Chapter 10 - NCPN
Chapter 10 - NCPN
Chapter 10 - NCPN
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Solution<br />
Use the definitions of the trigonometric ratios. Reduce each ratio.<br />
sinN<br />
=<br />
8<br />
=<br />
4<br />
csc N =<br />
<strong>10</strong><br />
=<br />
5<br />
<strong>10</strong> 5<br />
8 4<br />
cosN<br />
=<br />
6<br />
=<br />
3<br />
sec N =<br />
<strong>10</strong><br />
=<br />
5<br />
<strong>10</strong> 5<br />
6 3<br />
tanN<br />
=<br />
8<br />
=<br />
4<br />
6 3<br />
cot N<br />
Ongoing Assessment<br />
Find the trigonometric ratios<br />
for ∠Z in the triangle below.<br />
see margin<br />
=<br />
6<br />
=<br />
8<br />
3<br />
4<br />
Example 2<br />
Finding the Height of a Building<br />
Use the information in the opening paragraph of this lesson. What is the<br />
height of the school building<br />
Solution<br />
Draw a picture to help solve the problem.<br />
Choose a trigonometric ratio that relates the leg opposite an angle and the<br />
leg adjacent to an angle. Use the tangent ratio to find the unknown height of<br />
the school building.<br />
tan 40° =<br />
x<br />
38<br />
Use a calculator to approximate tan 40° and solve for x.<br />
0.839 ≈<br />
x<br />
38<br />
31.9 ≈ x<br />
The height of the school building is about 31.9 feet.<br />
438 <strong>Chapter</strong> <strong>10</strong> Trigonometric Functions and Identities
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