Lecture Notes for Astronomy 321, W 2004 1 Stellar Energy ...
Lecture Notes for Astronomy 321, W 2004 1 Stellar Energy ...
Lecture Notes for Astronomy 321, W 2004 1 Stellar Energy ...
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expressions <strong>for</strong> K are accurate, and we will often notationally use E to mean<br />
kinetic energy.<br />
We will borrow the unit system which is customary in atomic, nuclear,<br />
and particle physics. <strong>Energy</strong> is expressed in units of eV, where<br />
1 eV = 1.60 × 10 −19 J = 1.60 × 10 −12 erg .<br />
Most importantly, we use E 2 = p 2 c 2 +m 2 c 4 to allow us to also write rest mass<br />
and momentum using the eV. So rest mass has units eV/c 2 (more typically<br />
MeV/c 2 ), and momentum eV/c. In this way, we do not usually have to<br />
multiply or divide by the numerical value <strong>for</strong> c.<br />
1.2 Physical data and conversions<br />
c = 2.9979 × 10 8 m/s<br />
1 eV = 1.60 × 10 −19 J = 1.60 × 10 −12 erg<br />
1 fm = 10 −15 m<br />
¯h = h/2π = 1.054 × 10 −34 J s = 6.58 × 10 −22 MeV s<br />
¯hc = 197 MeV fm<br />
e = 1.60 × 10 −19 C = 4.80 × 10 −10 esu<br />
k = 1.38 × 10 −23 J/K = 8.62 × 10 −11 MeV/K<br />
G = 6.67 × 10 −11 N m 2 / kg 2<br />
α = e 2 /(4πɛ 0¯hc) (in SI) = 1/137<br />
m e c 2 = 0.511 MeV<br />
m p c 2 = 938 MeV<br />
(m n − m p )c 2 = 1.293 MeV<br />
1 u = 931.49432 MeV/c 2<br />
1 pc = 3.086 × 10 16 m = 3.262 ly<br />
M ⊙ = 1.99 × 10 30 kg<br />
L ⊙ = 3.85 × 10 26 W<br />
2