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Constructing soluble quantum spin models - Department of Physics ...

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H.Y. Shik et al. / Nuclear <strong>Physics</strong> B 666 [FS] (2003) 337–360 341<br />

The triplets |t α 〉 with α =±1and0beingthez-component <strong>of</strong> the total <strong>spin</strong> are defined<br />

as<br />

|t 1 〉≡t † 1 |vac〉= 1<br />

(16)<br />

√<br />

2<br />

(<br />

|0↑〉 − |↑0〉<br />

)<br />

,<br />

(17)<br />

|t 0 〉≡t † 0 |vac〉= 1 √<br />

2<br />

(<br />

|↓↑〉 − |↑↓〉<br />

)<br />

,<br />

(18)<br />

|t −1 〉≡t † −1 |vac〉= 1 √<br />

2<br />

(<br />

|↓0〉−|0↓〉<br />

)<br />

.<br />

The fivefold multiplets pentad |p β 〉 with β =±2, ±1, and 0 are defined as<br />

|p 2 〉≡p † 2 |vac〉 = |↑↑〉, (19)<br />

(20)<br />

|p 1 〉≡p † 1 |vac〉= 1 √<br />

2<br />

( |0↑〉 + |↑0〉<br />

) ,<br />

(21)<br />

|p 0 〉≡p † 0 |vac〉= 1 √<br />

6<br />

(<br />

|↑↓〉 + 2|00〉 + |↓↑〉<br />

)<br />

,<br />

(22)<br />

Conversely,<br />

|p −1 〉≡p † −1 |vac〉= 1 √<br />

2<br />

(<br />

|0↓〉 + |↓0〉<br />

)<br />

,<br />

(23)<br />

|p −2 〉≡p † −2 |vac〉=|↓↓〉.<br />

S z<br />

= p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† −1 p −1 − p † −2 p −2 + 1 2 t† 1 t 1 − 1 2 t† −1 t −1<br />

− 1 2<br />

(<br />

p<br />

†<br />

1 t 1 + t † 1 p ) 1 (<br />

1 − √3 p<br />

†<br />

0 t 0 + t † 0 p 0<br />

) 1( − p<br />

†<br />

−1<br />

2<br />

t −1 + t † −1 p )<br />

−1<br />

−<br />

√<br />

2 (<br />

t<br />

†<br />

0<br />

3<br />

s + ) s† t 0 ,<br />

S ′ z = p † 2 p 2 + 1 2 p† 1 p 1 − 1 2 p† −1 p −1 − p † −2 p −2 + 1 2 t† 1 t 1 − 1 2 t† −1 t −1<br />

+ 1 2<br />

+<br />

(<br />

p<br />

†<br />

1 t 1 + t † 1 p ) 1 (<br />

1 + √3 p<br />

†<br />

0 t 0 + t † 0 p 0<br />

√<br />

2 (<br />

t<br />

†<br />

3<br />

0 s + s† t 0<br />

)<br />

,<br />

S + = p † 2 p 1 + p † −1 p −2 +<br />

) 1( + p<br />

†<br />

2<br />

−1 t −1 + t † −1 p )<br />

−1<br />

√<br />

3 (<br />

p<br />

†<br />

1<br />

2<br />

p 0 + p † 0 p ) 1 (<br />

−1 + √2 t<br />

†<br />

1 t 0 + t † 0 t )<br />

−1<br />

+ p † 2 t 1 − t † −1 p −2 + √ 1 (<br />

p<br />

†<br />

1 t 0 − t † 0 p ) 1 (<br />

−1 + √6 p<br />

†<br />

0 t −1 − t † 1 p )<br />

0<br />

2<br />

+ 2 √<br />

3<br />

( t<br />

†<br />

1 s − s† t −1<br />

) ,

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