Constructing soluble quantum spin models - Department of Physics ...
Constructing soluble quantum spin models - Department of Physics ...
Constructing soluble quantum spin models - Department of Physics ...
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H.Y. Shik et al. / Nuclear <strong>Physics</strong> B 666 [FS] (2003) 337–360 357<br />
|00〉=√<br />
2<br />
3 |p 0〉− 1 √<br />
3<br />
|s〉,<br />
|0↓〉 = 1 √<br />
2<br />
(<br />
|p−1 〉−|t −1 〉 ) ,<br />
|↓↑〉 = 1 √<br />
6<br />
|p 0 〉+ 1 √<br />
2<br />
|t 0 〉+ 1 √<br />
3<br />
|s〉,<br />
|↓0〉= 1 √<br />
2<br />
(<br />
|p−1 〉+|t −1 〉 ) ,<br />
|↓↓〉 = |p −2 〉.<br />
(A.7)<br />
(A.8)<br />
(A.9)<br />
(A.10)<br />
(A.11)<br />
Introducing the matrix representations <strong>of</strong> Spin-1 operators<br />
S z =<br />
[ ]<br />
1 0 0<br />
0 0 0 , S + = √ 2<br />
0 0 −1<br />
[ ] 0 1 0<br />
0 0 1 , S − = √ 2<br />
0 0 0<br />
[ 0 0<br />
] 0<br />
1 0 0 ,<br />
0 1 0<br />
the bond operator representations <strong>of</strong> the original <strong>spin</strong> operator S z and S + are given by<br />
S z = ẽ T · (S z ⊗ I ) · ẽ = e T · M T · (S z ⊗ I ) · M · e<br />
= p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† 1 t 1 − 1 √<br />
3<br />
p † 0 t 0 − 1 2 p† −1 p −1 − 1 2 p† −1 t −1 − p † −2 p −2<br />
(A.12)<br />
− 1 2 t† 1 p 1 + 1 2 t† 1 t 1 − 1 √<br />
3<br />
t † 0 p 0 − 1 2 t† −1 p −1 − 1 2 t† −1 t −1 −<br />
where I is an 3 × 3 identity matrix, and<br />
S + = ẽ T · (S + ⊗ I ) · ẽ<br />
√<br />
2 ( t<br />
†<br />
3<br />
0 s + ) s† t 0 ,<br />
(A.13)<br />
= p † 2 p 1 + p † 2 t 1 +<br />
√<br />
3<br />
2 p† 1 p 0 + 1 √<br />
2<br />
p † 1 t 0 +<br />
√<br />
3<br />
2 p† 0 p −1 + 1 √<br />
6<br />
p † 0 t −1 + p † −1 p −2<br />
− 1 √<br />
6<br />
t † 1 p 0 + 1 √<br />
2<br />
t † 1 t 0 − 1 √<br />
2<br />
t † 0 p −1 + 1 √<br />
2<br />
t † 0 t −1 − t † −1 p −2<br />
+ 2 √<br />
3<br />
( t<br />
†<br />
1 s − s† t −1<br />
) .<br />
(A.14)<br />
Similarly,<br />
S ′ z = ẽ T · (I<br />
⊗ S z) · ẽ = e T · M T · (I<br />
⊗ S z) · M · e<br />
= p † 2 p 2 + 1 2 p† 1 p 1 + 1 2 p† 1 t 1 + 1 √<br />
3<br />
p † 0 t 0 − 1 2 p† −1 p −1 + 1 2 p† −1 t −1 − p † −2 p −2<br />
+ 1 2 t† 1 p 1 + 1 2 t† 1 t 1 + √ 1 t † 0 p 0 + 1<br />
3 2 t† −1 p −1 − 1 √<br />
2<br />
2 t† −1 t (<br />
−1 + t<br />
†<br />
0<br />
3<br />
s + ) s† t 0 ,<br />
(A.15)