22.05.2014 Views

Constructing soluble quantum spin models - Department of Physics ...

Constructing soluble quantum spin models - Department of Physics ...

Constructing soluble quantum spin models - Department of Physics ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

H.Y. Shik et al. / Nuclear <strong>Physics</strong> B 666 [FS] (2003) 337–360 357<br />

|00〉=√<br />

2<br />

3 |p 0〉− 1 √<br />

3<br />

|s〉,<br />

|0↓〉 = 1 √<br />

2<br />

(<br />

|p−1 〉−|t −1 〉 ) ,<br />

|↓↑〉 = 1 √<br />

6<br />

|p 0 〉+ 1 √<br />

2<br />

|t 0 〉+ 1 √<br />

3<br />

|s〉,<br />

|↓0〉= 1 √<br />

2<br />

(<br />

|p−1 〉+|t −1 〉 ) ,<br />

|↓↓〉 = |p −2 〉.<br />

(A.7)<br />

(A.8)<br />

(A.9)<br />

(A.10)<br />

(A.11)<br />

Introducing the matrix representations <strong>of</strong> Spin-1 operators<br />

S z =<br />

[ ]<br />

1 0 0<br />

0 0 0 , S + = √ 2<br />

0 0 −1<br />

[ ] 0 1 0<br />

0 0 1 , S − = √ 2<br />

0 0 0<br />

[ 0 0<br />

] 0<br />

1 0 0 ,<br />

0 1 0<br />

the bond operator representations <strong>of</strong> the original <strong>spin</strong> operator S z and S + are given by<br />

S z = ẽ T · (S z ⊗ I ) · ẽ = e T · M T · (S z ⊗ I ) · M · e<br />

= p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† 1 t 1 − 1 √<br />

3<br />

p † 0 t 0 − 1 2 p† −1 p −1 − 1 2 p† −1 t −1 − p † −2 p −2<br />

(A.12)<br />

− 1 2 t† 1 p 1 + 1 2 t† 1 t 1 − 1 √<br />

3<br />

t † 0 p 0 − 1 2 t† −1 p −1 − 1 2 t† −1 t −1 −<br />

where I is an 3 × 3 identity matrix, and<br />

S + = ẽ T · (S + ⊗ I ) · ẽ<br />

√<br />

2 ( t<br />

†<br />

3<br />

0 s + ) s† t 0 ,<br />

(A.13)<br />

= p † 2 p 1 + p † 2 t 1 +<br />

√<br />

3<br />

2 p† 1 p 0 + 1 √<br />

2<br />

p † 1 t 0 +<br />

√<br />

3<br />

2 p† 0 p −1 + 1 √<br />

6<br />

p † 0 t −1 + p † −1 p −2<br />

− 1 √<br />

6<br />

t † 1 p 0 + 1 √<br />

2<br />

t † 1 t 0 − 1 √<br />

2<br />

t † 0 p −1 + 1 √<br />

2<br />

t † 0 t −1 − t † −1 p −2<br />

+ 2 √<br />

3<br />

( t<br />

†<br />

1 s − s† t −1<br />

) .<br />

(A.14)<br />

Similarly,<br />

S ′ z = ẽ T · (I<br />

⊗ S z) · ẽ = e T · M T · (I<br />

⊗ S z) · M · e<br />

= p † 2 p 2 + 1 2 p† 1 p 1 + 1 2 p† 1 t 1 + 1 √<br />

3<br />

p † 0 t 0 − 1 2 p† −1 p −1 + 1 2 p† −1 t −1 − p † −2 p −2<br />

+ 1 2 t† 1 p 1 + 1 2 t† 1 t 1 + √ 1 t † 0 p 0 + 1<br />

3 2 t† −1 p −1 − 1 √<br />

2<br />

2 t† −1 t (<br />

−1 + t<br />

†<br />

0<br />

3<br />

s + ) s† t 0 ,<br />

(A.15)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!