IIT-JEE 2011 - Career Point

Ans.
[D]
Sol. (i) CH 3 –CH 2 –C≡CH
NaNH 2
CH 3 CH 2 C≡
C –
C –
+
Na
(ii) CH 3 –CH 2 –CH 2 –CH 2 –Br + CH 3 CH 2 –C≡
+
Na
––→ CH 3 –CH 2 –CH 2 –CH 2 –C ≡C–CH 2 –CH 3
6. The correct statement about the following
disaccharide is
CH 2 OH
H O
CH 2 OH O H
H
H (a)
OH H
(b) OH
OCH 2 CH 2 O
H
OH
CH 2 OH
H OH
OH H
(A) Ring (a) is pyranose with α-glycosidic link
(B) Ring (a) is furanose with α-glycosidic link
(C) Ring (b) is furanose with α-glycosidic link
(D) Ring (b) is Pyranose with β-glycosidic link
Ans. [A]
Sol. Ring (a) is pyranose with α-glycosidic link
7. Plots showing the variation of the rate constant
(k) with temperature (T) are given below. The
plot that follows Arrhenius equation is -
Ans.
Sol.
(A)
k
(C)
k
T
T
[A]
k = Ae –Ea/RT ; k ∝ e
k
T
– E a / RT
(B)
k
(D)
k
8. In the reaction OCH 3 HBr the
products are
(A) Br
OCH 3 and H 2
(B)
Br and CH 3 Br
T
T
Ans.
Sol.
(C)
(D)
[D]
Br and CH 3 OH
OH and CH 3 Br
OCH 3
HBr
SECTION – II
Multiple Correct Choice Type
OH + CH 3 Br
This section contains 5 multiple choice questions. Each
questions has 4 choices (A), (B), (C) and (D), out of
which ONE OR MORE is/are correct.
9. In the reaction
intermediate(s) is (are)
(A)
O
Br
O
(C)
Br
Ans. [A, B, C]
OH
Br
Sol. NaOH(aq)/Br 2
Br
OH
(B)
(D)
NaOH(aq)/Br 2
OH
Br
Br
O
Br Br
O
Br
the
Bromination take place at ortho & para position
due to activation of benzene ring by –OH group.
10. The reagent(s) used for softening the temporary
hardness of water is (are) -
(A) Ca 3 (PO 4 ) 2 (B) Ca(OH) 2
(C) Na 2 CO 3
(D) NaOCl
Ans. [B, C, D]
11. Aqueous solutions of HNO 3 , KOH, CH 3 COOH
and CH 3 COONa of identical concentrations are
provided. The pair(s) of solutions which from a
buffer upon mixing is(are)
XtraEdge for IIT-JEE 67
MAY 2010