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IIT-JEE 2011 - Career Point

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the indivual forces. It's often helpful to use<br />

components in an xy-coordinate system. Be sure<br />

to use correct vector notation; if a symbol<br />

represents a vector quantity, put an arrow over it.<br />

If you get sloppy with your notation, you will also<br />

get sloppy with your thinking.<br />

As always, using consistent units is essential.<br />

With the value of k = 1/4πε 0 given above,<br />

distances must be in meters, charge in coulombs,<br />

and force in newtons. If you are given distance in<br />

centimeters, inches, or furlongs, donot forget to<br />

convert ! When a charge is given in<br />

microcoulombs (µC) or nanocoulombs (nC),<br />

remember that 1µC = 10 –6 C and 1nC = 10 –9 C.<br />

Some example and problems in this and later<br />

chapters involve a continuous distribution of<br />

charge along a line or over a surface. In these<br />

cases the vector sum described in Step 3 becomes<br />

a vector integral, usually carried out by use of<br />

components. We divide the total charge<br />

distribution into infinitesimal pieces, use<br />

Coulomb's law for each piece, and then integrate<br />

to find the vector sum. Sometimes this process<br />

can be done without explicit use of integration.<br />

In many situations the charge distribution will be<br />

symmetrical. For example, you might be asked to<br />

find the force on a charge Q in the presence of<br />

two other identical charges q, one above and to<br />

the left of Q and the other below and to the left of<br />

Q. If the distance from Q to each of the other<br />

charges are the same, the force on Q from each<br />

charge has the same magnitude; if each force<br />

vector makes the same angle with the horizontal<br />

axis, adding these vectors to find the net force is<br />

particularly easy. Whenever possible, exploit any<br />

symmetries to simplify the problem-solving<br />

process.<br />

Step 4 : your answer : Check whether your numerical<br />

results are reasonable, and confirm that the like<br />

charges repel opposite charges attract.<br />

Problem solving strategy : Electric-field calculations<br />

Step 1: the relevant concepts : Use the principle of<br />

superposition whenever you need to calculate the<br />

electric field due to a charge distribution (two or<br />

more point charges, a distribution over a line, surface,<br />

or volume or a combination of these).<br />

Step 2: The problem using the following steps :<br />

Make a drawing that clearly shows the locations<br />

of the charges and your choice of coordinate axes.<br />

On your drawing, indicate the position of the field<br />

point (the point at which you want to calculate the<br />

electric field E r ). Sometimes the field point will<br />

be at some arbitrary position along a line. For<br />

example, you may be asked to find E r at point on<br />

the x-axis.<br />

Step 3 : The solution as follows :<br />

Be sure to use a consistent set of units. Distances<br />

must be in meters and charge must be in<br />

coulombs. If you are given centimeters or<br />

nanocoulombs, do not forget to convert.<br />

When adding up the electric fields caused by<br />

different parts of the charge distribution,<br />

remember that electric field is a vector, so you<br />

must use vector addition. Don't simply add<br />

together the magnitude of the individual fields:<br />

the directions are important, too.<br />

Take advantage of any symmetries in the charge<br />

distribution. For example, if a positive charge and<br />

a negative charge of equal magnitude are placed<br />

symmetrically with respect to the field point, they<br />

produce electric fields of the same magnitude but<br />

with mirror-image directions. Exploiting these<br />

symmetries will simplify your calculations.<br />

Must often you will use components to compute<br />

vector sums. Use proper vector notation;<br />

distinguish carefully between scalars, vectors, and<br />

components of vectors. Be certain the<br />

components are consistent with your choice of<br />

coordinate axes.<br />

In working out the directions of E r<br />

vectors, be<br />

careful to distinguish between the source point<br />

and the field point. The field produced by a point<br />

charge always points from source point to field<br />

point if the charge is positive; it points in the<br />

opposite direction if the charge is negative.<br />

In some situations you will have a continuous<br />

distribution of charge along a line, over a surface,<br />

or through a volume. Then you must define a<br />

small element of charge that can be considered as<br />

a point, finds of all charge elements. Usually it is<br />

easiest to do this for each component of E r<br />

separately, and often you will need to evaluate<br />

one or more integrals. Make certain the limits on<br />

your integrals are correct; especially when the<br />

situation has symmetry, make sure you don't<br />

count the charge twice.<br />

Step 4 : your answer : Check that the direction of E r<br />

is reason able. If your result for the electric-field<br />

magnitude E is a function of position (say, the<br />

coordinate x), check your result in any limits for<br />

which you know what the magnitude should be.<br />

When possible, check your answer by calculating it<br />

in a different way.<br />

Problem solving strategy : Gauss's Law<br />

Step 1 : Identify the relevant concepts : Gauss's law<br />

is most useful in situations where the charge<br />

distribution has spherical or cylindrical symmetry or<br />

is distributed uniform over a plane. In these situations<br />

we determine the direction of E r from the symmetry<br />

of the charge distribution. If we are given the charge<br />

distribution. we can use Gauss's law to find the the<br />

magnitude of E r . Alternatively, if we are given the<br />

field, we can use Gauss's law to determine the details<br />

XtraEdge for <strong>IIT</strong>-<strong>JEE</strong> 25 MAY 2010

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