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IIT-JEE 2011 - Career Point

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⎛ n ⎞ ⎛ n ⎞<br />

Correction term ∝ ⎜ ⎟ ⎜ ⎟<br />

⎝ V ⎠ ⎝ V ⎠<br />

2<br />

n<br />

or Correction term = a<br />

...( 3)<br />

2<br />

V<br />

Where a is the proportionality constant and is a<br />

measure of the forces of attraction between the<br />

molecules. Thus<br />

2<br />

n<br />

p i = p + a<br />

...(4)<br />

2<br />

V<br />

The unit of the term an 2 /V 2 will be the same as that of<br />

the pressure. Thus, the SI unit of a will be Pa m 6 mol –2 .<br />

It may be conveniently expressed in kPa dm 6 mol –2 .<br />

When the expressions as given by Eqs (1) and (4) are<br />

substituted in the ideal gas equation p i V i = nRT, we<br />

get<br />

⎛<br />

2<br />

⎞<br />

⎜<br />

n a<br />

p + ⎟ (V – nb) = nRT ...(5)<br />

2<br />

⎝ V ⎠<br />

This equation is applicable to real gases and is known<br />

as the van der Waals equation.<br />

Values of van der Waals Constants :<br />

The constants a and b in van der Waals equation are<br />

called van der Waals constants and their values<br />

depend upon the nature of the gas. They<br />

Van Der Waals Constants<br />

a<br />

Gas 6 2<br />

kPa dm mol –<br />

H 2<br />

He<br />

N 2<br />

O 2<br />

Cl 2<br />

NO<br />

NO 2<br />

H 2 O<br />

CH 4<br />

C 2 H 6<br />

C 3 H 8<br />

C 4 H 10 (n)<br />

C 4 H 10 (iso)<br />

C 5 H 12 (n)<br />

CO<br />

CO 2<br />

21.764<br />

3.457<br />

140.842<br />

137.802<br />

657.903<br />

135.776<br />

535.401<br />

553.639<br />

228.285<br />

556.173<br />

877.880<br />

1466.173<br />

1304.053<br />

1926.188<br />

150.468<br />

363.959<br />

b<br />

dm<br />

3 mol –1<br />

0.026 61<br />

0.023 70<br />

0.039 13<br />

0.031 83<br />

0.056 22<br />

0.027 89<br />

0.044 24<br />

0.030 49<br />

0.042 78<br />

0.063 80<br />

0.084 45<br />

0.122 6<br />

0.114 2<br />

0.146 0<br />

0.039 85<br />

0.042 67<br />

are characteristics of the gas. The values of these<br />

constants are determined by the critical constants of<br />

the gas. Actually, the so-called constant vary to some<br />

extent with temperature and this shows that the van<br />

der Waals equation is not a complete solution of the<br />

behaviour of real gases.<br />

Applicability of the Van Der Waals Equation :<br />

Since the van der Waals equation is applicable to real<br />

gases, it is worth considering how far this equation<br />

can explain the experimental behaviours of real<br />

gases. The van der Waals equation for 1 mole of a<br />

gas is<br />

⎛ ⎞<br />

⎜<br />

a<br />

p + ⎟ (V 2<br />

m – b) = RT ..(i)<br />

⎝ V m ⎠<br />

At low pressure When pressure is low, the volume is<br />

sufficiently large and b can be ignored in comparison<br />

to V m in Eq. (i). Thus, we have<br />

⎛ ⎞<br />

⎜<br />

a<br />

⎟<br />

a<br />

p + V 2<br />

m = RT or pV m + =RT<br />

⎝ V m ⎠<br />

V m<br />

a<br />

or Z = 1 –<br />

...(ii)<br />

VmRT<br />

From the above equation it is clear that in the low<br />

pressure region, Z is less than 1. On increasing the<br />

pressure in this region, the value of the term<br />

(a/V m RT) increase as V is inversely proportional to p.<br />

Consequently, Z decreases with increase of p.<br />

At high pressure When p is large , V m will be small<br />

and one cannot ignore b in comparison to V m .<br />

2<br />

However, the term a / V m may be considered<br />

negligible in comparison to p in Eq. (i) Thus,<br />

pb<br />

p(V m – b) = RT or Z = 1 + ...(iiii)<br />

RT<br />

Here Z is greater than 1 and increases linearly with<br />

pressure. This explains the nature of the graph in the<br />

high pressure region.<br />

A high temperature and low pressure If<br />

temperature is high, V m will also be sufficiently large<br />

2<br />

and thus the term a / V m will be negligibly small. At<br />

this stage, b may also be negligible in comparison to<br />

V m . Under these conditions, Eq. (i) reduces to an<br />

ideal gas equation of state:<br />

pV m = RT<br />

Hydrogen and helium The value of a is extremely<br />

small for these gases as they are difficult to liquefy.<br />

Thus, we have the equation of state as p(V m – b) = RT,<br />

obtained from the van der Waals equation by<br />

2<br />

ignoring the term a / V m . Hence, Z is always greater<br />

than 1 and it increases with increase of p.<br />

The van dar Waals equation is a distinct<br />

improvement over the ideal gas law in that it gives<br />

qualitative reasons for the deviations from ideal<br />

behaviour. However, the generality of the equation is<br />

lost as it contains two constants, the values of which<br />

depend upon the nature of the gas.<br />

XtraEdge for <strong>IIT</strong>-<strong>JEE</strong> 35 MAY 2010

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