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Radiation pressure P rad<br />
F<br />
1<br />
P = = ⋅a<br />
⋅T<br />
4<br />
rad<br />
F: force A<br />
3<br />
A: Area<br />
a: radiation constant: a=7.566·10 -16 J m -3 K -4<br />
T: temperature in K …. For T≈10 7 K<br />
( )<br />
J<br />
P 1 −16<br />
7 4<br />
11 ⎡<br />
−<br />
Pa bar<br />
rad<br />
7.566 10 10 2.52 10<br />
10<br />
5 ⎤<br />
= ⋅ ⋅ ⋅ = ⋅<br />
3<br />
3<br />
⎢<br />
= =<br />
⎣m<br />
⎥<br />
⎦<br />
P rad<br />
= 2.<br />
52<br />
Mbar<br />
[ ]