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CHAPTER 2. SPECIAL RELATIVITY 14<br />

ct ′<br />

✲<br />

vt ′<br />

✲✛<br />

l<br />

✲<br />

v(t − t ′ ) c(t − t ′ )<br />

✲✛<br />

Figure 2.6: Length Contraction.<br />

total time <strong>of</strong> flight. Eliminate t ′ , we have<br />

2l = (1 − v 2 /c 2 )ct . (2.16)<br />

The times <strong>of</strong> flight in the two reference frames, t 0 and t, are related by<br />

Eq. (2.14). Finally, we have<br />

l = (1 − v 2 /c 2 ) ct/2 =<br />

√<br />

√<br />

1 − v 2 /c 2 ct 0 /2 = 1 − v 2 /c 2 l 0 . (2.17)<br />

Notice that the transverse direction will not be contracted. T<strong>here</strong>fore,<br />

the shape <strong>of</strong> a fast moving object will be distorted.<br />

Now, we will give an example that shows the various concepts in this<br />

chapter. When some cosmic particles enter our atmosp<strong>here</strong> and collide with<br />

the molecules, many other unstable particles will be created. Let us assume<br />

the lifetime <strong>of</strong> such an unstable particle be T, also assume for simplicity the<br />

thickness <strong>of</strong> the atmosp<strong>here</strong> be L. What will be their minimum speed if we<br />

detect those particles on the Earth surface?<br />

T<strong>here</strong> are two equivalent ways to solve this problem. Let the minimum<br />

speed <strong>of</strong> the particle be v. From the point <strong>of</strong> view <strong>of</strong> the particle, due to<br />

length contraction, the thickness <strong>of</strong> the atmosp<strong>here</strong> is shorten to<br />

√<br />

L 1 − v 2 /c 2 . (2.18)<br />

In order to reach the Earth surface, vT must be equal to or larger than this<br />

length. Hence, we have<br />

√<br />

vT = L 1 − v 2 /c 2<br />

c<br />

v = √1 + (cT/L) . (2.19)<br />

2

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