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A Calculus of Number Based on Spatial Forms - University of ...

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78<br />

([xd][xd])([xd][f])<br />

([xd][xd])([xd][f])([xd][])([f][])<br />

([xd][xdf])([xdf][])<br />

([xdf][xd])<br />

([x][x])<br />

Inversi<strong>on</strong><br />

Promoti<strong>on</strong><br />

Distributi<strong>on</strong><br />

Distributi<strong>on</strong><br />

Inverse Cancellati<strong>on</strong><br />

This gives two soluti<strong>on</strong>s.<br />

x = and x = <br />

Expand these for the recognized soluti<strong>on</strong>s. Recall f.<br />

f<br />

: = (([[([d][d])]]))<br />

First expand the interior <str<strong>on</strong>g>of</str<strong>on</strong>g> f.<br />

([d][d]) =<br />

= ([([b])][([b])]) Deniti<strong>on</strong> <str<strong>on</strong>g>of</str<strong>on</strong>g> d<br />

= ( [b] [b] ) Involuti<strong>on</strong><br />

= ([b][b]) Deniti<strong>on</strong> <str<strong>on</strong>g>of</str<strong>on</strong>g> e<br />

= ([b][b])<br />

<br />

Inversi<strong>on</strong><br />

= ([b][b])<br />

<br />

Collecti<strong>on</strong><br />

= ([([b][b])])<br />

<br />

Involuti<strong>on</strong><br />

= ([([b][b])])<br />

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