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STAT170 Workshop Notes prepared by Nan Carter for Numeracy ...

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QUESTION 1: The Chapin Social Insight Test is a psychological test designed<br />

to measure how accurately the subject appraises other people. The possible<br />

scores on the test range from 0 to 41. During the development of the Chapin<br />

Test, it was given to several groups of people. Here are the results <strong>for</strong> male and<br />

female students majoring in the liberal arts:<br />

Group Sex N X-bar S.D.<br />

1 Male 133 25.34 5.05<br />

2 Female 162 24.94 5.44<br />

Do these data support the contention that female and male students differ in<br />

average social insight?<br />

The variable is a score on a psychological test. It is reasonable to assume the<br />

variable, score, is normally distributed.<br />

Do these data support the contention that female and male students differ in<br />

average score?<br />

CHECKS: sp = 5.2679; SE(y1bar – y2bar) = 0.6164; t = 0.649; df = 293; pvalue<br />

> 0.05; no.<br />

METHOD Two independent random samples: do the samples come from<br />

populations with the same mean?<br />

Population 1 male 2 female<br />

Mean μ1 μ2<br />

Standard deviation σ1 σ2<br />

Sample size n1 133 n 2 162<br />

Sample mean y1bar 25.34 y2bar 24.94<br />

Sample SD s1 5.05 s 2 5.44<br />

Null hypothesis H0: μ1 = μ2<br />

Assumptions:<br />

• the populations are both normal<br />

• the standard deviations are equal, or in symbols: σ1 = σ 2;<br />

• to check this second assumption use:<br />

smax / s min < about 2.<br />

The value of the t-statistic is given <strong>by</strong><br />

y1bar – y2bar<br />

t = __________________ where<br />

SE(y1bar – y2bar)<br />

SE(y1bar – y2bar) = sp √( 1/n1 + 1/n2) and<br />

22<br />

<strong>Nan</strong> <strong>Carter</strong>: workshop notes <strong>prepared</strong> <strong>for</strong> <strong>Numeracy</strong> Centre Macquarie University.

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