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Unit 5 & 6 Test Review<br />
Heat of Fusion<br />
q = m ∙ΔH f<br />
Specific Heat<br />
c = ____q____<br />
m ∙ ΔT ᵒC<br />
Heat of Fusion of Water<br />
334 J/g = 80 cal/g<br />
Specific Heat of Water<br />
4.18 J/g ∙ᵒC<br />
Heat of fusion is the amount of heat energy required to change the state of a substance from solid to<br />
liquid. This example problem demonstrates how to calculate the amount of energy required to melt a<br />
sample of water ice.<br />
With Graham's Law, you can find the effusion rates for two gases or the molecular mass of a gas.<br />
This ratio of effusion rates follows the pattern that the gas with the lesser molecular mass has a<br />
greater rate of effusion.<br />
Ideal Gas Law<br />
Combined Gas Law<br />
p∙v=n∙R∙T V 1 ∙P 1 = V 2 ∙P 2<br />
T 1 T 2<br />
R = .082 atm or 8.31kpa<br />
Boyle’s Law<br />
P 1 ∙V 1 = P 2 ∙V 2<br />
Charles’ Law<br />
Gay – Lussac’s Law<br />
V 1 = V 2 P 1 = P 2<br />
T 1 T 2 T 1 T 2<br />
Molarity<br />
M = moles<br />
L<br />
Gas Solubility<br />
S 1 = S 2<br />
P 1 P 2
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