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Chapter 10 - NCPN

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Practice and Problem Solving<br />

Simplify each expression.<br />

6. 1 – cos 2 θ sin 2 θ 7. tan θ cos θ sin θ<br />

8. sin 2 θ sec θ csc θ tan θ 9. sin 2 θ + tan 2 θ + cos 2 θ sec 2 θ<br />

<strong>10</strong>. (1 + cot 2 θ)(sec θ) csc 2 θ sec θ 11. sin θ csc θ – cos 2 θ sin 2 θ<br />

12. sec θ cos θ – cos 2 θ sin 2 θ 13. sec θ cos 2 θ csc θ cot θ<br />

Verify each identity. check students’ work; see margin for samples<br />

14. cos θ tan θ = sin θ 15. tan θ (cot θ + tan θ) = sec 2 θ<br />

16. sin θ sec θ = tan θ 17. cos θ + sin θ tan θ = sec θ<br />

18. sec 2 θ = 1 + tan 2 θ 19. sec θ – sin θ tan θ = cos θ<br />

20. cos θ sin θ (cot θ + tan θ) = 1<br />

21. sin 2 θ tan 2 θ = tan 2 θ – sin 2 θ<br />

22. Let sin θ = − 7 and θ be in quadrant III. see margin<br />

25<br />

a. Find cos θ. b. Find tan θ.<br />

23. Let tan θ = − 15 and θ be in quadrant II. see margin<br />

8<br />

a. Find sin θ. b. Find cos θ.<br />

24. How can you express tan θ in terms of cos θ tan θ = ± −<br />

2<br />

1 cos<br />

θ<br />

cosθ<br />

25. How can you express cot θ in terms of csc θ cot θ = ± csc 2 θ −1<br />

26. How can you express sec θ in terms of tan θ sec θ = 2<br />

± 1+<br />

tan θ<br />

27. Mario simplified the<br />

trigonometric expression<br />

sin 2 θ sec 2 θ + 1 as<br />

shown here. What error<br />

did he make Simplify<br />

the expression. see margin<br />

2 2 2<br />

sin θsec θ + 1 = sin θ<br />

1<br />

+ 1<br />

2<br />

sin θ<br />

= 1+<br />

1<br />

= 2<br />

28. Verify the trigonometric identity csc θ tan θ = sec θ.<br />

check students’ work<br />

2 2<br />

29. Simplify the trigonometric expression cot θ − csc θ<br />

2 2<br />

tan θ − sec θ<br />

Mixed Review<br />

Write a recursive formula for each sequence.<br />

30. 7, 2, –3, –8, –13, … 31. 2, –5, 16, –47, 142, …<br />

a n<br />

a n–1<br />

a 1<br />

a n<br />

a n–1<br />

a 1<br />

474 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities<br />

. 1

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