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Pythagorean Theorem Differentiated Instruction for Use in an ...

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F<strong>in</strong>d the length of the miss<strong>in</strong>g leg on the tri<strong>an</strong>gles below.<br />

Page 5<br />

a = 5 25 + b² = 81<br />

9 b = ? 25 + b² – 25 = 81 – 25<br />

5 c = 9 b² = 56<br />

Substitute <strong>in</strong>to the <strong>for</strong>mula b = √56<br />

5² + b² = 9² b = 7.483314774<br />

F<strong>in</strong>d the length of the miss<strong>in</strong>g leg.<br />

a = ? a² + 400 = 484<br />

b = 20 a² + 400 – 400 = 484 - 400<br />

c = 22 a² = 84<br />

20 22 Substitute <strong>in</strong>to the <strong>for</strong>mula a = √84<br />

a² + 20 = 22 a = 9.16515139<br />

F<strong>in</strong>d the length of the miss<strong>in</strong>g leg.<br />

The tri<strong>an</strong>gle at the right has a leg<br />

of 12 <strong>an</strong>d a hypotenuse of 23.4.<br />

Label the tri<strong>an</strong>gle at the right <strong>an</strong>d<br />

f<strong>in</strong>d the miss<strong>in</strong>g leg. Round to the<br />

nearest 100 th . 20.09<br />

20

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