Chapter 10 - NCPN
Chapter 10 - NCPN
Chapter 10 - NCPN
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Practice and Problem Solving<br />
Simplify each expression.<br />
6. 1 – cos 2 θ sin 2 θ 7. tan θ cos θ sin θ<br />
8. sin 2 θ sec θ csc θ tan θ 9. sin 2 θ + tan 2 θ + cos 2 θ sec 2 θ<br />
<strong>10</strong>. (1 + cot 2 θ)(sec θ) csc 2 θ sec θ 11. sin θ csc θ – cos 2 θ sin 2 θ<br />
12. sec θ cos θ – cos 2 θ sin 2 θ 13. sec θ cos 2 θ csc θ cot θ<br />
Verify each identity. check students’ work; see margin for samples<br />
14. cos θ tan θ = sin θ 15. tan θ (cot θ + tan θ) = sec 2 θ<br />
16. sin θ sec θ = tan θ 17. cos θ + sin θ tan θ = sec θ<br />
18. sec 2 θ = 1 + tan 2 θ 19. sec θ – sin θ tan θ = cos θ<br />
20. cos θ sin θ (cot θ + tan θ) = 1<br />
21. sin 2 θ tan 2 θ = tan 2 θ – sin 2 θ<br />
22. Let sin θ = − 7 and θ be in quadrant III. see margin<br />
25<br />
a. Find cos θ. b. Find tan θ.<br />
23. Let tan θ = − 15 and θ be in quadrant II. see margin<br />
8<br />
a. Find sin θ. b. Find cos θ.<br />
24. How can you express tan θ in terms of cos θ tan θ = ± −<br />
2<br />
1 cos<br />
θ<br />
cosθ<br />
25. How can you express cot θ in terms of csc θ cot θ = ± csc 2 θ −1<br />
26. How can you express sec θ in terms of tan θ sec θ = 2<br />
± 1+<br />
tan θ<br />
27. Mario simplified the<br />
trigonometric expression<br />
sin 2 θ sec 2 θ + 1 as<br />
shown here. What error<br />
did he make Simplify<br />
the expression. see margin<br />
2 2 2<br />
sin θsec θ + 1 = sin θ<br />
1<br />
+ 1<br />
2<br />
sin θ<br />
= 1+<br />
1<br />
= 2<br />
28. Verify the trigonometric identity csc θ tan θ = sec θ.<br />
check students’ work<br />
2 2<br />
29. Simplify the trigonometric expression cot θ − csc θ<br />
2 2<br />
tan θ − sec θ<br />
Mixed Review<br />
Write a recursive formula for each sequence.<br />
30. 7, 2, –3, –8, –13, … 31. 2, –5, 16, –47, 142, …<br />
a n<br />
a n–1<br />
a 1<br />
a n<br />
a n–1<br />
a 1<br />
474 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />
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