x - MathnMind
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x - MathnMind
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Your Notes<br />
Example 2 Solve a linear-quadratic system by substitution<br />
Solve the system using substitution.<br />
x2 1 y2 5 13 Equation 1<br />
y 5 x 1 5 Equation 2<br />
Solution<br />
Substitute x 1 5 for y in Equation 1 and solve for x.<br />
x2 1 y2 5 13 Equation 1<br />
x2 1 ( ) 2 5 13 Substitute for y.<br />
x2 1 5 13 Expand the power.<br />
5 0 Combine like terms.<br />
5 0 Divide each side by .<br />
5 0 Factor.<br />
x 5 or x 5 Zero product property<br />
The corresponding y-values are y 5 5 and<br />
y 5 5 . The solutions are ( , ) and<br />
( , ).<br />
Checkpoint Solve the system using substitution.<br />
2. y 2 1 6x 2 3 5 0<br />
y 5 2x 2 1<br />
254 Lesson 9.7 Algebra 2 Notetaking Guide Copyright © Holt McDougal. All rights reserved.
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