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Pulsed-field gradient nuclear magnetic resonance as a tool for ...

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326<br />

PRICE<br />

D will affect the me<strong>as</strong>ured echo attenuation<br />

Ž 114, 116 . .<br />

The situation with anisotropic restricted diffusion<br />

is more complicated, and we will illustrate<br />

this with reference to diffusion in a cylinder with<br />

an arbitrary Ž polar. angle, , between the symme-<br />

try axis of the cylinder and the static <strong>magnetic</strong><br />

<strong>field</strong> Ž which is also the direction of the <strong>gradient</strong>.<br />

Ž Fig. 9 . . Such a cylinder can be thought of, <strong>for</strong><br />

example, <strong>as</strong> a simplistic model of a muscle-fiber<br />

cell. The SGP solution <strong>for</strong> this geometry is given<br />

by Ž 117 .<br />

2 4 2 n<br />

2<br />

nm km<br />

2K R Ž 2qR. sin Ž 2. 1 Ž 1. cosŽ 2 qL cos . <br />

EŽ q,. Ý Ý Ý 2 2 2 2 2<br />

L nRL 2qR cos 2qR sin m<br />

n0 k1 m0<br />

2 Ž . Ž . 2 2 Ž . 2 Ž 2 2.<br />

km km<br />

2 n 2<br />

<br />

2<br />

km<br />

m ½ ž R / ž L / 5<br />

J Ž 2qR sin . exp D 110 where L is the length of the cylinder, R is the<br />

radius of the cylinder, and km is the kth nonzero<br />

<br />

root of the equation J Ž . m km 0, where J is the<br />

Bessel function of the first kind, and the constant<br />

K nm depends on the values of the indexes n and<br />

m according to<br />

K nm 1 if nm0<br />

Knm 1 if nm0orm0and n 0<br />

Knm 1 if n, m0. 111 Now, the mathematical complexity is no concern<br />

to us here and the point that we wish to emph<strong>as</strong>ize<br />

is the dependence; thus, in contradistinction<br />

to the c<strong>as</strong>es of free diffusion and diffusion<br />

with a sphere, in an anisotropic system the spinecho<br />

attenuation is now a function of the direction<br />

of the <strong>gradient</strong>. In fact, if we had a less<br />

symmetric geometry Ž e.g., an elliptic cylinder . ,<br />

then the equation <strong>for</strong> Eq, Ž . should also be<br />

dependent on the azimuthal angle, . If we set<br />

0, then the solution given by Eq. 110 reduces,<br />

<strong>as</strong> expected, to the solution <strong>for</strong> diffusion<br />

between planes Ži.e., Eq. 92 and noting that<br />

L2R . . Similarly, if 2, Eq. 110 reduces<br />

to the solution <strong>for</strong> diffusion in a cylinder Ž 110 . ,<br />

EŽ q,.<br />

<br />

2<br />

22qR Ž . Ý Ý<br />

k1 m0<br />

2 <br />

2 2<br />

K J Ž 2qR. exp Ž R. 0m km m km D4<br />

2 2<br />

2 2 2<br />

km km<br />

Ž 2qR. Ž m .<br />

.<br />

<br />

112<br />

The echo-attenuation curves <strong>for</strong> diffusion in a<br />

cylinder versus are plotted <strong>for</strong> three different<br />

values of in Fig. 10. The long time limiting<br />

<strong>for</strong>mula <strong>for</strong> the cylinder is given by Ž 117 .<br />

Ž .<br />

E q,<br />

2 8R 1cosŽ 2 qL cos .J Ž 2 qR sin .<br />

1<br />

.<br />

4 2<br />

2<br />

Ž 2qR. L Ž cos sin .<br />

113 When 0, this, of course, reduces to the long<br />

time <strong>for</strong> diffusion between planes <strong>as</strong> given in Eq.<br />

93 Ž n.b. L 2 R . , and when 2, this reduces<br />

to Ž 117 .<br />

2J Ž 2qR.<br />

1<br />

EŽ q,. . 114 2<br />

Ž 2qR.<br />

The echo-attenuation curves <strong>for</strong> diffusion in a<br />

cylinder versus qR are plotted <strong>for</strong> three different<br />

values of in Fig. 11.<br />

Clearly, the dependence on the attenuation<br />

curves and the diffraction patternsor alternately,<br />

we can think of this <strong>as</strong> the orientation of<br />

D with respect to the <strong>gradient</strong>provides an additional<br />

structural probe. If the restricted diffusion<br />

effects are not accounted <strong>for</strong> and free diffusion is<br />

<strong>as</strong>sumed, and Eq. 104 ,<br />

which is valid only <strong>for</strong><br />

free diffusion, is used to analyze the attenuation<br />

data, then D is really an apparent diffusion ten-<br />

2<br />

2

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