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<strong>Chapter</strong> <strong>10</strong><br />

Contents<br />

<strong>10</strong>.1 Right Triangle Trigonometry<br />

<strong>10</strong>.2 Evaluating Trigonometric<br />

Functions<br />

<strong>10</strong>.3 Inverse Trigonometric<br />

Functions<br />

<strong>10</strong>.4 Graphing Trigonometric<br />

Functions<br />

<strong>10</strong>.5 The Law of Sines and Law of<br />

Cosines<br />

<strong>10</strong>.6 Verifying Trigonometric<br />

Identities<br />

<strong>10</strong>.7 Angle Sum and Difference<br />

Identities<br />

<strong>10</strong>.8 Double-Angle and Half-<br />

Angle Identities<br />

<strong>10</strong>.9 Solving Trigonometric<br />

Equations<br />

Math Labs<br />

The Circle of Your City<br />

The Sun Today<br />

The Sine Curve of Biorhythms<br />

Swing of a Pendulum<br />

Math Applications<br />

<strong>Chapter</strong> Review<br />

<strong>Chapter</strong> Assessment<br />

434 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Trigonometric Functions<br />

and Identities<br />

Why should I learn this<br />

Trigonometry is about right angles and angle relationships. Many real‐world<br />

problems that are solved using trigonometric functions relate to indirect<br />

measurement. The topics of this chapter incorporate previously learned skills,<br />

such as using the Pythagorean Theorem and simplifying radicals.<br />

Trigonometric functions and relationships are the underlying mathematics used<br />

in occupations that deal with distance and measurement.<br />

• Air Traffic Controllers interpret data processed by machines that are<br />

programmed using trigonometric functions.<br />

• Cartographers use trigonometry to indirectly measure distances and<br />

verify that their maps are accurate.<br />

• Musicians, especially those who play stringed instruments, produce<br />

harmonic tones that are based on variations of the sine function.<br />

In this chapter, you will use the trigonometric ratios to interpret and solve<br />

problems. You will also learn to convert measurements between degrees<br />

and radians.<br />

Project Idea: Shadow to Shadow<br />

When you are outside on a sunny day, you cast a shadow. The length<br />

of the shadow depends on the time of day. The ratio of the height of<br />

a person to the length of the shadow cast is equivalent to the ratio of<br />

another person or object and its shadow length. Both measurements<br />

must be taken at the same time of day from the same place.<br />

Select an object, such as a tree or a flag pole, on the school<br />

grounds. Work with a partner to determine and verify the<br />

height of that object using indirect measurement. Find the<br />

length of shadows cast by you and your selected object.<br />

Then use your height and measurements gathered to find<br />

the height of your object. Your partner should make the<br />

same measurements and computations using his or her<br />

height and shadow to find the height of the object. You<br />

can verify the height of your object by comparing results<br />

with your partner.<br />

<strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities 435


Lesson <strong>10</strong>.1 Right Triangle Trigonometry<br />

Objectives<br />

Find lengths in triangles<br />

using trigonometric<br />

relationships.<br />

From where Horacio stands at a distance of 38 feet from the base of<br />

the school building, the angle to the top of the school is 40°. What is<br />

the height of the school building<br />

Activity<br />

Finding Right Triangle Ratios<br />

Use a protractor and a straightedge to<br />

draw three right triangles on a sheet<br />

of paper. Each triangle should have an<br />

acute angle that measures 50°. Label<br />

this angle a in each triangle. Make<br />

the hypotenuses of the three similar<br />

triangles 5, 8, and <strong>10</strong> centimeters.<br />

1 Measure the lengths of the legs of each right triangle to the<br />

nearest tenth. Small: 3.8 cm, 3.2 cm; Medium: 6.1 cm, 5.1 cm;<br />

Large: 7.7 cm, 6.4 cm<br />

2 What is the ratio of the length of the leg opposite ∠a to<br />

the length of the hypotenuse in each triangle Round to the<br />

nearest tenth. 0.8 for each triangle<br />

3 What is the ratio of the length of the leg adjacent to ∠a to<br />

the length of the hypotenuse in each triangle Round to the<br />

nearest tenth. 0.6 for each triangle<br />

4 What is the ratio of the length of the leg opposite ∠a to the<br />

length of the leg adjacent to ∠a in each triangle Round to<br />

the nearest tenth. 1.2 for each triangle<br />

5 Make a conjecture about these ratios for all right triangles<br />

that have an acute angle of 50°. The ratios are the same for any<br />

right triangle with an acute angle of 50°.<br />

436 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Trigonometric Ratios<br />

There are six special ratios between the lengths of the sides of right triangles<br />

that are known as trigonometric ratios. These trigonometric ratios are<br />

shown below.<br />

Trigonometric Ratios<br />

leg opposite ∠A<br />

The sine of angle A, abbreviated sin A = =<br />

a<br />

hypotenuse c<br />

leg adjacent ∠A<br />

The cosine of angle A, abbreviated cos A = =<br />

b<br />

hypotenuse c<br />

A<br />

The tangent of angle A, abbreviated tan A = leg opposite ∠<br />

leg adjacent ∠A<br />

=<br />

The cosecant of angle A, abbreviated csc A =<br />

1 hypotenuse<br />

= =<br />

c<br />

sin A leg opposite ∠A<br />

a<br />

The secant of angle A, abbreviated sec A = 1<br />

A<br />

= hypotenuse<br />

cos leg adjacent ∠A<br />

=<br />

A<br />

The cotangent of angle A, abbreviated cot A =<br />

1 leg adjacent ∠<br />

= =<br />

b<br />

tan A leg opposite ∠A<br />

a<br />

Notice that the sine and cosecant ratios are multiplicative inverses of each<br />

other, as are the cosine and secant ratios and tangent and cotangent ratios.<br />

a<br />

b<br />

c<br />

b<br />

Example 1<br />

Finding Trigonometric Ratios<br />

Find the trigonometric ratios for ∠N in the triangle below.<br />

<strong>10</strong>.1 Right Triangle Trigonometry 437


Solution<br />

Use the definitions of the trigonometric ratios. Reduce each ratio.<br />

sinN<br />

=<br />

8<br />

=<br />

4<br />

csc N =<br />

<strong>10</strong><br />

=<br />

5<br />

<strong>10</strong> 5<br />

8 4<br />

cosN<br />

=<br />

6<br />

=<br />

3<br />

sec N =<br />

<strong>10</strong><br />

=<br />

5<br />

<strong>10</strong> 5<br />

6 3<br />

tanN<br />

=<br />

8<br />

=<br />

4<br />

6 3<br />

cot N<br />

Ongoing Assessment<br />

Find the trigonometric ratios<br />

for ∠Z in the triangle below.<br />

see margin<br />

=<br />

6<br />

=<br />

8<br />

3<br />

4<br />

Example 2<br />

Finding the Height of a Building<br />

Use the information in the opening paragraph of this lesson. What is the<br />

height of the school building<br />

Solution<br />

Draw a picture to help solve the problem.<br />

Choose a trigonometric ratio that relates the leg opposite an angle and the<br />

leg adjacent to an angle. Use the tangent ratio to find the unknown height of<br />

the school building.<br />

tan 40° =<br />

x<br />

38<br />

Use a calculator to approximate tan 40° and solve for x.<br />

0.839 ≈<br />

x<br />

38<br />

31.9 ≈ x<br />

The height of the school building is about 31.9 feet.<br />

438 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Ongoing Assessment<br />

The angle from the top of a tree to a point 20 meters from the base of<br />

the tree is 52°. What is the height of the tree Round your answer to the<br />

nearest tenth. about 15.6 m<br />

Lesson Assessment<br />

Think and Discuss<br />

1. Which trigonometric ratio in a right triangle relates an angle<br />

measure to the side opposite the angle and the hypotenuse<br />

see margin<br />

2. Explain how to find the height of a tree if the horizontal distance<br />

to the base of the tree and the angle of elevation to the top of<br />

the tree are known.<br />

3. In a right triangle, what ratio of side lengths is equal to the cosine<br />

of an angle<br />

4. What happens to the cosine of an angle if the side lengths of the<br />

triangle are doubled<br />

5. Which trigonometric ratio is the reciprocal of the sine ratio<br />

Practice and Problem Solving<br />

Use triangle DEF to find each trigonometric ratio.<br />

6. sin E 5<br />

13<br />

9. cos E 12<br />

13<br />

12. sec D 13<br />

5<br />

15. csc D 13<br />

12<br />

7. cos D 5<br />

13<br />

<strong>10</strong>. sin D 12<br />

13<br />

13. csc E 13<br />

5<br />

16. cot E 12<br />

5<br />

8. tan E 5<br />

12<br />

11. tan D 12<br />

5<br />

14. cot D 5<br />

12<br />

17. sec E 13<br />

12<br />

<strong>10</strong>.1 Right Triangle Trigonometry 439


Solve for x in each right triangle. Round your answer to the<br />

nearest tenth if necessary.<br />

18.<br />

19.<br />

x = 6.0<br />

x = 8.2<br />

20.<br />

21.<br />

x = 8.5<br />

x = 30.1<br />

22. The angle from the top of a flagpole to a point 30 feet from the<br />

base of the flagpole is 54°. What is the height of the flagpole<br />

Round your answer to the nearest tenth. 21.8 ft<br />

23. Three fishing docks are situated on a riverbank as shown. What is<br />

the width of the river Round your answer to the nearest tenth.<br />

54.5 yd<br />

24. A ladder is leaning against the side of the house. The ladder and<br />

the side of the house form an angle of 25°. The bottom of the<br />

ladder is 5.1 feet from the base of the house. What is the length<br />

of the ladder Round your answer to the nearest tenth. 12.0 ft<br />

25. After an airplane takes off from the runway, it climbs at an<br />

angle of elevation of 25°. What is the altitude of the plane after<br />

covering a horizontal distance of 400 feet Round your answer to<br />

the nearest tenth. 186.5 ft<br />

440 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


26. What is the height of the skyscraper to the nearest meter 192 m<br />

27. Carlos built a bike ramp shaped like a right triangular prism. The<br />

board used for the ramp is 6 feet long. If the ramp has an angle<br />

of elevation of 24º, what is the height of the ramp Round your<br />

answer to the nearest tenth. 2.4 ft<br />

28. A wire support for a radio antenna forms a 68º angle with the<br />

side of the antenna tower. The wire is 48 feet long. How high<br />

up the antenna tower does it reach Round your answer to the<br />

nearest tenth. 18.0 ft<br />

29. What is the horizontal distance between the hot air balloon and<br />

the landing zone Round your answer to the nearest tenth.<br />

2,425.8 ft<br />

<strong>10</strong>.1 Right Triangle Trigonometry 441


30. A wheelchair ramp is 20 feet long with an angle of incline of 5°.<br />

How many feet does the incline of the ramp rise Round your<br />

answer to the nearest tenth. 1.7 ft<br />

31. The angle of elevation from a boat to the top of a lighthouse<br />

is 21°. The height of the lighthouse is 47 feet. What is the<br />

distance from the boat to the base of the lighthouse Round to<br />

the nearest tenth of a foot. 122.4 ft<br />

32. A landscaper is standing 25 meters from the base of a tree. The<br />

angle of elevation from the landscaper to the top of the tree<br />

is 41°. What is the height of the tree Round to the nearest tenth<br />

of a meter. 22.7 m<br />

Mixed Review<br />

Find each difference.<br />

33.<br />

5<br />

– 2 3x<br />

− 6<br />

2<br />

x + 3 x x + 3x<br />

35. 9 –<br />

2k<br />

k + 2 3k + 6<br />

27 − 2k<br />

3k<br />

+ 6<br />

442 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

34.<br />

36.<br />

4<br />

5r – 1 8 40<br />

t<br />

t + 4 – t − 7<br />

4t<br />

32 − 5r<br />

r<br />

2<br />

3t<br />

+ 3t+<br />

28<br />

2<br />

4t<br />

+ 16t<br />

37. Find the length of a side of a rectangle if its area can be<br />

modeled by the expression 28x 2 + <strong>10</strong>x – 2 and its width by<br />

the expression 4x + 2. 7x – 1<br />

38. If the third term in the expansion of (x + y) n has a coefficient<br />

of 15, what is the value of n n = 6


Lesson <strong>10</strong>.2 Evaluating Trigonometric<br />

Functions<br />

Objectives<br />

Convert between<br />

degrees and<br />

radians.<br />

Find the length of<br />

an arc.<br />

Evaluate<br />

trigonometric<br />

functions.<br />

Radians and Degrees<br />

To draw an angle in standard<br />

position, place the vertex at the<br />

origin and one ray of the angle<br />

along the positive x-axis. The ray<br />

on the x‐axis is the initial side of<br />

the angle, and the other ray is the<br />

terminal side of the angle.<br />

To measure an angle in standard<br />

position, find the amount of<br />

rotation counterclockwise from<br />

the initial side to the terminal<br />

side. Angles can be measured<br />

in degrees and in radians. A<br />

complete rotation is 360° or<br />

2π radians.<br />

Example 1 Converting Radians and Degrees<br />

Find the radian measure of an angle with a measure of 120°.<br />

Solution<br />

A full rotation of 360° is equal to 2π radians. Set up and solve a<br />

proportion for the angle measure in radians.<br />

120°<br />

=<br />

r radians<br />

360°<br />

2 π radians<br />

120 • 2π<br />

= 360°<br />

• r<br />

240π<br />

= r<br />

360<br />

2π<br />

= r<br />

3<br />

An angle with a measure of 120° has a measure of 2 3≠ , or<br />

approximately 2.1 radians.<br />

442 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Arc Length<br />

The unit circle has a radius of 1 unit<br />

and is centered about the origin.<br />

A central angle of a circle is an<br />

angle with a vertex at the center of<br />

the circle. An intercepted arc is the<br />

part of the circle that has endpoints on<br />

the sides of the central angle and all<br />

points in the interior of the angle.<br />

Arc Length<br />

If a circle with radius r has a central angle of measure<br />

θ radians, the length, l, of the intercepted arc is l = rθ.<br />

Example 2<br />

Measuring Arc Length<br />

Find the length of the intercepted arc<br />

in the circle.<br />

Solution<br />

The measure of the central angle is 1.9 radians, and the circle has a radius of<br />

6 centimeters. Use the formula for the length of an intercepted arc.<br />

l = rθ<br />

l = (6)(1.9)<br />

l = 11.4<br />

The length of the intercepted arc is 11.4 centimeters.<br />

<strong>10</strong>.2 Evaluating Trigonometric Functions 443


Ongoing Assessment<br />

The measure of the central angle is <strong>10</strong>5°, and the circle has a radius of<br />

5 inches. Find the length of the intercepted arc in the circle. 35 ≠ in.<br />

12<br />

Trigonometric Functions<br />

The sine function ( f (θ ) = sin θ )<br />

takes an angle measure as its<br />

input and gives the corresponding<br />

y-coordinate where the terminal<br />

side of the angle intersects<br />

the unit circle. The cosine<br />

function ( f (θ ) = cos θ ) gives the<br />

corresponding x-coordinate where<br />

the terminal side of the angle<br />

intersects the unit circle.<br />

The tangent function<br />

( f (θ ) = tan θ ) is the y-coordinate<br />

of the point where the ray of<br />

the terminal side of the angle θ<br />

intersects the tangent line x = 1.<br />

Example 3 Finding Trigonometric Values<br />

Use the circle to evaluate<br />

f (θ ) = sin θ for θ = 30°.<br />

Solution<br />

The sine function returns the y-coordinate of the point on the unit<br />

circle intersected by the terminal side. So sin 30° = 0.5.<br />

444 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Using a Calculator<br />

A scientific calculator can be used to evaluate trigonometric functions of<br />

different angles. Make sure your calculator is in degree mode if the angle<br />

measure is given in degrees and in radian mode if the angle measure is given<br />

in radians.<br />

Example 4<br />

Using a Calculator<br />

Use a calculator to evaluate y = tan θ for θ = 160°. Round your answer to<br />

the nearest thousandth.<br />

Solution<br />

Be sure the calculator is in DEGREE mode. Then press the key and<br />

enter the angle measure, 160. Note that on some scientific calculators, the<br />

measure of the angle is entered first.<br />

tan 160° ≈ –0.364<br />

Ongoing Assessment<br />

Use a calculator to evaluate each trigonometric expression. Round to the<br />

nearest thousandth. Be sure the calculator is in RADIAN mode. see margin<br />

a. cos 2 ≠<br />

7<br />

Lesson Assessment<br />

Think and Discuss<br />

b. sin ≠ 4<br />

c. tan 2p<br />

1. Explain how to convert an angle measure from radians<br />

to degrees.<br />

see margin<br />

2. Describe how to find the measure of a central angle if the<br />

circumference of the circle and the length of the intercepted arc<br />

are known.<br />

3. What is the x-coordinate of the point where the terminal side of<br />

an angle, θ, intersects the unit circle<br />

4. Describe in your own words what the value of tan θ means as it<br />

pertains to the unit circle.<br />

5. What is the y-coordinate of the point where the terminal side of<br />

an angle, θ, intersects the unit circle<br />

6. Which trigonometric function has a value of 1 for θ = 45°<br />

<strong>10</strong>.2 Evaluating Trigonometric Functions 445


Practice and Problem Solving<br />

Convert each angle measure from degrees to radians.<br />

7. 180° π radians 8. 135° 3 ≠ radians<br />

4<br />

9. 60° ≠ 3 radians <strong>10</strong>. 75° 5 ≠ radians<br />

12<br />

Convert each angle measure from radians to degrees.<br />

11.<br />

≠<br />

2 90° 12. 3≠ 67.5°<br />

8<br />

13.<br />

3≠ 270 14.<br />

7≠ 157.5°<br />

2<br />

8<br />

Use the unit circles to evaluate each trigonometric function.<br />

Round each answer to the nearest thousandth.<br />

15. cos 60° 0.5 16. sin 3 ≠ –1<br />

2<br />

17. tan 40° 0.839 18. sin 5 ≠<br />

0.5<br />

6<br />

446 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Find the length of the intercepted arc in each circle. Round your<br />

answer to the nearest tenth if necessary. see margin<br />

19. 20.<br />

Use a calculator to evaluate each trigonometric function. Round<br />

to the nearest thousandth when necessary.<br />

21. cos 2 ≠<br />

–0.5 22. sin 85° 0.996<br />

3<br />

23. cos 90° 0 24. tan 3 ≠<br />

–1<br />

4<br />

25. sin 225° –0.707 26. tan 135° –1<br />

Use a calculator to evaluate each function for the given<br />

argument. Round to the nearest thousandth when necessary.<br />

27. y = 3cos 2θ, θ = 20º 2.298<br />

28. g(θ) = 4 – sin 1.5θ, θ = 5 ≠<br />

3.076<br />

12<br />

29. The height above the ground of a person riding on a Ferris Wheel<br />

can be modeled by the function f(x) = 30 – 28cos ≠x . In the<br />

24<br />

function, x is the number of seconds since the ride began, and<br />

f(x) is the height in feet.<br />

a. What is the height of the passenger when the ride begins<br />

(at x = 0 seconds) 2 ft<br />

b. The passenger reaches the top of the Ferris Wheel after<br />

24 seconds. What is the height at the top of the ride 58 ft<br />

c. What is the passenger’s height above the ground after<br />

<strong>10</strong> seconds Round to the nearest tenth if necessary. 22.8 ft<br />

d. How long does it take for the passenger to complete one<br />

full rotation around the Ferris Wheel Check your answer by<br />

evaluating the trigonometric function. 48 s<br />

<strong>10</strong>.2 Evaluating Trigonometric Functions 447


30. A stretch of highway has a 12° angle of incline. What is this angle<br />

measure in radians ≠<br />

15 radians<br />

31. Kimmy skated from point A to point B along the outside of the<br />

skating rink. How far did she travel Round your answer to the<br />

nearest foot. 314 ft<br />

32. The temperature, in degrees Fahrenheit, inside a refrigerator can<br />

be modeled by the function y = 38 + 1.5cos ≠x , where x is the<br />

<strong>10</strong><br />

number of minutes after the refrigerator’s motor begins to run.<br />

448 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

a. The warmest temperature inside the refrigerator occurs just as<br />

the motor begins to run. What is this temperature 39.5ºF<br />

b. The motor runs for <strong>10</strong> minutes until the air inside the<br />

refrigerator is cooled to its lowest temperature. Then the<br />

motor rests for <strong>10</strong> minutes before it begins to run. What is<br />

the coolest temperature inside the refrigerator 36.5ºF<br />

33. Nancy attaches a reflector to one of the spokes of her bicycle tire<br />

for increased visibility in low light. The position of the reflector<br />

relative to the ground as Nancy pedals down the street is given<br />

by the function h(x) = <strong>10</strong> + 7sin 4πx. In the function, x is the<br />

number of seconds since Nancy began pedaling, and h(x) is the<br />

height, in inches, of the reflector above the ground.<br />

a. How long does it take for the reflector to complete one<br />

full rotation Verify your answer by substituting it into the<br />

function. 0.5 s<br />

b. What is the maximum height of the reflector above the<br />

ground 17 in.<br />

Mixed Review<br />

State whether or not each infinite geometric series converges<br />

or diverges. Then determine whether or not each series has<br />

a sum.<br />

d<br />

)<br />

∑ . ( )<br />

∞<br />

∑ (<br />

d=<br />

1<br />

∞<br />

34. 5 1 2<br />

35. 045 <strong>10</strong> 9<br />

b=<br />

1<br />

converges; has a sum<br />

b<br />

diverges; does not have a sum<br />

36. A radio tower is located <strong>10</strong> miles east and 15 miles north of the<br />

origin on a map of Reedsburg. The tower has enough power to<br />

broadcast over a radius of 40 miles. Write an equation to model<br />

the area of the broadcast of the radio tower.<br />

(x – <strong>10</strong>) 2 + (y – 15) 2 = 40 2


Lesson <strong>10</strong>.3 Inverse Trigonometric<br />

Functions<br />

Objectives<br />

Find the angle measure<br />

given the side lengths of<br />

a triangle.<br />

Joshua and his friends built a skateboarding ramp. The ramp is 5 feet<br />

long and 2 feet high. What is the angle of the ramp’s incline<br />

Evaluating Inverse Trigonometric Functions<br />

An inverse function is a mathematical function that “undoes”<br />

another function. That is, if f and f –1 are inverse functions,<br />

(f ◦ f –1 )(x) = x and (f –1 ◦ f )(x) = x. For the sin, cos, and tan functions,<br />

the corresponding inverse functions are sin –1 , cos –1 , and tan –1 .<br />

Example 1<br />

Evaluating Inverse Trigonometric<br />

Functions<br />

Use a calculator to find the measure, in radians, of an angle that has a<br />

sine value of 0.707. Round your answer to the nearest hundredth.<br />

Solution<br />

Be sure the calculator is in RADIAN mode. Enter the sine value on<br />

the calculator. Then use the sin –1 function to evaluate the inverse<br />

trigonometric function.<br />

sin –1 (0.707) ≈ 0.79 radians<br />

Ongoing Assessment<br />

Use a calculator to find the measure, in degrees, of an angle that has<br />

a tangent value of 2.145. Round your answer to the nearest whole<br />

degree. Be sure the calculator is in DEGREE mode. 65°<br />

<strong>10</strong>.3 Inverse Trigonometric Functions 449


Finding Angle Measures<br />

Inverse trigonometric functions can be used to find missing angle measures<br />

when you know the side lengths of a right triangle.<br />

Example 2<br />

Finding an Angle Measure<br />

Given Side Lengths<br />

Use the information from the opening paragraph of this lesson. What is the<br />

measure, in degrees, of the angle of the ramp’s incline Round your answer<br />

to the nearest tenth.<br />

Solution<br />

Draw a diagram.<br />

Recall that the tangent of an angle in a right triangle is defined as the ratio of<br />

the length of the side opposite the angle to the length of the side adjacent to<br />

the angle. So, tan x = 2 . Use the inverse tangent function to solve for x.<br />

5<br />

tan x =<br />

2<br />

5<br />

tan (tan x)<br />

= tan<br />

x ≈ 21.<br />

8°<br />

2<br />

5<br />

−1 − 1( )<br />

The angle of the ramp’s incline, rounded to the nearest tenth, is 21.8°.<br />

Ongoing Assessment<br />

The figure shows the cross-section of a roof. What is the roof’s angle of<br />

incline, x, in degrees Round your answer to the nearest tenth. 22.6°<br />

450 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


see margin<br />

After taking off, a commercial jet covers<br />

a horizontal distance of 23,<strong>10</strong>0 feet<br />

during the first 45 seconds of flight<br />

and climbs to a height of 3,040 feet<br />

above the ground. What is the plane’s<br />

angle of elevation during the first part<br />

of the ascent. Explain why it might be<br />

important to know the plane’s initial<br />

angle of elevation.<br />

Step 1 Understand the Problem<br />

What is the relevant information<br />

presented in the problem statement<br />

What will you need to calculate to solve<br />

the problem<br />

Step 2 Develop a Plan<br />

Problem-solving strategy: Use a diagram.<br />

What kind of triangle can be used to model<br />

the situation Drawing a diagram can help<br />

you understand the problem and develop a<br />

method to solve it.<br />

Step 3 Carry Out the Plan<br />

Model the problem situation with a diagram.<br />

Use the diagram to help you set up and solve<br />

a trigonometric equation for the jet’s angle of<br />

elevation, x. Round your answer to the nearest<br />

tenth of a degree.<br />

Step 4 Check the Results<br />

Check the angle measure by substituting it into<br />

the equation and making sure the result is a<br />

true number sentence.<br />

Lesson Assessment<br />

Think and Discuss<br />

see margin<br />

1. What is the result when you simplify tan –1 (tan x) Explain.<br />

2. Explain how to find the measure of the angle whose terminal side<br />

intersects the unit circle at (0.5, 0.866).<br />

3. If the lengths of the legs of a right triangle are known, how can<br />

the measures of the acute angles of the triangle be found<br />

4. Which inverse trigonometric function would you use to find the<br />

measure of an acute angle in a right triangle if you know the<br />

lengths of the hypotenuse and the side opposite the angle<br />

5. How many values of x are there such that tan x = 0 Explain.<br />

<strong>10</strong>.3 Inverse Trigonometric Functions 451


Practice and Problem Solving<br />

Find the measure, in degrees, of each angle x. Round to the<br />

nearest tenth if necessary.<br />

6. sin x = 0.65, –90º ≤ x ≤ 90º 40.5º<br />

7. cos x = 0.5, 0º ≤ x ≤ 180º 60º<br />

8. sin x = 1, –90º ≤ x ≤ 90º 90º<br />

9. tan x = 2.35, –90º < x < 90º 66.9º<br />

<strong>10</strong>. cos x = 0.26, 0º ≤ x ≤ 180º 74.9º<br />

Find the measure, in radians, of each angle x. Round to the<br />

nearest thousandth if necessary.<br />

11. cos x = 0.809, 0 ≤ x ≤ π 0.628 radians<br />

12. sin x = 0.707, − π 2 ≤ x ≤ ≠ 2<br />

13. tan x = 11.6, − π 2 < x < ≠ 2<br />

0.785 radians<br />

1.485 radians<br />

14. sin x = 0, − π 2 ≤ x ≤ ≠ 2 0 radians<br />

15. cos x = 0, 0 ≤ x ≤ π 1.571 radians<br />

16. tan x = 1, − π 2 < x < ≠ 2<br />

0.785 radians<br />

Solve for the missing angle in each right triangle. Round your<br />

answer to the nearest tenth if necessary.<br />

17. 66.8º<br />

18. 46.2º<br />

19. 11.3º<br />

452 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


20. What is the angle of descent of the airplane Round your answer<br />

to the nearest tenth if necessary. 22.6º<br />

21. In triangle WXY, m∠W = 90º, x = 6.4, and y = 3.7. Find m∠X,<br />

in radians, to the nearest thousandth. 1.047 radians<br />

22. One of the legs of an isosceles right triangle is <strong>10</strong> units long and<br />

the base is <strong>10</strong> 2 units long. What is the measure, in degrees,<br />

of the base angles of the triangle Round to the nearest tenth<br />

if necessary. 45º<br />

23. Give three angle measures, in degrees, that have a cosine value of<br />

–0.5. Round your answers to the nearest tenth if necessary.<br />

Answers will vary. sample answers: 120º, 240º, 480º<br />

Mixed Review<br />

24. The geometric sequence $500, , $551.25, $578.81 gives<br />

the amount of money in Fran’s money market at an interest rate<br />

of 5% compounded quarterly. What is the missing amount in<br />

the sequence $525<br />

25. Japanese magnetic levitation trains (maglev) are among the<br />

fastest trains in the world. A maglev train sounds a 320-Hz<br />

whistle while traveling at its top speed. What is the speed of the<br />

train if the whistle is perceived as 550 Hz Round to the nearest<br />

tenth. (Assume that the speed of sound is 760 miles per hour.)<br />

≈ 317.8 mph<br />

<strong>10</strong>.3 Inverse Trigonometric Functions 453


Lesson <strong>10</strong>.4 Graphing Trigonometric<br />

Functions<br />

Objectives<br />

Graph trigonometric<br />

functions.<br />

A floating object is observed to<br />

move in circles when waves oscillate<br />

harmoniously in deep water. When<br />

the object is placed in deeper water, it<br />

moves along a circular path. The size<br />

of the circular path gets smaller and<br />

smaller in diameter at different water<br />

depths. At a certain depth, the object<br />

would stand still. This is the wave’s<br />

base, which is exactly half the wave’s<br />

length. An oceanologist is studying the<br />

position of a leaf floating on the surface<br />

of a wave. The oceanologist describes<br />

the motion of the leaf by the function y = 1.5sin 2θ. The oceanologist<br />

wants to graph this function to display the motion of the leaf.<br />

The Sine Function<br />

Recall that the function, y = sin θ, takes an angle measure as its input<br />

and gives the corresponding y-coordinate where the terminal side of<br />

the angle intersects the unit circle. So the domain of the function is<br />

the set of all angle measures, θ, and the range is between –1 and 1.<br />

The graph of a sine function is called a sine curve.<br />

The amplitude of a function is half the positive difference between<br />

its maximum and minimum values. So the amplitude of the function<br />

y = sin θ is 1. The period of a function is the horizontal length of one<br />

cycle. The function y = sin θ completes one full cycle as its output<br />

values range from 0 to 1 to –1 and then back to 0. So the period of the<br />

standard sine curve is 360° or 2π radians.<br />

454 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


The y-values on the unit circle are positive in Quadrants I and II, and<br />

negative in Quadrants III and IV. Thus, the sine curve is positive between<br />

0° and 180° and is negative between 180° and 360°. Use a calculator to<br />

verify the points along the sine curve.<br />

Characteristics of Sine Functions<br />

For the generalized sine function y = asin bθ, with a ≠ 0, b > 0,<br />

and θ in radians,<br />

• the amplitude of the function is |a|.<br />

• the number of cycles in the interval from 0 to 2π radians is b.<br />

• the period of the function is<br />

2π<br />

b .<br />

Example 1<br />

Graphing Sine Functions<br />

At the beginning of this lesson information was given about an oceanologist<br />

describing the motion of a leaf floating on the surface of a wave. The function<br />

used was y = 1.5sin 2θ. Graph this function over the interval 0 ≤ θ ≤ 2π.<br />

Solution<br />

The amplitude of the function is 1.5 because a = 1.5. Because b = 2, the<br />

function will complete 2 cycles in the interval 0 ≤ θ ≤ 2π. The period, or<br />

horizontal length, of the function is 2 ≠<br />

= 2 ≠<br />

= ≠. Choose appropriate scales<br />

b 2<br />

for the vertical and horizontal axes. Then graph the function. The graph will<br />

complete 2 cycles and range from –1.5 to 1.5.<br />

Ongoing Assessment<br />

Graph a sine curve that has amplitude 2 and a period of 4π over the interval<br />

0 ≤ θ ≤ 4π.<br />

<strong>10</strong>.4 Graphing Trigonometric Functions 455


The Cosine Function<br />

The cosine function y = cos θ gives the corresponding x-coordinate where<br />

the terminal side of the angle intersects the unit circle. So the graph of the<br />

cosine function is a sine curve that is shifted to the left. A phase shift is a<br />

horizontal translation of a periodic function. The cosine and sine functions<br />

have graphs that are 90° or ≠ radians out of phase.<br />

2<br />

Characteristics of Cosine Functions<br />

The generalized cosine function y = acos bθ, with a ≠ 0,<br />

b > 0, and θ in radians has the following properties:<br />

• the amplitude of the function is |a|.<br />

• the number of cycles in the interval from 0 to 2π<br />

radians is b.<br />

• the period of the function is 2≠ b .<br />

The graphs of the cosine (blue) and sine (purple) functions are defined for<br />

θ values that are negative and for θ values that are larger than 360°. The<br />

measure of an angle is positive when the rotation is counterclockwise. The<br />

measure of an angle is greater than 360° when more than one full rotation of<br />

the unit circle has been completed. Every angle that is negative or is greater<br />

than 360° is in the same position as an angle between 0° and 360°. Thus, the<br />

sine curve repeats itself as θ → ∞ and as θ → –∞.<br />

456 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Example 2<br />

Graphing Cosine Functions<br />

Graph the function y = 2cos θ over the interval 0 ≤ θ ≤ 2π.<br />

Solution<br />

The amplitude of the function is 2 because a = 2. Because b = 1, the<br />

function will complete 1 cycle in the interval 0 ≤ θ ≤ 2π. The period, or<br />

horizontal length, of the function is 2 ≠ 2 ≠<br />

≠<br />

b = 1<br />

= 2 . Choose appropriate<br />

scales for the vertical and horizontal axes. Then graph the function. The<br />

graph will complete 1 cycle and range from –2 to 2.<br />

Critical Thinking The function y = cos (θ – x) has a graph that is<br />

x radians out of phase with the function y = cos θ. What value of x would<br />

result in a graph that is the same as the standard sine curve y = sin θ x = π 2<br />

The Tangent Function<br />

The graph of the function y = tan θ is also a periodic function that repeats its<br />

shape over and over. The graph is centered about the origin, has a period of<br />

π radians or 180°, and vertical asymptotes that repeat every π units.<br />

<strong>10</strong>.4 Graphing Trigonometric Functions 457


The tangent function behaves asymptotically because y = tan θ is<br />

undefined when θ = π ± a π where a is an integer and a ≠ 0. Recall that<br />

y<br />

2<br />

tanθ<br />

= =<br />

sinθ<br />

and is therefore undefined whenever cos θ = 0.<br />

x cosθ<br />

Characteristics of Tangent Functions<br />

The generalized tangent function y = atan bθ, with<br />

a ≠ 0, b > 0, and θ in radians has the following<br />

properties:<br />

• one cycle occurs in the interval – ≠<br />

2b to ≠<br />

2b .<br />

• the period of the function is ≠ b .<br />

• there are vertical asymptotes between each repeated<br />

cycle of the graph.<br />

Example 3 Graphing Tangent Functions<br />

Graph the function y = tan πθ over the interval –1.5 ≤ θ ≤ 1.5.<br />

Solution<br />

Because b = π, the period of the function is ≠ =1 and one cycle occurs in<br />

the interval −<br />

π<br />

= −<br />

1<br />

to ≠ 2π<br />

2<br />

=<br />

1. So there will be a vertical asymptote at<br />

2≠<br />

2<br />

x = − 1 2 , x = 1 , and at each additional unit. Choose appropriate scales for<br />

2<br />

the horizontal and vertical axes and graph the function.<br />

Ongoing Assessment<br />

Graph the function y = tan ≠ θ over the interval –6 ≤ θ ≤ 6.<br />

4<br />

458 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Activity<br />

Using a Graphing Calculator<br />

A graphing calculator can be used to graph trigonometric functions such<br />

as the sine, cosine, and tangent functions. A graphing calculator will also<br />

graph the reciprocal functions: cosecant, secant, and cotangent.<br />

1 Enter y = 1/sin x in the function list on a graphing calculator. Use<br />

the ZTRIG key to set up horizontal axes that are spaced every 90°<br />

or ≠ radians. Graph the function.<br />

2<br />

2 Delete the function from Step 1 and enter y = 1/cos x in the<br />

function list. Then graph the function.<br />

3 Delete the function from Step 2 and enter y = 1/tan x in the<br />

function list. Then graph the function.<br />

4 Recall that these functions are the reciprocals of the basic<br />

trigonometric functions. For example, csc x = 1 sin x<br />

. Clear the<br />

calculator screen and plot the graphs of y = sin x and<br />

y = csc x at the same time. What do you notice about the<br />

cosecant graph at the points where y = 0 in the sine graph<br />

Explain why this occurs.<br />

Lesson Assessment<br />

Think and Discuss<br />

1. What is the range of the sine function, y = sin θ What is the<br />

amplitude of the function<br />

2. How many degrees is it before the graph of the cosine function<br />

begins to repeat How many radians<br />

3. Compare and contrast the graphs of the sine function and the<br />

cosine function.<br />

4. What happens to the graph of y = sin θ if the equation is<br />

changed to y = 2sin θ<br />

5. What happens to the graph of y = tan θ if the equation is<br />

changed to y = tan 2θ<br />

<strong>10</strong>.4 Graphing Trigonometric Functions 459


Practice and Problem Solving<br />

Identify the amplitude, period, and number of cycles in the<br />

interval from 0 to 2π for each trigonometric function. (Assume<br />

that θ is given in radians.)<br />

6. y = 1.5sin 2θ 7. y = 4cos θ<br />

8. y = –2sin θ 9. y = 3cos θ 2<br />

<strong>10</strong>. y = 0.2cos 0.2θ 11. y = –1.5sin θ 3<br />

12. y = 3sin (θ + π) 13. y = cos ( θ − π )<br />

1 2 2 2<br />

Identify the period and the location of two vertical asymptotes<br />

for each function. (Assume that θ is given in radians.)<br />

14. y = tan 2θ 15. y = 3tan θ<br />

1<br />

2<br />

1<br />

3<br />

16. y = 7.5tan θ 2<br />

17. y = 2tan (θ + π)<br />

Graph each trigonometric function over the specified domain.<br />

18. y = 2cos 2θ, 0 ≤ θ ≤ 2π 19. y = sin 2θ, 0 ≤ θ ≤ 360°<br />

20. y = tan 2θ, –180° ≤ θ ≤ 180° 21. y = 2cos θ, –2π ≤ θ ≤ 2π<br />

22. y = tan ≠ θ, –4.5 ≤ θ ≤ 4.5 23. y = –1.5sin θ, –2π ≤ θ ≤ 2π<br />

3<br />

24. Sounds traveling through the air can be modeled by sine waves.<br />

The sound of a car horn can be represented by the function<br />

y = 8sin 160θ.<br />

a. The loudness of a sound is related to the<br />

amplitude of its sound wave. Write a new<br />

function for a sound that is twice as loud as<br />

the car horn.<br />

b. Sounds are caused by vibrations. When an<br />

object vibrates twice as fast, it produces<br />

a sound with a pitch that is one octave<br />

higher. The period of the sound wave is half<br />

the original period. Write a new function<br />

for a sound that is the same loudness as<br />

the car horn, but one octave higher.<br />

c. Graph the function modeling the sound of the car horn over<br />

the interval 0 ≤ θ ≤ 0.1.<br />

460 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


25. The function y = 3sin ≠ t models the position of a fishing boat on<br />

4<br />

the ocean relative to sea level. The independent variable t is given<br />

in seconds, and the dependent variable y is given in feet above or<br />

below sea level.<br />

a. Graph the trigonometric function for values of θ between<br />

0 and 12 seconds.<br />

b. How long does it take the boat to complete one full cycle as it<br />

rides the waves of the ocean<br />

c. What is the amplitude of the function What is the physical<br />

interpretation of this value<br />

d. How would the equation of the function change if the boat<br />

were riding on a 4-foot wave y = 4 sin π t<br />

Mixed Review<br />

Determine if each sequence is arithmetic. If so, state the<br />

common difference of the sequence.<br />

26. 4, 12, 20, 28, 36, …<br />

27. 1, 2, 4, 7, 11, …<br />

Find the area of each triangle. Round your answers to the<br />

nearest tenth if necessary.<br />

28.<br />

4<br />

29.<br />

30. A cereal box has a width of 2x inches, a length of 4x + 1 inches,<br />

and a height of 6x + 1 inches. Write an expression for the<br />

volume of the box. Then find the volume of the cereal box if<br />

x = 1.5 inches.<br />

<strong>10</strong>.4 Graphing Trigonometric Functions 461


Lesson <strong>10</strong>.5 The Law of Sines<br />

and Law of Cosines<br />

Objectives<br />

Use the Law of Sines to<br />

solve for missing sides<br />

and/or angle measures<br />

in triangles.<br />

Find the area of triangles.<br />

The sine ratio is used to find missing side lengths in right triangles when<br />

at least one angle measure and one side length is known. However, this<br />

ratio cannot be used in triangles that are not right triangles.<br />

For any triangle ABC, if a, b, and c represent the side lengths opposite<br />

angles A, B, and C, respectively, then the Law of Sines states that<br />

sin A<br />

=<br />

sin B<br />

=<br />

sin C .<br />

a b c<br />

Finding Side Lengths Using the Law of Sines<br />

462 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

The Law of Sines can be used to find missing side lengths<br />

of triangles. It can be used to find missing side lengths in both right<br />

triangles and non-right triangles when two of the angle measures and<br />

at least one of the side lengths is known.<br />

Example 1<br />

Finding the Side Length<br />

of a Triangle<br />

In LMN, m∠L = 59°, m∠M = 45°, and MN = 12 yards. Find the<br />

length of LM to the nearest tenth.<br />

Solution<br />

Draw and label LMN.<br />

Find the measure of ∠N.<br />

m∠N = 180° – 59° – 45° = 76°<br />

Use the Law of Sines to solve for LM.<br />

sin59° sin 76°<br />

=<br />

12 LM<br />

12sin<br />

76°<br />

LM =<br />

sin59°<br />

LM ≈ 13.<br />

6<br />

Side LM is about 13.6 yards long.


Ongoing Assessment<br />

In PQR, m∠P = 35°, m∠R = 78°, and PQ = 9.5 in. Find the length of PR<br />

to the nearest tenth. 8.9 in.<br />

Finding Angle Measures Using the Law of Sines<br />

The Law of Sines can also be used to find missing angle measures in<br />

right triangles and non-right triangles. Sufficient information must be<br />

provided about the triangle so that a proportion with only one variable can<br />

be formulated.<br />

Example 2<br />

Finding the Angle Measure of a Triangle<br />

In RST, m∠R = 62°, RS = 14 meters, and ST = 16 meters. Find m∠T to<br />

the nearest tenth.<br />

Solution<br />

Draw and label LMN.<br />

Use the Law of Sines to solve for m∠T.<br />

sin<br />

−1<br />

sin 62° sin x°<br />

=<br />

16 14<br />

14sin<br />

62°<br />

= sin x°<br />

16<br />

⎛14sin<br />

62°<br />

⎞ −1<br />

⎜<br />

sin<br />

⎝ 16 ⎟ = (sin x°<br />

)<br />

⎠<br />

50.<br />

6°≈x<br />

The measure of ∠T is approximately 50.6°.<br />

Ongoing Assessment<br />

In MNO, m∠M = 83°, MN = 8 in., and NO = <strong>10</strong> in. Find m∠O to the<br />

nearest tenth. 52.6°<br />

Critical Thinking In Example 2, how could m∠S be found After finding<br />

m∠T, subtract m∠R and m∠T from 180° to find m∠S.<br />

<strong>10</strong>.5 The Law of Sines and Law of Cosines 463


Finding Area Using the Law of Sines<br />

An oblique triangle is any triangle that does not contain a right angle. In<br />

an oblique triangle with sides a, b, and c, the height of the triangle can be<br />

found by h = csin A, h = asin B, or h = bsin C. So the area, K, of the triangle<br />

can be found using the equations K = 0.5(bc)(sin A), K = 0.5(ac)(sin B), or<br />

K = 0.5(ab)(sin C).<br />

Example 3<br />

Finding the Area of a Triangle<br />

Find the area of ABC. Round to the nearest tenth.<br />

Solution<br />

Use the expression for the area of an oblique triangle. In the triangle, c = 22,<br />

a = <strong>10</strong>, and m∠B = 25°.<br />

K = 0.5(ac)(sin B)<br />

K = 0.5(<strong>10</strong>)(22)(sin 25°)<br />

K ≈ 46.5<br />

The area of ABC, rounded to the nearest tenth, is 46.5 ft 2 .<br />

Ongoing Assessment<br />

Find the area of XYZ. Round to the<br />

nearest tenth. 87.6 cm 2<br />

464 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Activity<br />

Ambiguous Cases<br />

Two triangles that have a<br />

congruent angle and two pairs<br />

of congruent sides are not<br />

necessarily congruent as shown<br />

below. The Law of Sines can be<br />

used to find the missing angle<br />

measures for both triangles.<br />

1 Use the Law of Sines to express the relationship between<br />

∠A and ∠B. sin43<br />

° = sin B<br />

16 20<br />

2 Solve the equation from Step 1 for m∠B. Round your answer to<br />

the nearest tenth. 58.5°<br />

3 The sine function is positive in Quadrant I and II. Therefore,<br />

another value for m∠B can be found by subtracting the answer<br />

from Step 2 from 180°. Find another value for m∠B. 121.5°<br />

4 Find the other missing angle measures in the two triangles.<br />

Express the angles of the two triangles that satisfy the given<br />

conditions and the Law of Sines. Blue triangle: 43°, 58.5°, 78.5°;<br />

Orange triangle: 43°, 121.5°, 15.5°<br />

For any triangle ABC, if a, b, and c represent the side lengths opposite<br />

angles A, B, and C, respectively, then the Law of Cosines states that<br />

a 2 = b 2 + c 2 – 2bccos A,<br />

b 2 = a 2 + c 2 – 2accos B, and<br />

c 2 = a 2 + b 2 – 2abcos C.<br />

The Law of Cosines can be used to find missing measurements in triangles<br />

when the measures of two sides and the angle between them are known or<br />

when the measures of all three sides are known.<br />

<strong>10</strong>.5 The Law of Sines and Law of Cosines 465


Finding Side Lengths Using the Law of Cosines<br />

Example 4<br />

466 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

Finding the Side Length of a Triangle<br />

Reggie wants to know the distance between the items located at B and C<br />

for the scavenger hunt. If AB = 150 yards, AC = 220 yards, and m∠A = 48°,<br />

what is the distance between the items located at B and C<br />

Solution<br />

Sketch the locations of the scavenger hunt items to model the problem.<br />

Use the Law of Cosines to solve for BC. The measures of ∠A, b, and c are<br />

known. Solve for a.<br />

a 2 = b 2 + c 2 – 2bccos A<br />

a 2 = (220) 2 + (150) 2 – 2(220)(150)(cos 48°)<br />

a 2 ≈ 26,737.4<br />

a ≈ 163.5<br />

The distance between the items is approximately 163.5 yards.<br />

Finding Angle Measures<br />

Example 5<br />

Finding the Angle Measures<br />

of a Triangle<br />

Find m∠A in the triangle. Round your answer to the nearest tenth.<br />

Solution<br />

The measure of ∠A cannot be solved directly. The Law of Cosines can be<br />

used to solve for b, the length of side AC.<br />

b 2 = a 2 + c 2 – 2accos B<br />

b 2 = (30) 2 + (15) 2 – 2(30)(15)(cos 75°)<br />

b 2 ≈ 892.1<br />

b ≈ 29.9<br />

Now the lengths a, b, c, and m∠B are known. Use the Law of Sines to solve<br />

for m∠A.<br />

sin 75ϒ =<br />

sin A<br />

29.<br />

9 30<br />

0.96916 ≈ sin A<br />

sin –1 0.96916 ≈ sin –1 (sin A)<br />

75.7° ≈ A<br />

The measure of ∠ A, rounded to the nearest tenth, is 75.7°.


Lesson Assessment<br />

Think and Discuss<br />

see margin<br />

1. Explain how the Law of Sines relates the angles of a triangle to<br />

the sides of the triangle.<br />

2. Two angle measures of a triangle and the length of a side<br />

opposite one of the angles are known. Explain how to find the<br />

unknown angle measure and the other side lengths.<br />

3. Is it possible to use the Law of Sines if you only know the three<br />

side lengths of a triangle Is it possible to use the Law of Cosines<br />

if you only know the three side lengths of a triangle Explain.<br />

4. In triangle ABC, what happens to the Law of Cosines if<br />

m∠C = 90º Explain.<br />

Practice and Problem Solving<br />

Use triangle ABC to find the indicated side length. Round your<br />

answers to the nearest tenth if necessary.<br />

5. Find a if m∠A = 78º, m∠C = 63º, and c = 12. 13.2<br />

6. Find b if m∠B = 55º, m∠A = 80º, and a = 7.6. 6.3<br />

7. Find c if m∠A = 74º, m∠C = 65º, and a = 22. 20.7<br />

8. Find b if m∠B = 60º, m∠C = 50º, and c = 30. 33.9<br />

Use triangle RST to find the indicated angle measure. Round<br />

your answers to the nearest tenth if necessary.<br />

9. Find m∠R if s = 13, r = 9, and m∠S = 52º. 33.1º<br />

<strong>10</strong>. Find m∠T if r = <strong>10</strong>, t = 6, and m∠R = 65º. 32.9º<br />

11. Find m∠S if r = 20, s = 14, and m∠R = 80º. 43.6º<br />

12. Find m∠T if s = 6.1, t = 4.3, and m∠S = 12.5º. 8.8º<br />

<strong>10</strong>.5 The Law of Sines and Law of Cosines 467


Use triangle ABC to find the indicated side length. Round your<br />

answers to the nearest tenth if necessary.<br />

13. Find a if m∠ A = 81º, b = <strong>10</strong>, and c = 8. 11.8<br />

14. Find b if m∠B = 64º, a = 7, and c = 4. 6.4<br />

15. Find c if m∠C = 29º, a = 9, and b = 7. 4.4<br />

16. Find b if m∠B = 50º, a = <strong>10</strong>.4, and c = 16.7. 12.8<br />

Use triangle ABC to find each indicated angle measure. Round<br />

your answers to the nearest tenth if necessary.<br />

17. Find m∠B if a = 13, b = 9, and c = 8. 43.0º<br />

18. Find m∠ A if a = 6, b = 4, and c = 8. 46.6º<br />

19. Find m∠C if a = 18, b = 15, and c = 12. 41.4º<br />

20. Find m∠ A if a = 4.6, b = 7.1, and c = <strong>10</strong>.2. 23.0º<br />

21. A hiking group built a bridge across a ravine from point P to<br />

point Q. A diagram is shown at the left. What is the length, x, of<br />

the bridge Round your answer to the nearest tenth if necessary.<br />

25.7 yd<br />

22. Use the Law of Sines to estimate the distance, d, across the river.<br />

Round your answer to the nearest tenth if necessary. 41.5 m<br />

468 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


23. Two points in a forest, A and B, are separated by a lake.<br />

A forest ranger draws a baseline AC on one side of the lake so<br />

that AC = 140 meters. He then uses surveying equipment to<br />

determine that m∠A = 72° and m∠C = 50°. What is the distance<br />

from point A to B across the lake Round your answer to the<br />

nearest tenth if necessary. 126.5 m<br />

24. The Great Pyramid at Giza has four triangular faces with the<br />

dimensions shown. What is the area of one of the pyramid’s<br />

faces Round your answer to the nearest square meter. 16,809 m 2<br />

25. A boat racing course is shaped like a triangle with a<br />

36º angle between two legs that measure 5.2 kilometers and<br />

4.9 kilometers. What is the length of the third leg of the course<br />

Round your answer to the nearest tenth if necessary.<br />

3.1 km<br />

26. The lengths of the sides of a triangular sheet of metal are<br />

4.5 inches, 5.2 inches, and 3.8 inches. What is the measure of<br />

the largest angle of the sheet of metal Round your answer to the<br />

nearest tenth if necessary. 77.1º<br />

27. How many square feet of material were used to build the front<br />

face of the tent shown below Round your answer to the nearest<br />

tenth if necessary. 78.1 ft 2<br />

<strong>10</strong>.5 The Law of Sines and Law of Cosines 469


28. A surveyor wants to estimate the height of a mountain peak. She<br />

locates two observation points, A and B, 4,456 yards apart at the<br />

base of the mountain. From point A, the angle of elevation to<br />

the peak of the mountain, C, is 23º. From point B, the angle of<br />

elevation is 35º. What is the height of the mountain peak to the<br />

nearest yard 4,803 yd<br />

29. Two tanker ships leave a port at the same time. The first ship<br />

plots a course 28º north of due west and travels at a rate of<br />

12.6 nautical miles per hour. The second ship plots a course<br />

7º south of due west and travels at a rate of <strong>10</strong>.2 nautical<br />

miles per hour.<br />

a. How far has each ship traveled after 2.5 hours Sketch a<br />

diagram to model their positions after 2.5 hours.<br />

31.5 nautical miles and 25.5 nautical miles; see margin for diagram<br />

b. What is the distance between the two tanker ships after<br />

2.5 hours Round your answer to the nearest tenth.<br />

18.1 nautical miles<br />

Mixed Review<br />

Find all possible rational roots using the Rational Root Theorem.<br />

30. x 3 – 4x 2 + 2x + 3 ±3, ±1<br />

31. 2x 4 + 8x 3 – x 2 – x + 12 ±12, ±6, ±4, ±3, ±2, ±1<br />

32. The wheels on Jason’s bicycle have a diameter of 20 inches. There<br />

are several spokes evenly spaced along the wheel. If the central<br />

angle between each pair of neighboring spokes is 22.5°, what is<br />

the arc length of the wheel between each pair of spokes Round<br />

to the nearest tenth. 3.9 in.<br />

470 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Lesson <strong>10</strong>.6 Verifying Trigonometric<br />

Identities<br />

Objectives<br />

Simplify a<br />

trigonometric<br />

expression.<br />

Verify a<br />

trigonometric<br />

identity.<br />

Trigonometric Identities<br />

The following trigonometric identities can be used to simplify<br />

expressions. These are equations that are true for all values of θ for<br />

which the expressions on each side of the equation are defined.<br />

Reciprocal Identities<br />

csc θ = 1 sec θ = 1 cot θ =<br />

1<br />

sin θ<br />

cos θ<br />

tan θ<br />

Tangent and Cotangent Identities<br />

sin θ<br />

cos θ<br />

tan θ = cot θ =<br />

cos θ<br />

sin θ<br />

Pythagorean Identities<br />

cos 2 θ + sin 2 θ = 1 1+ tan 2 θ = sec 2 θ<br />

1+ cot 2 θ = csc 2 θ<br />

Example 1 Simplifying a Trigonometric Expression<br />

Simplify the expression cos θ + sin θ tan θ.<br />

Solution<br />

Use the identity tan θ = sin θ<br />

cos θ .<br />

cosθ + sin θtan<br />

θ<br />

⎛ sin θ ⎞<br />

cosθ<br />

+ sin θ⎜<br />

cos θ ⎟<br />

⎝ ⎠<br />

2<br />

cos θ +<br />

sin θ<br />

cos θ<br />

⎛ 1 ⎞<br />

Multiply the expression by 1 in the form of ⎜ cos θ<br />

⎝ cos θ ⎟ .<br />

⎠<br />

⎛<br />

cos θ<br />

1 ⎞<br />

2<br />

cos θ<br />

sin θ<br />

⎜<br />

⎝ cos θ ⎠<br />

⎟ ⎛<br />

+ ⎞<br />

⎜ cos θ ⎟<br />

⎝<br />

⎠<br />

1 2 2<br />

(cos θ + sin θ)<br />

cos θ<br />

Because of the Pythagorean Identity cos 2 θ + sin 2 θ = 1, the result is<br />

1<br />

= sec θ.<br />

cos θ<br />

Ongoing Assessment<br />

Simplify the expression sin θ sec θ cot θ. 1<br />

<strong>10</strong>.6 Verifying Trigonometric Identities 471


Trigonometric expressions can also be simplified to verify trigonometric<br />

identities. When verifying an identity, you should transform one side of the<br />

equation until it is identical to the other side of the equation. Although there<br />

are no universal strategies for verifying trigonometric identities, it is often<br />

helpful to transform the more complicated side into the less complicated side.<br />

Example 2<br />

Verifying a Trigonometric Identity<br />

Verify the Pythagorean Identity 1 + cot 2 θ = csc 2 θ.<br />

Solution<br />

Use the identity cot θ = cos θ<br />

to rewrite the Pythagorean Identity.<br />

sin θ<br />

2<br />

1+ = 1+ ⎛ ⎝ ⎜ cos θ ⎞<br />

cot θ<br />

sin θ ⎟<br />

⎠<br />

2<br />

= 1+<br />

cos θ<br />

2<br />

sin θ<br />

Multiply the expression by 1 in the form of<br />

2<br />

sin θ<br />

2<br />

2<br />

= sin θ<br />

1<br />

( )( 1+<br />

cos θ<br />

2<br />

2<br />

sin θ sin θ )<br />

=<br />

1 2 2<br />

(sin θ + cos θ)<br />

2<br />

sin θ<br />

=<br />

1<br />

() 1<br />

2<br />

sin θ<br />

= csc 2 θ<br />

Ongoing Assessment<br />

2<br />

( )<br />

1<br />

2<br />

sin θ<br />

Verify the Pythagorean Identity 1 + tan 2 θ = sec 2 θ. see margin<br />

and simplify.<br />

Activity 1<br />

Proving a Pythagorean Identity<br />

Prove cos 2 θ + sin 2 θ = 1. see margin<br />

1 The Pythagorean Theorem states that a 2 + b 2 = c 2 , which can<br />

be written as opposite 2 + adjacent 2 = hypotenuse 2 . Divide the<br />

equation opposite 2 + adjacent 2 = hypotenuse 2 by hypotenuse 2 .<br />

2 Simplify your answer to Step 1. Recall, sine =<br />

cosine =<br />

adjacent<br />

hypotenuse .<br />

opposite<br />

hypotenuse and<br />

472 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Activity 2<br />

Using the Pythagorean Identity<br />

to Find Trigonometric Values<br />

Let cosθ = 4 and θ be in quadrant IV. Find sinθ and tanθ.<br />

5<br />

1 Complete the table using in the Pythagorean Identity.<br />

Step<br />

cos 2 θ + sin 2 θ = 1<br />

Reason<br />

Pythagorean Identity<br />

2<br />

⎛4⎞<br />

⎝⎜<br />

5⎠⎟ + sin2 θ = 1 Substitute 4 5<br />

for cos θ.<br />

16<br />

25 + sin2 θ = 1 Simplify the exponent.<br />

sin 2 θ = 9 25<br />

Subtract 16<br />

25<br />

from both sides.<br />

sin θ = 3 5<br />

Take the square root of both sides.<br />

2 Determine whether sine is positive or negative in quadrant IV.<br />

sin is negative in quadrant IV.<br />

3 Find sin θ in quadrant IV. sin θ = − 3 5<br />

4 Find tan θ in quadrant IV. Show your work. see margin<br />

Lesson Assessment<br />

Think and Discuss<br />

see margin<br />

1. Give an example of a trigonometric identity that is equal to 1.<br />

2. How can sin θ be expressed in terms of cos θ<br />

3. What does it mean for a trigonometric equation to be a<br />

trigonometric identity<br />

4. Which trigonometric function is the reciprocal of the<br />

sine function<br />

5. Create a trigonometric identity of your own by beginning with a<br />

simple trigonometric expression and working backward.<br />

<strong>10</strong>.6 Verifying Trigonometric Identities 473


Practice and Problem Solving<br />

Simplify each expression.<br />

6. 1 – cos 2 θ sin 2 θ 7. tan θ cos θ sin θ<br />

8. sin 2 θ sec θ csc θ tan θ 9. sin 2 θ + tan 2 θ + cos 2 θ sec 2 θ<br />

<strong>10</strong>. (1 + cot 2 θ)(sec θ) csc 2 θ sec θ 11. sin θ csc θ – cos 2 θ sin 2 θ<br />

12. sec θ cos θ – cos 2 θ sin 2 θ 13. sec θ cos 2 θ csc θ cot θ<br />

Verify each identity. check students’ work; see margin for samples<br />

14. cos θ tan θ = sin θ 15. tan θ (cot θ + tan θ) = sec 2 θ<br />

16. sin θ sec θ = tan θ 17. cos θ + sin θ tan θ = sec θ<br />

18. sec 2 θ = 1 + tan 2 θ 19. sec θ – sin θ tan θ = cos θ<br />

20. cos θ sin θ (cot θ + tan θ) = 1<br />

21. sin 2 θ tan 2 θ = tan 2 θ – sin 2 θ<br />

22. Let sin θ = − 7 and θ be in quadrant III. see margin<br />

25<br />

a. Find cos θ. b. Find tan θ.<br />

23. Let tan θ = − 15 and θ be in quadrant II. see margin<br />

8<br />

a. Find sin θ. b. Find cos θ.<br />

24. How can you express tan θ in terms of cos θ tan θ = ± −<br />

2<br />

1 cos<br />

θ<br />

cosθ<br />

25. How can you express cot θ in terms of csc θ cot θ = ± csc 2 θ −1<br />

26. How can you express sec θ in terms of tan θ sec θ = 2<br />

± 1+<br />

tan θ<br />

27. Mario simplified the<br />

trigonometric expression<br />

sin 2 θ sec 2 θ + 1 as<br />

shown here. What error<br />

did he make Simplify<br />

the expression. see margin<br />

2 2 2<br />

sin θsec θ + 1 = sin θ<br />

1<br />

+ 1<br />

2<br />

sin θ<br />

= 1+<br />

1<br />

= 2<br />

28. Verify the trigonometric identity csc θ tan θ = sec θ.<br />

check students’ work<br />

2 2<br />

29. Simplify the trigonometric expression cot θ − csc θ<br />

2 2<br />

tan θ − sec θ<br />

Mixed Review<br />

Write a recursive formula for each sequence.<br />

30. 7, 2, –3, –8, –13, … 31. 2, –5, 16, –47, 142, …<br />

a n<br />

a n–1<br />

a 1<br />

a n<br />

a n–1<br />

a 1<br />

474 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

. 1


Lesson <strong>10</strong>.7 Angle Sum and Difference<br />

Identities<br />

Objectives<br />

Find exact values<br />

of trigonometric<br />

expressions using<br />

sum and difference<br />

identities.<br />

Angle Sum and Difference Identities<br />

The tables below summarize the Angle Sum Identities and the<br />

Angle Difference Identities. Each of the Angle Difference Identities<br />

can be verified using Angle Sum Identities such as sin (A + (–B)).<br />

Angle Sum Identities<br />

• sin(A + B) = sin A cos B + cos A sin B<br />

• cos(A + B) = cos A cos B – sin A sin B<br />

• tan(A + B) = tan A+<br />

tan B<br />

1− tan Atan<br />

B<br />

Angle Difference Identities<br />

• sin(A – B) = sin A cos B – cos A sin B<br />

• cos(A – B) = cos A cos B + sin A sin B<br />

• tan(A – B) = tan A−<br />

tan B<br />

1+ tan Atan<br />

B<br />

Example 1 Using Angle Sum and Difference Identities<br />

Find the exact value of tan 135°.<br />

Solution<br />

It is known that tan 180° = 0 and tan 45° = 1. Because<br />

180° – 45° = 135°, the tangent difference identity can be used to find<br />

the exact value of tan 135°.<br />

tan( A−<br />

B)<br />

=<br />

tan A−<br />

tan B<br />

1+<br />

tan Atan<br />

B<br />

tan( 180°− 45°<br />

) =<br />

tan180° − tan 45°<br />

1 + (tan 180° )(tan 45°<br />

)<br />

=<br />

0−1<br />

1+<br />

( 0)()<br />

1<br />

=<br />

−1<br />

1<br />

= −1<br />

The exact value of tan 135° is –1.<br />

<strong>10</strong>.7 Angle Sum and Difference Identities 475


Ongoing Assessment<br />

Find the exact value of cos 240°. − 1 2<br />

Example 2<br />

Using Angle Sum and<br />

Difference Identities<br />

Find the value of the expression sin 1<strong>10</strong>° cos 65° – cos 1<strong>10</strong>° sin 65°.<br />

Solution<br />

Use the angle difference identity sin(A – B) = sin A cos B – cos A sin B to<br />

evaluate the expression.<br />

sin(A – B) = sin A cos B – cos A sin B<br />

sin(1<strong>10</strong>° – 65°) = sin 1<strong>10</strong>° cos 65° – cos 1<strong>10</strong>° sin 65°<br />

sin(1<strong>10</strong>° – 65°) = sin 45° =<br />

2<br />

2<br />

So sin 1<strong>10</strong>° cos 65° – cos 1<strong>10</strong>° sin 65° =<br />

Ongoing Assessment<br />

2<br />

2 .<br />

Find the value of the expression sin 160° cos 1<strong>10</strong>° + cos 160° sin 1<strong>10</strong>°. –1<br />

Lesson Assessment<br />

Think and Discuss<br />

see margin<br />

1. Is sin (A + B) = sin A + sin B If not, give a counterexample.<br />

2. Is cos (A + B) = cos A + cos B If not, give a counterexample.<br />

3. What expression is equal to sin (A – B)<br />

4. Explain how to use a difference identity to find the exact value of<br />

sin 142° cos 112° – cos 142° sin 112°.<br />

5. Explain how to use mental math and a sum identity to find the<br />

exact value of cos 71° cos 19° – sin 71° sin 19°.<br />

476 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Practice and Problem Solving<br />

Use a sum or difference identity to find the exact value of<br />

each expression.<br />

6. sin 150° 1 2<br />

7. cos 120° – 1 2<br />

8. tan 135° –1 9. cos 300° 1 2<br />

<strong>10</strong>. tan 225° 1 11. cos 135° − 2<br />

2<br />

12. tan 15° 2− 3 13. sin 225° − 2<br />

2<br />

14. tan <strong>10</strong>5° − 3−2<br />

15. sin 390° 1 2<br />

16. cos 33° cos 27° – sin 33° sin 27° 1 2<br />

17. sin 156° cos 66° – cos 156° sin 66° 1<br />

18. cos 58° cos 13° + sin 58° sin 13°<br />

2<br />

2<br />

19. sin 22° cos 8° + cos 22° sin 8° 1 2<br />

tan31°+ tan 14°<br />

20.<br />

1− tan31° tan 14° 1<br />

Write each expression as a trigonometric function of a single<br />

angle measure.<br />

21. sin 3θ cos 2θ + cos 3θ sin 2θ sin 5θ<br />

22. cos 4θ cos 2θ – sin 4θ sin 2θ cos 6θ<br />

23. sin 2θ cos θ – cos 2θ sin θ sin θ<br />

24. cos 3θ cos θ + sin 3θ sin θ cos 2θ<br />

25.<br />

tan3θ<br />

− tan θ<br />

1+tan3θ<br />

tan θ<br />

tan 2θ<br />

26. Use a graphing calculator to graph the function y = sin x and<br />

y = (sin x + 30) on the same coordinate grid. Use the interval<br />

0° ≤ x ≤ 360°.<br />

a. Describe the graphs of the functions. see margin<br />

b. For what value(s) of x in the interval 0° ≤ x ≤ 360° are the<br />

functions equal x = 75°, 255°<br />

<strong>10</strong>.7 Angle Sum and Difference Identities 477


27. The figure at the right shows<br />

a Ferris Wheel with a radius of<br />

26 feet. Point A represents a<br />

30° rotation of the wheel from<br />

its starting position. Point B<br />

represents an additional θ°<br />

rotation of the Ferris Wheel.<br />

a. The x-coordinate of point B<br />

is 26 cos (θ + 30°). Use an<br />

angle sum identity to write<br />

this expression in terms of<br />

cos θ and sin θ. 13 3 cos θ – 13 sin θ<br />

b. The y-coordinate of point B<br />

is 26 sin (θ + 30°). Use an<br />

angle sum identity to write this<br />

expression in terms of cos θ<br />

and sin θ. 13 3 sin θ + 13 cos θ<br />

c. What are the coordinates of<br />

point B if θ = 60° (0, 26)<br />

d. What are the coordinates of<br />

point B if θ = 150° (–26, 0)<br />

Mixed Review<br />

Find the constant of variation, k, in each joint variation. Then<br />

write the joint variation equation.<br />

28. z = 30 when x = –3 and y = 5 k = –2, z = –2xy<br />

29. z = 36 when x = 2 and y = 12 k = 1.5, z = 1.5xy<br />

30. The city hall custodial staff arranged 26 chairs in the first row<br />

of a meeting room for a town meeting. Each additional row<br />

had 2 more chairs than the previous row. There were 12 rows<br />

altogether. How many chairs are in the meeting room 444<br />

478 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Lesson 13.4 Double-Angle and<br />

Half-Angle Identities<br />

Objectives<br />

Find exact values of<br />

trigonometric expressions<br />

using double-angle and<br />

half-angle identities.<br />

A radio wave is an electromagnetic wave<br />

transmitted by an antenna. Radio waves<br />

have different frequencies. When tuning<br />

a radio receiver to a specific frequency, a<br />

specific signal can be picked up. Listening<br />

to a radio station, such as 99.1 FM,<br />

“The Wave,” means that a radio station<br />

is broadcasting an FM radio signal at a<br />

frequency of 99.1 megahertz. Megahertz<br />

means “millions of cycles per second.”<br />

So “99.1 megahertz” means that the<br />

transmitter at the radio station is oscillating<br />

at a frequency of 99,<strong>10</strong>0,000 cycles per<br />

second. A transmitter at the radio station<br />

needs to evaluate sin 150° to isolate a radio<br />

frequency. What is the isolated frequency<br />

Double-Angle Identities<br />

The Double Angle Identities are special cases of the Angle Sum<br />

Identities in which A = B. If A = B, then the cos (A + A) can be<br />

expressed as cos 2A.<br />

Therefore, cos (A + A) = cos A cos A – sin A sin A<br />

= cos 2 A – sin 2 A<br />

Note that the Double-Angle Identity for cos has multiple variations.<br />

These variations can be derived using trigonometric identities.<br />

The table below summarizes the Double-Angle Identities.<br />

Double-Angle Identities<br />

• cos 2θ = cos 2 θ – sin 2 θ<br />

• cos 2θ = 2cos 2 θ – 1<br />

• cos 2θ = 1 – 2sin 2 θ<br />

• sin 2θ = 2sin θ cos θ<br />

• tan 2θ =<br />

2tan<br />

θ<br />

2<br />

1−<br />

tan θ<br />

<strong>10</strong>.8 Double-Angle and Half-Angle Identities 479


Example 1<br />

Using the Double-Angle Identity<br />

Use a double-angle identity to find the exact value of cos 240°.<br />

Solution<br />

Because sin 120° = 3<br />

2 , the identity cos 2θ = 1 – 2 sin2 θ can be used to<br />

find the exact value of cos 240°.<br />

cos 2θ = 1 – 2 sin 2 θ<br />

cos (2 • 120°) = 1 – 2(sin 120°) 2<br />

⎛<br />

cos 240° = 1 – 2⎜<br />

⎝<br />

cos 240° = 1 – 2 3 4<br />

cos 240° = − 1 2<br />

3<br />

2<br />

( )<br />

⎞<br />

⎟<br />

⎠<br />

The exact value of cos 240° is − 1 2 .<br />

Ongoing Assessment<br />

2<br />

Use a double-angle identity to find the exact value of cos 120°. − 1 2<br />

Half-Angle Identities<br />

The table below summarizes the Half-Angle Identities. The Half Angle<br />

Identities can be derived from the Double Angle Identities. As part of<br />

the derivation process, you must take the square root of both sides of the<br />

equation. Recall that you must include ± when taking the square root of both<br />

sides of an equation.<br />

Half-Angle Identities<br />

• sin<br />

A<br />

=±<br />

2<br />

• cos<br />

A<br />

=±<br />

2<br />

• tan<br />

A<br />

=±<br />

2<br />

1−<br />

cos A<br />

2<br />

1+<br />

cos A<br />

2<br />

1−<br />

cos A<br />

1+<br />

cos A<br />

When using the half-angle identities, choose the sign for each function as<br />

appropriate for the angle. For example, the sine function is positive if the<br />

terminal side of the angle lies in quadrants I or II. Otherwise, it is negative.<br />

The table at the top of the next page summarizes this concept.<br />

480 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


When Trigonometric Function Values Are Positive<br />

• The sine function is positive for angles in<br />

Quadrants I and II.<br />

• The cosine function is positive for angles in<br />

Quadrants I and IV.<br />

• The tangent function is positive for angles in<br />

Quadrants I and III.<br />

Example 2<br />

Using the Half-Angle Identity<br />

At the beginning of this lesson, a situation was presented in which a<br />

transmitter at the radio station needed to evaluate sin 150° to isolate a radio<br />

frequency. What is the isolated frequency Use a half-angle identity to find<br />

the exact value of sin 150°.<br />

Solution<br />

Because cos 300° = 1 2 , the identity sin<br />

the exact value of sin 150°.<br />

cos<br />

sin<br />

A 1−<br />

A<br />

= ±<br />

2 2<br />

cos<br />

sin<br />

300°<br />

1− 300°<br />

= ±<br />

2<br />

2<br />

A<br />

= ±<br />

2<br />

1−<br />

cos A<br />

can be used to find<br />

2<br />

Choose the positive square root since sin 150° is positive.<br />

sin<br />

300°<br />

= ±<br />

2<br />

sin<br />

300°<br />

= ±<br />

2<br />

sin<br />

300°<br />

= ±<br />

2<br />

sin<br />

300°<br />

= 1 2 2<br />

1−<br />

1 2<br />

2<br />

1<br />

2<br />

2<br />

1<br />

4<br />

The exact value of sin 150° is 1 2 . So the isolated frequency is 1 2 .<br />

Ongoing Assessment<br />

Use a half-angle identity to find the exact value of tan 150°. − 3<br />

3<br />

<strong>10</strong>.8 Double-Angle and Half-Angle Identities 481


Activity<br />

Area<br />

The front face of a tent has the measurements shown below. The area<br />

of the face can be found using the formula A = 128sin 60°.<br />

1 Use the double-angle identity sin 2θ = 2sin θ cos θ to find the<br />

exact value of sin 60°.<br />

3<br />

2<br />

2 Write an expression for the exact area of the face of the tent.<br />

64 3 ft 2<br />

3 Use a calculator to approximate the area of the face of the tent to<br />

the nearest whole number. ≈ 111 ft 2<br />

4 Verify the area for the front face of the tent by first finding the<br />

altitude for the triangle and then using the formula for the area<br />

of a triangle. see margin<br />

5 Suppose the front face of the tent was 20 feet long. What would<br />

be the surface area for the exposed portion of the tent<br />

about 862 ft 2<br />

Lesson Assessment<br />

Think and Discuss<br />

see margin<br />

1. Is sin 2A = sin A + sin A If not, give a counterexample.<br />

2. Is cos 2A = cos A + cos A If not, give a counterexample.<br />

3. In which quadrant(s) is the tangent function positive<br />

4. In which quadrant(s) is the cosine function positive<br />

482 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Practice and Problem Solving<br />

Use a double-angle or half-angle identity to find the exact value<br />

of each expression.<br />

5. cos 120° − 1 2<br />

6. sin 90° 1<br />

7. cos 90° 0 8. sin 240° − 3<br />

2<br />

9. tan 240° 3 <strong>10</strong>. sin 15° 2−<br />

3<br />

11. tan 15° 7− 4 3 12. sin 120°<br />

13. tan 300° − 3 14. cos 15°<br />

15. tan 120° − 3 16. sin 60°<br />

2<br />

3<br />

2<br />

2+<br />

3<br />

2<br />

3<br />

2<br />

17. cos 60° 1 2 18. cos 150° − 3<br />

2<br />

19. tan 60° 3 20. sin 22.5°<br />

2−<br />

2<br />

2<br />

21. cos 600° − 1 2 22. tan 22.5° 3−<br />

2 2<br />

23. cos 240° − 1 2<br />

24. cos 22.5°<br />

2+<br />

2<br />

2<br />

25. Find cos 2θ if cos θ = − 2 5 and 90° < θ < 180°. − 17<br />

25<br />

26. Find cos θ if sin θ = − 24<br />

25 and 180° < θ < 270°. − 7<br />

27. Find tan<br />

2 θ if cos θ = 4 5 and 270° < θ < 360°. 1 3<br />

25<br />

28. Find sin θ 2 if cos θ = 1 2 and 0° < θ < 90°. 1 2<br />

29. The sound waves generated by a vibrating tuning fork<br />

can be modeled by the function y = 2sin θ. If the<br />

tuning fork vibrates twice as fast, the sound<br />

will be one octave higher. This is given by<br />

the function y = 2sin 2θ. Write the<br />

function in terms of θ to model the<br />

higher octave sound waves. y = 4 sin θ cos θ<br />

30. How could the identity for cos A 2 be<br />

derived from the identity for cos 2A<br />

Show your work. see margin<br />

<strong>10</strong>.8 Double-Angle and Half-Angle Identities 483


31. How could the identity for sin A be derived from the identity for<br />

2<br />

cos A Show your work. see margin<br />

2<br />

32. When an arrow is shot from a bow,<br />

the distance that the arrow travels is<br />

a function of the initial velocity and<br />

the angle of elevation, θ. The distance<br />

can be modeled by the function<br />

v<br />

d = ( ) 0 2<br />

sinθ<br />

cos θ, where v<br />

16<br />

0<br />

is the<br />

initial velocity of the arrow, in feet per<br />

second.<br />

a. Use a double angle formula to<br />

rewrite the function in terms of the<br />

v<br />

double angle, 2θ. d = ( ) 2<br />

0<br />

sin2θ<br />

32<br />

b. What angle of elevation, θ, will<br />

maximize the distance the arrow<br />

travels for a given initial velocity<br />

Explain. see margin<br />

c. An arrow is shot with an angle of<br />

elevation of 30° and an initial velocity<br />

of 80 feet per second. How many<br />

feet will the arrow travel Round your answer to the nearest<br />

tenth. 173.2 ft<br />

Mixed Review<br />

33. In ΔPRQ, m∠P = 72°, RQ = 7 units, and PQ = 4.3 units. Find<br />

m∠R to the nearest tenth. 35.7°<br />

34. What is the height, h, of the attic in Jeremy’s house Round your<br />

answer to the nearest tenth if necessary. 12.7 ft<br />

35. Verify the trigonometric identity<br />

check students’ work; see margin for sample<br />

484 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

cscθ<br />

cos θ<br />

= 1.<br />

cot θ


Lesson <strong>10</strong>.9 Solving Trigonometric<br />

Equations<br />

Objectives<br />

Solve trigonometric<br />

equations.<br />

While trigonometric identities are true for all values of θ, most<br />

trigonometric equations are true for only certain values of θ.<br />

Trigonometric equations can be solved by collecting like terms,<br />

finding square roots, factoring, and substitution.<br />

Collecting Like Terms<br />

Example 1 Solving by Collecting Like Terms<br />

Solve 2cos θ – 1 + 3cos θ = cos θ for 0 ≤ θ < 2π.<br />

Solution<br />

Collect like terms to isolate cos θ on one side of the equation.<br />

2cos θ – 1 + 3cos θ = cos θ<br />

2cos θ – 1 + 1 + 3cos θ – cos θ = cos θ – cos θ + 1<br />

4cos θ = 1<br />

cos θ = 1 4<br />

Use the inverse cosine function and a graphing calculator to solve<br />

for θ.<br />

cos –1 (cos θ) = cos –1 1 4<br />

θ ≈ 1.32<br />

Because the cosine function is also positive in the fourth quadrant,<br />

2π – 1.32 ≈ 4.97 radians is also a solution to the trigonometric<br />

equation. The two solutions for 0 ≤ θ ≤ 2π are 1.32 and 4.97 radians.<br />

Ongoing Assessment<br />

Solve 4tan θ – 3 = 2tan θ – 2 for 0 ≤ θ < 2π.<br />

Finding Square Roots<br />

Example 2 Solving by Square Roots<br />

Solve 4sin 2 θ – 1 = 0 for 0 ≤ θ < 2π.<br />

<strong>10</strong>.9 Solving Trigonometric Equations 485


Solution<br />

Add 1 to both sides of the equation and then divide both sides by 4.<br />

4sin 2 θ – 1 + 1 = 0 + 1<br />

4sin 2 θ = 1<br />

sin 2 θ = 1 4<br />

(sin θ) 2 = 1 4<br />

Find the square root of both sides of the equation.<br />

sin θ =<br />

1<br />

4<br />

sin θ = ± 1 2<br />

Use the inverse sine function and a graphing calculator to solve for θ.<br />

sin –1 (sin θ) = sin −1 1<br />

2<br />

θ ≈ 0.52<br />

Because the sine function is also positive in the second quadrant,<br />

π – 0.52 ≈ 2.62 radians is also a solution to the trigonometric equation. The<br />

values 0.52 + π ≈ 3.66 and 2.62 + π ≈ 5.76 are also solutions to the equation.<br />

So the solutions for 0 ≤ θ ≤ 2π are 0.52, 2.62, 3.66, and 5.76 radians.<br />

Factoring<br />

Ongoing Assessment<br />

Solve –27cos 2 θ + 3 = 0 for 0 ≤ θ < 2π.<br />

Example 3<br />

Solving by Factoring<br />

Solve 4cos θ sin θ + 2sin θ = 0 for 0 ≤ θ < 2π.<br />

Solution<br />

Divide both sides of the equation by 2 and then factor sin θ from each term.<br />

4cos θ sin θ + 2sin θ = 0<br />

2cos θ sin θ + sin θ = 0<br />

sin θ (2cos θ + 1) = 0<br />

486 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Use the Zero-Product Property to set each factor equal to 0 and solve for θ.<br />

sin θ = 0 2cos θ + 1 = 0<br />

θ = 0 or θ = π cos θ = − 1 2<br />

θ = 2 ≠ 4≠<br />

3 or θ =<br />

3<br />

The four solutions of the equation are 0, π, 2 ≠ 4≠ , and<br />

3 3 radians.<br />

Ongoing Assessment<br />

Solve 3cos θ sin θ + 3sin θ = 0 for 0 ≤ θ < 2π.<br />

Quadratic Trigonometric Equations<br />

Trigonometric equations can take the form of quadratic trinomials which<br />

can be factored into two binomials. It is helpful to use a substitution process<br />

to simplify the expression prior to factoring. In other words use x in place<br />

of the trigonometric function. Once the expression has been factored, the<br />

substitution process is reversed.<br />

Example 4<br />

Solving Trigonometric Equations<br />

of Degree Two<br />

Solve tan 2 θ – 2tan θ – 3 = 0 for 0 ≤ θ < 2π.<br />

Solution<br />

Let tan θ = x.<br />

x 2 – 2x – 3 = 0<br />

(x – 3)(x + 1) = 0<br />

x = 3 or x = –1<br />

Substitute tan θ for x.<br />

tan θ = 3 or tan θ = –1<br />

Solve for θ.<br />

tan θ = 3 tan θ = –1<br />

tan –1 (tan θ) = tan –1 (3) tan –1 (tan θ) = tan –1 (–1)<br />

θ ≈ 1.25 and 4.39 θ ≈ –0.7854<br />

Because the domain of θ is 0 ≤ θ < 2π and the tangent function is positive in<br />

quadrants I and III, the second equation has solutions –0.7854 + π ≈ 2.36 and<br />

2.36 + π ≈ 5.50 radians. The solutions are 1.25, 2.36, 4.39, and 5.50 radians.<br />

Ongoing Assessment<br />

Solve sin 2 θ – 3 4 sin θ + 1 = 0 for 0 ≤ θ < 2π.<br />

8<br />

<strong>10</strong>.9 Solving Trigonometric Equations 487


As a paddle wheel spins on its axis, the height<br />

of a point on the wheel with respect to the<br />

water level can be modeled by the function<br />

h(t) = 15 – 18cos ≠t . The height above<br />

12<br />

or below the water is given in feet, and t is<br />

the amount of time in seconds. Answer the<br />

following questions to describe the paddle<br />

wheel as it spins on its axis.<br />

a. What is the diameter of the wheel<br />

b. How high above the surface of the water is<br />

the top of the wheel<br />

c. How long does it take the wheel to complete<br />

one full revolution<br />

Step 1 Understand the Problem<br />

Describe the problem situation in your own<br />

words. What information do you need to find<br />

Step 2 Develop a Plan<br />

Problem-solving strategy: Use a graph.<br />

What are suitable axis limits to graph the<br />

cosine function How will graphing the<br />

function help you answer the questions in<br />

the problem statement<br />

Step 3 Carry Out the Plan<br />

Graph the trigonometric function on a graphing<br />

calculator or on grid paper using suitable axes.<br />

Use the graph to find the diameter of the<br />

wheel, the maximum height above the surface<br />

of the water, and the amount of time it takes<br />

to complete a full revolution. Explain how you<br />

found your answers.<br />

Step 4 Check the Results<br />

Check your results to make sure they<br />

seem reasonable.<br />

Lesson Assessment<br />

Think and Discuss<br />

1. Explain how to solve the equation cos 2 θ – 1 = 0 for 0 ≤ θ < 180°.<br />

2. How many solutions are there to the equation 4 tan θ – 0.25 = 0<br />

Explain.<br />

3. If the sine of an angle is positive and one of the solutions in<br />

the interval 0 ≤ θ < 2π is known, how can the other solution<br />

be found<br />

4. How could a graphing calculator be used to find the solutions of<br />

a trigonometric equation within a particular domain<br />

488 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Practice and Problem Solving<br />

Solve each equation in the given interval. Round your answers<br />

to the nearest hundredth radian or tenth degree.<br />

5. <strong>10</strong>cos θ = –5, 0 ≤ θ < π<br />

6. 1.5tan θ + 2.5 = 0, 0 ≤ θ < 180°<br />

7. 5tan θ = 3 + 2tan θ, 0 ≤ θ < 2π<br />

8. 2sin θ – 2 = 0, 0 ≤ θ < 360°<br />

9. 3tan θ = tan θ + 1, 0 ≤ θ < 360°<br />

<strong>10</strong>. tan 2 2θ = 1, 0 ≤ θ < π<br />

11. 2sin 2 θ + 3sin θ – 2 = 0, 0 ≤ θ < 180°<br />

12. (sin θ – 1)(sin θ + 1) = 0, 0 ≤ θ < 2π<br />

13. –15cos 2 θ + 8 = 0, 0 ≤ θ < 180°<br />

14. 3sin 2 θ – 2 = 0, 0 ≤ θ < 2π<br />

15. 2sin 4 θ + sin 2 θ = 0, 0 ≤ θ < 360°<br />

16. tan 2 θ + tan θ = 0, 0 ≤ θ < 360°<br />

17. 4sin 2 θ – 4sin θ + 1 = 0, 0 ≤ θ < 360°<br />

18. 2sin 2 θ – 3sin θ – 2 = 0, 0 ≤ θ < 2π<br />

19. The number of hours of daylight during the day depends on the<br />

time of year. The hours of daylight, y, can be modeled by the<br />

( )<br />

2<br />

function y = 14 + 3cos<br />

π ( d − <strong>10</strong>0 ) , where d is the number<br />

365<br />

of days since January 1. On which day(s) are there 16.5 hours of<br />

daylight Round to the nearest whole number.<br />

20. A boat trolling through a no-wake zone of<br />

a lake produces 3-inch waves that repeat<br />

every second. This can be modeled by<br />

the equation y = 3cos 2πt, where y is the<br />

height, in inches, of the wave and t is the<br />

time, in seconds. At what times between<br />

0 and 2 seconds is the height of the wave<br />

equal to 2 inches Round to the nearest<br />

hundredth of a second.<br />

<strong>10</strong>.9 Solving Trigonometric Equations 489


21. Use a Pythagorean trigonometric identity to solve the equation<br />

4sin 2 θ + 3cos θ – 2 = 0 for 0 ≤ θ < 2π. Round your answer to<br />

the nearest hundredth.<br />

22. The height above ground level of a person riding on a Ferris<br />

Wheel can be modeled by the function h(t) = 32 – 30cos ≠t. In<br />

the function, t is the number of seconds since the ride began, 20and<br />

h(t) is the passenger’s height, in feet, above the ground.<br />

a. What are the first two times, t, that the passenger’s height<br />

above the ground is 2 feet How long does it take to make<br />

one complete revolution around the ride<br />

b. When does the passenger first reach the highest point of<br />

the ride How high above the ground is the passenger at<br />

this point<br />

23. The voltage V in the power cord of a television<br />

after t seconds can be modeled using the function<br />

V(t) = 120cos (120πt).<br />

a. Find the first time the voltage is equal to<br />

0 volts after turning the television on.<br />

b. What is the maximum voltage in the power<br />

cord at any time Find all the times at which<br />

the voltage is at its maximum.<br />

c. What is the minimum voltage in the power cord at any time<br />

Find all the times at which the voltage is at its minimum.<br />

Mixed Review<br />

Convert each angle measure from radians to degrees.<br />

4≠<br />

24.<br />

3<br />

5≠<br />

25.<br />

6<br />

7≠<br />

26.<br />

4<br />

27. The lengths of several picture frames at a department store are<br />

3.5 inches, 4.25 inches, 6 inches, and 8 inches. Do these sizes<br />

represent a geometric sequence If so, state the common ratio.<br />

490 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Math Labs<br />

Activity 1: The Circle of Your City<br />

Problem Statement<br />

A circle of latitude is the circle that is formed<br />

by a two-dimensional plane parallel to the<br />

equator intersecting a point of latitude. The<br />

equation used to calculate the circle’s radius<br />

is r = Rcos θ where r is the length of the<br />

radius of the circle of latitude, R is the length<br />

of the radius of Earth (3,960 miles) and θ<br />

is the latitude in degrees. Find the radius<br />

of the circle of latitude for any city given<br />

the city’s latitude, and explain how a city’s<br />

temperature relates to its latitude.<br />

Equipment<br />

Computer with<br />

Internet<br />

access<br />

Scientific<br />

calculator<br />

Procedure<br />

1 Choose any city in the world. Find a website where you can<br />

determine the city’s latitude. sample answer: Jacksonville, FL;<br />

latitude = 30° 19’ 55”<br />

2 If the latitude has minutes and seconds, then convert it to a<br />

decimal. Round your answer to the nearest hundredth.<br />

sample answer: latitude = 30.33°<br />

3 Find the length of the radius, to the nearest tenth, of the circle<br />

of latitude for your city. sample answer: r = 3,418.0 miles<br />

4 Choose another city in the opposite hemisphere and repeat<br />

Steps 1 through 3. sample answer: Punta Arenas, Chile; r = 2,030.7 miles<br />

5 Choose a city located on the equator. Without using the<br />

equation, find the length of the radius of the circle of latitude.<br />

Verify your answer using the equation. For any city on the equator,<br />

r = 3,960 miles.<br />

6 Draw a circle to represent the Earth. Mark the equator with<br />

its radius. see margin<br />

7 Use an arc to represent the circle of latitude for each of your<br />

chosen cities. Label the radius of each. see margin<br />

8 Write a general statement about the radius of a circle of<br />

latitude and how it relates to the temperature of a city.<br />

see margin<br />

Math Labs 491


Activity 2: The Sun Today<br />

Problem Statement<br />

Use a protractor to approximate the angle<br />

of the sun at different times during the<br />

day. Model the position of the sun in the<br />

sky with a graph. Then use your graph to<br />

predict the position of the sun in the sky at<br />

different times during the day.<br />

Equipment<br />

Clock<br />

Grid paper<br />

Level<br />

Protractor<br />

Yard sticks<br />

Procedure<br />

1 Work with a partner. At various times throughout the day (on<br />

a sunny day) go outside and use the yard sticks, level, and<br />

protractor to measure the angle of the sun with respect to a<br />

level horizon. Have your partner hold a yard stick level in the<br />

direction of the sunrise. Form an angle by pointing the other<br />

yard stick directly at the center of the sun. Hold the yard sticks as<br />

steady as possible and use the protractor to measure the angle.<br />

2 Collect data at various times during the day to complete a<br />

table such as the one shown below. see margin<br />

3 Use your protractor to draw a<br />

large semicircle on grid paper.<br />

Place markings along the<br />

semicircle at every 30° like the<br />

one shown at the left. Draw<br />

each angle from your data on<br />

the semicircle and label each<br />

corresponding time. see margin<br />

Time of<br />

Day<br />

9:00 A.M.<br />

<strong>10</strong>:00 A.M.<br />

11:00 A.M.<br />

12:00 Noon<br />

1:00 P.M.<br />

2:00 P.M.<br />

3:00 P.M.<br />

Angle of<br />

the Sun<br />

4 What was the change in the<br />

angle of the sun between 9:00 A.M. and <strong>10</strong>:00 A.M. Use<br />

your data and your graph to predict the position of the sun<br />

at 9:30 A.M. sample answer: 15°, about 52.5° off the Eastern horizon<br />

5 What was the change in the angle of the sun between noon and<br />

1:00 P.M. Use your data to predict the position of the sun at<br />

12:30 P.M. sample answer: 15°, about 97.5° off the Eastern horizon<br />

6 How do you think your data would change if it were gathered<br />

at different times during the year Answers will vary.<br />

492 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Activity 3: The Sine Curve of Biorhythms<br />

Some believe that a person’s physical, emotional, and intellectual<br />

well-being are based on cycles that model sine curves. This<br />

unscientific theory is based on the idea that these three cycles<br />

begin on the day one is born and throughout one’s life the three<br />

cycles have high points and low points that occasionally coincide.<br />

Problem Statement<br />

Use the Internet to locate and print a<br />

biorhythm chart based on your date of birth.<br />

Translate each of your biorhythm sine curve<br />

graphs into an equation.<br />

The equation of a sine curve is given by<br />

y – k = Asin B(x – h) where k is the vertical<br />

offset, h is the horizontal offset, A is the<br />

amplitude and B is the period. Follow the<br />

steps to transform a sine curve graph to an<br />

equation.<br />

Equipment<br />

Computer with<br />

Internet<br />

access and<br />

a printer<br />

Steps to Transform a Sine Curve to an Equation<br />

1. Find the minimum and maximum point on the y-axis and calculate<br />

the amplitude A.<br />

2. Find the period B by using the equation period length = 2≠ B where<br />

B is the period of the sine curve.<br />

3. Find the first “zero” point. This is the first point where the<br />

horizontal line midway between the minimum and maximum<br />

y values intersects the sine curve. Use this point to calculate k and h.<br />

Procedure<br />

1 Locate a website on the Internet where you can generate a<br />

personalized biorhythm chart. Print a copy of the graphs. A<br />

sample chart is shown on the next page.<br />

2 Find the minimum and maximum values of the Intellectual sine<br />

curve on the y-axis and calculate the amplitude. sample answer:<br />

A = <strong>10</strong>0<br />

3 Find the period of the Intellectual sine curve. sample answer: B = 2 29<br />

4 Estimate the “zero” point and use this coordinate to determine<br />

the values of h and k. Sample answer: h = 7, k = 0<br />

π<br />

Math Labs 493


5 Write the equation in the form y – k = Asin B(x – h) to find the<br />

equation that fits the Intellectual sine curve. see margin<br />

6 Repeat Steps 2 through 5 for the Emotional and Physical<br />

sine curves. see margin<br />

Activity 4: Swing of a Pendulum<br />

Problem Statement<br />

Use a string and a washer to create a<br />

pendulum and measure the period and<br />

amplitude of the pendulum. Model the<br />

motion of the pendulum with a periodic<br />

function and graph the function. Experiment<br />

with factors such as the length of the string<br />

and the weight of the pendulum to see how<br />

each affects the swing of the pendulum.<br />

Equipment<br />

Graphing<br />

calculator<br />

Protractor<br />

Scissors<br />

Stopwatch<br />

String<br />

Washers or<br />

other weights<br />

Procedure<br />

1 Tie one end of a string to a weight such as a washer or a nut.<br />

Cut the string to a length between 8 and 20 inches.<br />

sample string length: 15 in.<br />

2 Attach the other end of the string to a fixed point such as<br />

a coat hanger hook. You could also tie the end to a pencil<br />

and hold the pencil level against a wall to form a swinging<br />

pendulum.<br />

494 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


3 Hold a protractor upside down so that the 0° vertex is aligned<br />

with the top of the pendulum. Holding the string taut, pull<br />

the weight to one side so that you form a 30° angle with the<br />

string and its vertical resting position. Work with a partner<br />

to time how long it takes the pendulum to swing through<br />

<strong>10</strong> complete cycles. sample answer: 12.5 s<br />

4 Time the pendulum as it swings. Find the average amount of<br />

time it takes to complete one full cycle. The average time of<br />

one full cycle is the period for the function.<br />

sample answer: 1.25 s<br />

5 How far from its resting position is the weight at its extremes<br />

Calculate the arc length of the pendulum along its swing path.<br />

In terms of a periodic function, what is this distance<br />

sample answer: The amplitude is about 7.85 inches.<br />

6 Write a trigonometric function to describe the distance of the<br />

pendulum from its original resting position t seconds after it<br />

is released. sample answer: y = 785 . cos<br />

8πt<br />

7 Graph the function over a domain that includes 3 full cycles.<br />

see margin<br />

8 Experiment with different lengths of string for the pendulum.<br />

Compare the period of your pendulum with those of your<br />

classmates. How does changing the length of the string<br />

affect the period of the pendulum How does it affect<br />

the amplitude see margin<br />

9 Experiment with different pendulum weights for a fixed length<br />

of string. For example, tie a second weight or a heavier weight<br />

to the end of your string. How does changing the weight of<br />

the pendulum seem to affect the period of the pendulum<br />

How does it affect the amplitude see margin<br />

5<br />

Math Labs 495


Math Applications<br />

The applications that follow are like the ones you will encounter in many workplaces. Use the<br />

mathematics you have learned in this chapter to solve the problems. Wherever possible, use<br />

your calculator to solve the problems that require numerical answers.<br />

General<br />

Content<br />

1 A mounted van ramp is 9 feet long when fully deployed. The<br />

distance between the ground and the point directly above it where<br />

the ramp connects to the van is 2 feet.<br />

a. What is the measure of the angle in radians that the mounted<br />

side-door van ramp makes with the ground Round to the<br />

nearest tenth of a radian. 0.2 radian<br />

b. What is the measure of the angle in degrees that the mounted<br />

van ramp makes with the ground Round to the nearest tenth<br />

of a degree. 12.8°<br />

c. If the distance between the ground and the point directly above it where<br />

the ramp connects to the van is 3 feet instead of 2 feet, what will be the<br />

measure of the angle in radians that the mounted van ramp makes with the<br />

ground Round to the nearest tenth of a radian. 0.3 radian<br />

d. In order to decrease the angle the mounted van ramp makes with the<br />

ground, should the van have a shorter ramp or longer ramp longer ramp<br />

2 Grace has been chosen to be a contestant on a reality TV show. The show<br />

takes place on a circular island that has two main trails. Trail A runs from<br />

the westernmost point of the island to the easternmost point of the island.<br />

Trail B runs from the northernmost point of the island to the southernmost point<br />

on the island. Both trails are 500 miles long. At the beginning of the show, all<br />

the participants are dropped off at the center of the island. The goal of each<br />

contestant is to be the first person to arrive at the boat dock. The boat dock is<br />

located northwest of the center of the island. The angle formed by the straight<br />

line going from the center of the island directly west and the straight line going<br />

from the center of the island to the boat dock is 11 ≠ radians.<br />

60<br />

a. How far north of Trail A is the boat dock Round to the nearest tenth. 136.2 mi<br />

b. How far west of Trail B is the boat dock Round to the nearest tenth. 209.7 mi<br />

c. If Grace travels along the outermost coast of the island from the<br />

westernmost point of the island to the boat dock, how far will she have to<br />

travel Round to the nearest hundredth. 143.99 mi<br />

496 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


3 Cale, Tammie, and Allison are members of the ultimate flying disc team. The<br />

object of the game is to score points by receiving a teammate’s pass of the flying<br />

disc in the opposing team’s end zone. Players may not run when in possession<br />

of the disc. Cale had the disc and passed it to Tammie, who was 18 meters<br />

away. Tammie then passed the disc to Allison in the end zone 28 meters away.<br />

When viewing the instant replay, the statistician calculated the measured angle<br />

formed by the straight line going from Cale to Tammie and the straight line<br />

going from Tammie to Allison to be 75°. Use the facts that sine and cosine of 45°<br />

is 1 2 , the sine of 30° is 1 2 , and the cosine of 30° is 3 to find cosine 75°.<br />

2<br />

a. If the straight line distance from Cale and Allison is a and the measure of<br />

the angle formed by the straight line going from Cale to Tammie and the<br />

straight line going from Tammie to Allison is A, use the Law of Cosines to<br />

write a 2 in terms of cos A. a 2 = 1,<strong>10</strong>8 – 1,008cos A<br />

b. The angle formed by the straight line going from Cale to Tammie and the<br />

straight line going from Tammie to Allison measured 75°. What angle sum<br />

identity can the statistician use to solve for a in the equation given in the<br />

answer to part a cos (A + B) = cos A cos B – sin A sin B<br />

c. Substitute the values the statistician knows into the angle sum identity<br />

given in the answer to part b. cos (30° + 45°) =<br />

3 1 1 1<br />

• − •<br />

d. Simplify the answer given to part c to solve for the cosine of 75° to the<br />

nearest hundredth. 0.26<br />

e. Substitute the answer given in part d for cos A in the answer given in part a<br />

and solve for a, which is the straight-line distance from Cale to Allison.<br />

Round to the nearest tenth. 29.1 m<br />

2<br />

2<br />

2<br />

2<br />

Agriculture &<br />

Agribusiness<br />

4 A combine is a machine that picks, thrashes, and cleans grain<br />

while traversing a field. Avery has a reclining backrest on her<br />

combine to increase comfort. The measure of the angle formed<br />

by the combine’s seat and the reclining backrest can range from<br />

90° to 135°. The equation tan 2 θ – 6tan θ – 16 = 0 represents<br />

this situation where θ is the measure of the angle formed by the<br />

combine’s seat and the reclining backrest. Avery wants to solve for<br />

θ so she can adjust her reclining backrest to this angle in the future.<br />

a. What type of trigonometric equation does Avery have to solve<br />

to find θ quadratic<br />

b. When tan θ is substituted for x, four possible angle measures emerge.<br />

Explain why three of them can not be correct. see margin<br />

c. What is the measure of the angle formed by the reclining backrest and the<br />

seat Round to the nearest tenth degree. 116.6°<br />

Math Applications 497


5 Juan decided to place a large scarecrow in his rice patty to keep the crows from<br />

ravaging his crop. The scarecrow is 20 feet tall. The angle of the elevation from<br />

the top of the scarecrow’s shadow to the top of the scarecrow has a cosecant<br />

of 1.03.<br />

a. What is the measure of the angle of elevation from the top of the<br />

scarecrow’s shadow to the top of the scarecrow 75.9°<br />

b. What is the distance from the top of the scarecrow’s shadow to the top of<br />

the scarecrow Round to the nearest tenth of a foot. 20.6 ft<br />

c. What is the length of the scarecrow’s shadow Round to the nearest tenth<br />

of a foot. 5.0 ft<br />

Business &<br />

Marketing<br />

6 Ronaldo has a kiosk at the local mall where he sells earrings. One of Ronaldo’s<br />

customers wants to purchase a 24-carat gold-plated triangular earring.<br />

Ronaldo charges $1.75 per mm 2 of gold. Two of the sides of the earring have<br />

measurements of 11 millimeters and 12 millimeters, respectively. The angle<br />

between the two sides measures 43°. The customer has $75.<br />

a. What is the area of the 24-carat gold-plated triangular earring that the<br />

customer wants to purchase Round to the nearest tenth. 45.0 mm 2<br />

b. Does the customer have enough money to purchase the earring no<br />

7 Marissa owns a 24-hour paper-recycling plant. There always exists some paper<br />

waiting to be recycled in the plant. Marissa found the range of the amount of<br />

paper waiting to be recycled is 2 tons, with 4 tons being the most that is ever<br />

waiting to be recycled and 2 tons being the least that is ever waiting to be<br />

recycled. Marissa also found that the amount of paper waiting to be recycled,<br />

in tons, can be represented by a sine curve with an amplitude of 1 and an offset<br />

of 3, and the curve goes through 1 cycle every 360 days. The offset of a sine<br />

curve is the number of units the axis about which the sine curve is oscillating<br />

is above or below 0. On Monday at 12:00 p.m., Marissa noticed the amount of<br />

paper waiting to be recycled was 3 tons and the amount of paper waiting to be<br />

recycled was increasing.<br />

a. How many tons of paper will be waiting to be recycled at 12:00 p.m.<br />

123 days from Monday Round to the nearest tenth. 3.8 tons<br />

b. How many tons of paper will be waiting to be recycled at 12:00 p.m.<br />

206 days from Monday Round to the nearest tenth. 2.6 tons<br />

c. How many days from Monday will the amount of paper waiting to be<br />

recycled be the greatest 90<br />

d. How many days from Monday will the amount of paper waiting to be<br />

recycled be the least 270<br />

498 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


8 Bella does freelance marketing work and is designing a logo for a small cafe that<br />

offers free wireless Internet access. The company asked Bella to design a black<br />

circle with a white pie slice, as shown below.<br />

The logo has a circumference of<br />

30π centimeters and the length of the<br />

intercepted arc of the white pie slice is<br />

5π centimeters.<br />

a. What is the measure of the<br />

central angle of the white pie slice<br />

in radians see margin<br />

b. What is the measure of the central angle of the white pie slice in degrees 60°<br />

c. If Bella enlarges the logo so that the circumference of the circle is<br />

720π centimeters, will the length of the intercepted arc of the white pie<br />

slice change Will the central angle of the white pie slice change yes; no<br />

9 Byron is currently at a convenience store. He is going to drive to the soccer field.<br />

He knows that if it were possible to travel directly in a straight line from the<br />

convenience store to the soccer field, the distance would be 6.5 miles. He also<br />

knows that the angle that is formed by the straight line going directly west and<br />

the straight line going directly to the soccer field measures 30°.<br />

a. Approximately how far should Byron travel west Round to the<br />

nearest tenth. 5.6 mi<br />

b. Approximately how far should Byron travel north Round to the<br />

nearest tenth. 3.3 mi<br />

<strong>10</strong> Lola decided to rent a canopy for her graduation party. Lola drives three stakes<br />

supporting the canopy into the ground at points A, B, and C. The distance<br />

between A and B is 11 meters. The distance between A and C is 17 meters. The<br />

angle formed by the straight line going from A to B and the straight line going<br />

from A to C is 29°.<br />

a. What type of triangle is formed by the straight line going from A to B, the<br />

straight line going from A to C, and the straight line going from B to C<br />

oblique<br />

b. What is the area of the triangle that is formed by the straight line going<br />

from A to B, the straight line going from A to C, and the straight line going<br />

from B to C Round to the nearest tenth. 45.3 m 2<br />

Math Applications 499


Family &<br />

Consumer<br />

Science<br />

11 Tamika is taking rowing lessons.<br />

She is learning the term layback,<br />

which is the position of the<br />

upper body at the end of a<br />

rowing stroke. Tamika’s coach<br />

told her at the end of a rowing<br />

stroke, her upper body should<br />

be leaning slightly backward, but<br />

it should not be leaning more<br />

than <strong>10</strong>° backward from vertical.<br />

If the measure of the angle at<br />

which Tamika is leaning slightly<br />

backwards is represented by θ,<br />

then 5sin θ cos θ – 4.9sin θ = 0.<br />

Tamika wants to solve for θ so<br />

she knows whether or not she is<br />

following her coach’s instructions.<br />

a. What method can Tamika use to help solve for θ factoring<br />

b. Is Tamika following her coach’s instructions no<br />

c. If the measure of the angle at which Tamika is leaning slightly backwards is<br />

represented by θ, and <strong>10</strong>sin θ cos θ – 9.9sin θ = 0, is Tamika following her<br />

coach’s instructions yes<br />

12 The length of the diameter of Anna’s clock is 18 inches. At a given time,<br />

the central angle between the hour hand and the minute hand is 3 ≠ radians.<br />

20<br />

At a second time the central angle between the hour hand and the minute hand<br />

on the clock is 39°.<br />

a. What is the length of the intercepted arc of the hour hand and the minute<br />

hand at the first time 27 ≠ in.<br />

20<br />

b. Which is greater, the central angle between the hour hand and the minute<br />

hand at the first time or the central angle between the hour hand and the<br />

minute hand at the second time the central angle between the hour hand and the<br />

minute hand at the second time<br />

500 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Health<br />

Occupations<br />

13 Dmitri wants to make sure his keyboard is located at the correct vertical position<br />

to be ergonomically correct. Current guidelines recommend the angle formed<br />

at the elbow by the upper arm and the forearm be between 70° and 135°. If<br />

the measure of the angle formed at Dmitri’s elbow by his upper arm and his<br />

forearm when typing is represented by θ, then 45sin θ + cos θ tan θ – 42.5 = 0.<br />

Dmitri wants to calculate the value of θ so he can be sure he is adhering to<br />

current ergonomic guidelines, so he uses a trigonometric identity to simplify the<br />

trigonometric expression so he can solve the equation for θ.<br />

a. What trigonometric identity does Dmitri use to simplify the trigonometric<br />

expression on the left side of the equation sin θ<br />

tan θ =<br />

cos θ<br />

b. What is the simplified trigonometric expression on the left side of the<br />

equation after using the trigonometric identity given in the answer to<br />

part a 46sin θ – 42.5<br />

c. What is the measure of the angle that should be formed at the elbow by<br />

Dmitri’s upper-arm and the forearm 112.5°<br />

Industrial<br />

Technology<br />

14 Serena, an astronaut working on the International Space Station, is using a<br />

robotic arm used to move equipment and to service instruments attached to<br />

the station to support astronauts working in space. The arm is attached to the<br />

station at the Mobile Base System (MBS). At the end of the arm is the hand.<br />

While doing some routine maintenance, she notices the arm forms a 36° angle<br />

at 1 of its 7 motorized joints. The segment of the arm going from the MBS<br />

to the joint is 27 feet long. The segment going from the joint to the end of<br />

the hand is 43 feet long. Serena will use the Law of Cosines to calculate the<br />

distance. She knows the sine of 18° is 0.31.<br />

a. What double-angle identity should Serena use to find the distance between<br />

the MBS and the end of the hand cos 2θ = 1 – 2sin 2 θ<br />

b. What is the distance between the MBS and the end of the hand Round to<br />

the nearest tenth. 26.5 ft<br />

Math Applications 501


<strong>Chapter</strong> Review<br />

Lessons <strong>10</strong>.1 and <strong>10</strong>.2<br />

Review Examples<br />

Student Review Exercises<br />

Solve for x. Round to the nearest tenth. Use triangle ABC to find each ratio.<br />

Use the sine ratio to solve for x.<br />

sin 28ϒ=<br />

14<br />

x<br />

x =<br />

14<br />

sin 28ϒ<br />

Use a scientific calculator to evaluate sin 28°.<br />

x ≈ 29.8 in.<br />

Lessons <strong>10</strong>.3 and <strong>10</strong>.4<br />

Review Examples<br />

Solve for x. Round to the nearest tenth.<br />

1. cos B 24 2. tan A 24 25<br />

7<br />

Convert each angle measure to degrees<br />

or radians as appropriate. see margin<br />

3. 40° 4. 3 ≠ radians<br />

4<br />

5. The angle from the top of a tree to a<br />

point 60 feet from its base is 44°. What<br />

is the height of the tree Round the<br />

answer to the nearest tenth. 62.1 ft<br />

Student Review Exercises<br />

Graph each function.<br />

6. y = 2cos θ, 0 ≤ θ ≤ 2π see margin<br />

7. y = tan ≠ θ, –4.5 ≤ θ ≤ 4.5 see margin<br />

2<br />

Use the tangent ratio to write an equation.<br />

4<br />

tan x°=<br />

<strong>10</strong><br />

tan x°=<br />

04 .<br />

Use the inverse tangent function and a scientific<br />

calculator to solve for x.<br />

tan –1 (tan x°) = tan –1 0.4<br />

x = tan –1 0.4<br />

x ≈ 21.8°<br />

8. A 6-ft board is leaning against a wall<br />

so that the top of the board reaches<br />

a height of 4 feet 9 inches. What is<br />

the measure of the angle formed by<br />

the board and the ground Round the<br />

answer to the nearest tenth. 52.3º<br />

502 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Lessons <strong>10</strong>.5 and <strong>10</strong>.6<br />

Review Examples<br />

Find the length, x, of the bridge across<br />

the ravine.<br />

Student Review Exercises<br />

Use the Law of Sines or the Law of<br />

Cosines to find each measure. Round to<br />

the nearest tenth.<br />

Find the missing angle of the triangle.<br />

180º – <strong>10</strong>8º – 40º = 32º<br />

Apply the Law of Sines.<br />

sin 32° sin 40°<br />

=<br />

18 x<br />

18sin<br />

40°<br />

x =<br />

sin 32°<br />

x ≈ 21.8 yd<br />

Lessons <strong>10</strong>.7, <strong>10</strong>.8, and <strong>10</strong>.9<br />

Review Examples<br />

Find the exact value of cos <strong>10</strong>5°.<br />

Write <strong>10</strong>5° as 45° + 60° and use the angle sum<br />

identity cos(A + B) = cos A cos B – sin A sin B.<br />

cos<strong>10</strong>5° =cos 45° • cos60° − sin 45° • sin 60°<br />

=<br />

2 1 2 3<br />

• − •<br />

2 2 2 2<br />

=<br />

2<br />

−<br />

6<br />

4 4<br />

=<br />

2−<br />

6<br />

4<br />

9. Find c if m∠C = 35º, a = 6, and b = 8. 4.6<br />

<strong>10</strong>. Find m∠B if a = 18, b = 13, and<br />

m∠A = 67º. 41.7º<br />

11. Verify the trigonometric identity<br />

sin θ tan θ =<br />

1<br />

– cos θ.<br />

cos θ<br />

Check students’ work; see margin for sample<br />

12. The lengths of the sides of a triangular<br />

garden are 18 feet, 14 feet, and <strong>10</strong> feet.<br />

What is the measure of the largest angle<br />

of the garden Round to the nearest<br />

tenth. 95.7º<br />

Student Review Exercises<br />

Find the exact value of each expression.<br />

13. tan <strong>10</strong>5° − 3−2<br />

14. sin 75° 2+<br />

6<br />

4<br />

15. sin 15° 6 − 2<br />

4<br />

16. cos 300° 1 2<br />

Solve each equation.<br />

17. tan 2 θ – tan θ = 0, 0 ≤ θ < 2π 0, ≠ , ≠ ,<br />

5<br />

4<br />

18. sin 2 θ – 1 = 0, 0 ≤ θ < 360° 90°, 270°<br />

≠<br />

4<br />

19. sin 2 θ – 1 = cos 2 θ, 0 ≤ θ < 2π ≠ ,<br />

3 ≠<br />

2<br />

2<br />

<strong>Chapter</strong> Review 503


<strong>Chapter</strong> Test<br />

Solve each problem.<br />

1. Solve for x. Round to the nearest tenth.<br />

53.6 m<br />

2. Convert 70° to radians. 7 ≠<br />

18<br />

3. Convert 3 ≠ radians to degrees. 54°<br />

<strong>10</strong><br />

Graph each function over the specified<br />

domain. see margin<br />

4. y = 3sin θ, 0 ≤ θ ≤ 2π<br />

5. y = –1.5cos 2θ, –2π ≤ θ ≤ 2π<br />

Use the Law of Sines or the Law of<br />

Cosines to find each measure. Round to<br />

the nearest tenth.<br />

14. Find b if m∠B = 52º, m∠C = 31º,<br />

and c = 12. 18.4<br />

15. Find m∠A if a = 13.5, b = 9.4,<br />

and c = 16.3. 55.9º<br />

Solve each equation in the given interval.<br />

16. sin 2 θ – 2sin θ – 3 = 0, 0 ≤ θ < 360°<br />

270°<br />

17. 2sin θ + 1 = csc θ, 0 ≤ θ < 2π ≠ ,<br />

5 ≠ ,<br />

3 ≠<br />

18. Find the area of triangle ABC below.<br />

Round to the nearest whole number.<br />

38 cm 2<br />

6<br />

6<br />

2<br />

Find each function value. Round to the<br />

nearest tenth.<br />

6. g(θ) = <strong>10</strong> – 4sin θ, θ = 35º 7.7<br />

7. y = –2.5tan x 2 , x = 2 ≠ –4.3<br />

3<br />

Solve for x. Round to the nearest tenth<br />

degree or thousandth radian.<br />

8. sin x = 0.96, –90º ≤ x ≤ 90º 73.7º<br />

9. cos x = 0.809, 0 ≤ x ≤ π 0.628 radians<br />

Find the measure, in degrees, of each<br />

angle x. Round to the nearest tenth if<br />

necessary.<br />

<strong>10</strong>. tan x = –1.1, –90º < x < 90º–47.7º<br />

11. sin x = –0.965, –90º ≤ x ≤ 90º–74.8º<br />

Use an angle identity to rewrite<br />

each expression.<br />

12. cos 35° cos 75° – sin 35° sin 75° cos 1<strong>10</strong>°<br />

13. sin 80° cos 40° – cos 80° sin 40° sin 40°<br />

19. An airliner is cruising at an elevation<br />

of 6 miles. To make a smooth descent<br />

for the passengers, the pilot begins his<br />

descent at a distance of 70 miles from<br />

the airport. What is the plane’s angle of<br />

descent (the angle formed by the runway<br />

and the flight path) Round to the<br />

nearest tenth. 4.9°<br />

20. The voltage, V, in the power cord of a<br />

computer t seconds after it was turned<br />

on can be modeled using the function<br />

V(t) = 120cos (120πt). After how many<br />

seconds is the voltage equal to its<br />

maximum Express the answer so that<br />

it represents all solutions in the interval<br />

t > 0. n , where n is a whole number<br />

60<br />

504 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities


Standardized Test Practice<br />

Multiple Choice<br />

1. What is the value of cos –1 0.788 A<br />

A 38° B 42°<br />

C 49° D 56°<br />

2. What is the common difference of the<br />

arithmetic sequence below C<br />

18.4, 16.1, 13.8, 11.5, 9.2, …<br />

A 2.8 B 2.3<br />

C –2.3 D –2.8<br />

3. What is the slope of line m below B<br />

Gridded Response<br />

6. How many 4-inch cubes can be placed<br />

inside a box that is 16 inches tall,<br />

8 inches wide, and 12 inches long 24<br />

7. What is the value of x in the triangle<br />

below Round to the nearest tenth<br />

of a centimeter. 22.1<br />

Open Ended Response<br />

8. Describe how to convert an angle<br />

measure of 20º from degrees to<br />

radians. Then give the number of<br />

radians. Multiply 20º by<br />

≠<br />

180 ; ≠ 9 radians<br />

A – 3 B – 2 2<br />

3<br />

C<br />

2<br />

D<br />

3<br />

3<br />

2<br />

4. Which angle measure is equivalent to<br />

2≠ radians D<br />

5<br />

A 48° B 64°<br />

C 70° D 72°<br />

5. Evaluate the trigonometric function<br />

y = 6 – cos 2θ for θ = 20º. Round to the<br />

nearest tenth. B<br />

A 5.1<br />

B 5.2<br />

C 5.3<br />

D 5.4<br />

Extended Response<br />

9. Two airplanes take off from the same<br />

airport at the same time. Plane A flies in<br />

a direction 24º east of north and cruises<br />

at a speed of 550 miles per hour. Plane B<br />

flies in a direction 38º west of north and<br />

cruises at a speed of 490 miles per hour.<br />

a. How far has each plane traveled after<br />

90 minutes Plane A: 825 mi; Plane B: 735 mi<br />

b. Sketch a diagram to show the<br />

position of each plane after<br />

90 minutes. see margin<br />

c. Find the distance between the<br />

two planes after 90 minutes. Round<br />

to the nearest tenth. 807.2 mi<br />

<strong>Chapter</strong> Assessments 505

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