Constructing soluble quantum spin models - Department of Physics ...
Constructing soluble quantum spin models - Department of Physics ...
Constructing soluble quantum spin models - Department of Physics ...
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
H.Y. Shik et al. / Nuclear <strong>Physics</strong> B 666 [FS] (2003) 337–360 341<br />
The triplets |t α 〉 with α =±1and0beingthez-component <strong>of</strong> the total <strong>spin</strong> are defined<br />
as<br />
|t 1 〉≡t † 1 |vac〉= 1<br />
(16)<br />
√<br />
2<br />
(<br />
|0↑〉 − |↑0〉<br />
)<br />
,<br />
(17)<br />
|t 0 〉≡t † 0 |vac〉= 1 √<br />
2<br />
(<br />
|↓↑〉 − |↑↓〉<br />
)<br />
,<br />
(18)<br />
|t −1 〉≡t † −1 |vac〉= 1 √<br />
2<br />
(<br />
|↓0〉−|0↓〉<br />
)<br />
.<br />
The fivefold multiplets pentad |p β 〉 with β =±2, ±1, and 0 are defined as<br />
|p 2 〉≡p † 2 |vac〉 = |↑↑〉, (19)<br />
(20)<br />
|p 1 〉≡p † 1 |vac〉= 1 √<br />
2<br />
( |0↑〉 + |↑0〉<br />
) ,<br />
(21)<br />
|p 0 〉≡p † 0 |vac〉= 1 √<br />
6<br />
(<br />
|↑↓〉 + 2|00〉 + |↓↑〉<br />
)<br />
,<br />
(22)<br />
Conversely,<br />
|p −1 〉≡p † −1 |vac〉= 1 √<br />
2<br />
(<br />
|0↓〉 + |↓0〉<br />
)<br />
,<br />
(23)<br />
|p −2 〉≡p † −2 |vac〉=|↓↓〉.<br />
S z<br />
= p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† −1 p −1 − p † −2 p −2 + 1 2 t† 1 t 1 − 1 2 t† −1 t −1<br />
− 1 2<br />
(<br />
p<br />
†<br />
1 t 1 + t † 1 p ) 1 (<br />
1 − √3 p<br />
†<br />
0 t 0 + t † 0 p 0<br />
) 1( − p<br />
†<br />
−1<br />
2<br />
t −1 + t † −1 p )<br />
−1<br />
−<br />
√<br />
2 (<br />
t<br />
†<br />
0<br />
3<br />
s + ) s† t 0 ,<br />
S ′ z = p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† −1 p −1 − p † −2 p −2 + 1 2 t† 1 t 1 − 1 2 t† −1 t −1<br />
+ 1 2<br />
+<br />
(<br />
p<br />
†<br />
1 t 1 + t † 1 p ) 1 (<br />
1 + √3 p<br />
†<br />
0 t 0 + t † 0 p 0<br />
√<br />
2 (<br />
t<br />
†<br />
3<br />
0 s + s† t 0<br />
)<br />
,<br />
S + = p † 2 p 1 + p † −1 p −2 +<br />
) 1( + p<br />
†<br />
2<br />
−1 t −1 + t † −1 p )<br />
−1<br />
√<br />
3 (<br />
p<br />
†<br />
1<br />
2<br />
p 0 + p † 0 p ) 1 (<br />
−1 + √2 t<br />
†<br />
1 t 0 + t † 0 t )<br />
−1<br />
+ p † 2 t 1 − t † −1 p −2 + √ 1 (<br />
p<br />
†<br />
1 t 0 − t † 0 p ) 1 (<br />
−1 + √6 p<br />
†<br />
0 t −1 − t † 1 p )<br />
0<br />
2<br />
+ 2 √<br />
3<br />
( t<br />
†<br />
1 s − s† t −1<br />
) ,