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CHAPTER 4. RELATIVISTIC KINEMATICS 29<br />

Their relative speed in their frame is given by<br />

Hence, the observed frequency is<br />

v 1 + v 2<br />

1 + v 1 v 2 /c 2 . (4.8)<br />

⎛<br />

f 1<br />

⎝ 1 + (v ⎞<br />

1+v 2 )/c 1/2<br />

1+v 1 v 2 /c 2<br />

⎠<br />

1 − (v 1+v 2 )/c<br />

1+v 1 v 2 /c 2<br />

= f 1<br />

( 1 + v1 /c + v 2 /c + v 1 v 2 /c 2<br />

1 − v 1 /c − v 2 /c + v 1 v 2 /c 2 ) 1/2<br />

= f 1<br />

( (1 + v1 /c)(1 + v 2 /c)<br />

(1 − v 1 /c)(1 − v 2 /c)<br />

) 1/2<br />

. (4.9)<br />

Another way to explain this formula is that, in the frame <strong>of</strong> the other spaceship,<br />

the observed frequency is just the Doppler shifted frequency <strong>of</strong> the one<br />

in Eq. (4.7) <strong>of</strong> speed v 2 , and this is exactly given by the above formula.<br />

T<strong>here</strong> are many applications <strong>of</strong> the Doppler effect. For example, police<br />

uses radar to monitor speed <strong>of</strong> vehicles by emitting radio wave <strong>of</strong> known<br />

frequency and detect the frequency <strong>of</strong> the reflected wave. The two are related<br />

by the Doppler effect. Also, astronomers detect the speeds <strong>of</strong> galaxies by<br />

measuring the shift <strong>of</strong> the spectrum <strong>of</strong> light emitted.<br />

4.2 Conservation <strong>of</strong> Energy and Momentum<br />

We are going to prove that energy and momentum are conserved in any frame<br />

if they are in one frame. Let the two frames, one moving one stationary, be<br />

related as in Eq. (3.15) to Eq. (3.18), as usual, and let the velocity <strong>of</strong> a particle<br />

be u and u ′ relative to the stationary and moving frames as in Eq. (3.29) to<br />

Eq. (3.33). We first prove an useful relation<br />

1 − u2<br />

= 1 c 2 ( c2<br />

=<br />

=<br />

c 2 − (u′ x + v)2<br />

(1 + vu ′ x /c2 ) 2<br />

u ′ 2<br />

y<br />

u ′ 2<br />

z<br />

−<br />

(1 + vu ′ x /c2 ) (1 − 2 v2 /c 2 ) −<br />

(1 + vu ′ x /c2 ) (1 − 2 v2 /c 2 ) ⎠<br />

1 (<br />

c 2 (1 + vu ′<br />

c 2 (1 + vu ′ x/c 2 ) 2 x /c2 ) 2 − (u ′ x + v)2<br />

−u ′ y2 (1 − v 2 /c 2 ) − u ′ 2 z (1 − v 2 /c 2 ) )<br />

1 (<br />

c 2 + 2vu ′<br />

c 2 (1 + vu ′ x /c2 ) 2 x + v2 u ′ 2 x /c 2 − u ′ x2 − 2u ′ x v − v2<br />

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