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Your Notes<br />

Example 3 Solve a quadratic system by elimination<br />

Solve the system by elimination.<br />

5x2 1 y2 1 48x 1 99 5 0 Equation 1<br />

x2 2 y2 2 9 5 0 Equation 2<br />

Solution<br />

Add the equations to eliminate the y2-term and obtain a<br />

quadratic equation in x.<br />

5x2 1 y2 1 48x 1 99 5 0<br />

x 2 2 y 2 2 9 5 0<br />

5 Add.<br />

5 Divide each side by .<br />

5 Factor.<br />

x 5 or x 5 Zero product property<br />

When x 5 , y 5 . When x 5 , y 5 .<br />

The solutions are , , and .<br />

Checkpoint Solve the system by elimination.<br />

3. 2x 2 1 2y 2 2 26 5 0<br />

2x 2 1 y 1 7 5 0<br />

Copyright © Holt McDougal. All rights reserved. Lesson 9.7 Algebra 2 Notetaking Guide 255

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