here - Department of Physics, HKU
here - Department of Physics, HKU
here - Department of Physics, HKU
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CHAPTER 2. SPECIAL RELATIVITY 14<br />
ct ′<br />
✲<br />
vt ′<br />
✲✛<br />
l<br />
✲<br />
v(t − t ′ ) c(t − t ′ )<br />
✲✛<br />
Figure 2.6: Length Contraction.<br />
total time <strong>of</strong> flight. Eliminate t ′ , we have<br />
2l = (1 − v 2 /c 2 )ct . (2.16)<br />
The times <strong>of</strong> flight in the two reference frames, t 0 and t, are related by<br />
Eq. (2.14). Finally, we have<br />
l = (1 − v 2 /c 2 ) ct/2 =<br />
√<br />
√<br />
1 − v 2 /c 2 ct 0 /2 = 1 − v 2 /c 2 l 0 . (2.17)<br />
Notice that the transverse direction will not be contracted. T<strong>here</strong>fore,<br />
the shape <strong>of</strong> a fast moving object will be distorted.<br />
Now, we will give an example that shows the various concepts in this<br />
chapter. When some cosmic particles enter our atmosp<strong>here</strong> and collide with<br />
the molecules, many other unstable particles will be created. Let us assume<br />
the lifetime <strong>of</strong> such an unstable particle be T, also assume for simplicity the<br />
thickness <strong>of</strong> the atmosp<strong>here</strong> be L. What will be their minimum speed if we<br />
detect those particles on the Earth surface?<br />
T<strong>here</strong> are two equivalent ways to solve this problem. Let the minimum<br />
speed <strong>of</strong> the particle be v. From the point <strong>of</strong> view <strong>of</strong> the particle, due to<br />
length contraction, the thickness <strong>of</strong> the atmosp<strong>here</strong> is shorten to<br />
√<br />
L 1 − v 2 /c 2 . (2.18)<br />
In order to reach the Earth surface, vT must be equal to or larger than this<br />
length. Hence, we have<br />
√<br />
vT = L 1 − v 2 /c 2<br />
c<br />
v = √1 + (cT/L) . (2.19)<br />
2