
⎦<br />
⎥<br />
3<br />
12 ⎛36<br />
27 ⎞<br />
= −1−⎜ − ⎟<br />
4 ⎝16<br />
64 ⎠<br />
t t=2x<br />
4<br />
3<br />
2<br />
1<br />
1 2<br />
t=x<br />
x<br />
--------------------------------------------------------------------------------------------------------<br />
121. Solution: C<br />
The marginal density of X is given by<br />
1<br />
3<br />
1 1 1<br />
1<br />
2 ⎛ xy ⎞ ⎛ x⎞<br />
fx( x) = ∫ ( 10 − xy ) dy = ⎜10y− ⎟ = 10<br />
0<br />
⎜ − ⎟<br />
64 64 ⎝ 3 ⎠ 64 ⎝ 3 ⎠<br />
Then<br />
2<br />
10 10 1 ⎛ x ⎞<br />
∫2 x ∫ ⎜ ⎟ x<br />
2<br />
E( X) = xf ( x) dx= 10x−<br />
d<br />
64 ⎝ 3 ⎠<br />
= 1 1000 8<br />
⎡⎛ ⎞ ⎛ ⎞⎤<br />
500 20<br />
64<br />
⎢⎜ − ⎟−⎜ − ⎟<br />
9 9<br />
⎥ = 5.778<br />
⎣⎝ ⎠ ⎝ ⎠ ⎦<br />
0<br />
Page 53 of 55<br />
10<br />
3<br />
⎛ 2 x ⎞<br />
1<br />
= ⎜5x−⎟ 64 ⎝ 9 ⎠<br />
2