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Answers to Math
Applications
Math Applications for this
chapter are on pages 422–429.
The notes and solutions shown
below accompany the suggested
applications to assign with this
lesson.
8. a. 2(3) 0 = 2(1) = 2
4
b. ∑ 23 ( ) n
= 2(3) 0 + 2(3) 1
n= 0
+ 2(3) 2 + 2(3) 3 + 2(3) 4
= 2 + 6 + 18 + 54 + 162
= 242
c. total ratings = 242 +
= 250
no; Misty has a 242
250 =
96.8% positive feedback
rating, which is less than
98%.
10. a. Convert the times to
seconds.
220 242
= 1.1;
200 220 = 1.1;
266. 2 = 1.1;
292.
82
242 266.
2
= 1.1;
322.
102
= 1.1
292.
82
The common ratio is 1.1.
b. 322.102(1.1) = 354.3122
= 5 min 54.3122 s
c. 2 h 28 min = 8,880 s
8,880 + 200 + 220 +
242 + 266.2 + 292.82
+ 322.102 + 354.3122
= 10,777.4342 ≈
179.62 min
Paige’s goal was 3 hours or
180 minutes.
179.62 min < 180 min, so
yes, Paige met her goal.
13. a. 120 48
300
= 0.4;
120 = 0.4;
19.
2
48
= 0.4; 768 .
= 0.4;
19.
2
3.
072
= 0.4
768 .
The common ratio is 0.4.
3.072(0.4) = 1.2288 kb/s
10 a
d
2
10a
25,
000
( x 500)
2
( ) 2
500
250,
000
b. 1.2288(0.4) = 0.49152 kb/s, therefore 400 users would be on the
network.
408 Chapter 9 Sequences and Series