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<strong>1.3</strong> <strong>Creating</strong> <strong>New</strong> <strong>Polynomial</strong><br />

<strong>Functions</strong>: <strong>An</strong> <strong>Introduction</strong><br />

<strong>to</strong> Composition<br />

SETTING THE STAGE<br />

EXAMINING THE CONCEPT<br />

Can you combine polynomial functions using the basic mathematical<br />

operations If so, what is the result<br />

Rhona is a licensed plumber and Bill is an apprentice training for his licence.<br />

Rhona earns $28/h and receives $22/day <strong>to</strong> travel <strong>to</strong> the job site. Bill earns $12/h<br />

and receives a $10/day travel allowance. The polynomial model for Rhona’s<br />

daily earnings, R, in dollars is R(h) 28h 22, where h is the number of hours<br />

worked. Similarly, Bill’s earnings are modelled by B(h) 12h 10.<br />

In this section, you will examine what happens when polynomial functions<br />

are combined using familiar operations <strong>to</strong> form new polynomial functions.<br />

Adding and Subtracting <strong>Functions</strong><br />

When Rhona and Bill are working <strong>to</strong>gether on a job, the contrac<strong>to</strong>r for the job<br />

site needs a single function <strong>to</strong> determine the costs for plumbing work.<br />

The <strong>to</strong>tal daily cost, T(h), is a function of the number of hours worked, h, by<br />

Rhona and Bill.<br />

Rhona’s Bill’s Total Earnings,<br />

Time Earnings, R(h) Earnings, B(h) T(h) R(h) B(h)<br />

(h) ($) ($) ($)<br />

0 22 10 22 10 32<br />

1 50 22 50 22 72<br />

2 78 34 78 34 112<br />

3 106 46 106 46 152<br />

So<br />

T(h) R(h) B(h)<br />

(28h 22) (12h 10)<br />

28h 22 12h 10<br />

40h 32<br />

In both the table and the graph, the<br />

values of the functions are added<br />

<strong>to</strong>gether <strong>to</strong> obtain the value of the<br />

new function.<br />

Adding or subtracting two<br />

functions means adding or<br />

subtracting the corresponding<br />

outputs, or, in terms of the graph,<br />

adding or subtracting the<br />

y-coordinates.<br />

Earnings ($)<br />

160<br />

140<br />

120<br />

100<br />

80<br />

60<br />

40<br />

20<br />

Total cost <strong>to</strong><br />

contrac<strong>to</strong>r<br />

y = 40h + 32<br />

0 1 2 3<br />

Time (h)<br />

(3, 152)<br />

(152 = 46 + 106)<br />

Rhona's earnings<br />

y = 28h + 22<br />

Bill's earnings<br />

y = 12h + 10<br />

28 CHAPTER 1 POLYNOMIAL FUNCTION MODELS


Example 1<br />

Subtracting Two <strong>Polynomial</strong> <strong>Functions</strong><br />

Let f (x) 2(x 1)(x 2)(x 4) and g(x) (x 1)(x 2)(x 4).<br />

(a) On the same axes, sketch the graph of each function. Use intercepts, the<br />

degree of the function, and the leading coefficient <strong>to</strong> develop the sketch.<br />

(b) Graph h(x) f (x) g(x).<br />

(c) Identify the domain of each function.<br />

9<br />

6<br />

3<br />

–3 –2 –1<br />

–3<br />

–6<br />

–9<br />

–12<br />

–15<br />

–18<br />

y<br />

Solution<br />

y = g(x)<br />

x<br />

1 2 3 4 5 6<br />

y = f(x)<br />

(a) The zeros for both f (x) and g(x) are 1, 2, and 4.<br />

By inspection, both functions are degree-3 polynomials.<br />

The leading coefficient of f (x) is negative.<br />

Therefore, as x → ∞, f (x) →∞and as x →∞, f (x) → ∞.<br />

For g(x), the leading coefficient is positive.<br />

Therefore, as x → ∞, g(x) → ∞ and as x →∞, g(x) →∞.<br />

The y-intercept of g(x) is 8 and the y-intercept of f (x) is 16.<br />

Using this information results in the sketch <strong>to</strong> the left.<br />

y<br />

12<br />

y = h(x)<br />

8<br />

y = g(x)<br />

4<br />

x<br />

–3 –2 –1<br />

–4<br />

–8<br />

–12<br />

1 2 3 4 5 6<br />

–16<br />

–20<br />

y = f(x)<br />

–24<br />

–28<br />

–32<br />

f (x), g(x), and h(x) f (x) g(x)<br />

(b) h(x) f (x) g(x)<br />

To find points that lie on h(x), subtract the y-coordinates of points<br />

that have the same x-coordinate. The difference function has the<br />

same zeros as the two original functions, that is, 1, 2, and 4.<br />

Subtracting the y-intercepts results in point (0, 24). Create a table<br />

<strong>to</strong> record some additional key points on f and g, and use these <strong>to</strong><br />

find more points on h.<br />

x f (x) g(x) h(x) f (x) g(x)<br />

1 12 6 12 6 18<br />

3 8 4 8 (4) 12<br />

5 36 18 36 18 54<br />

(c) Since f (x) and g(x) are polynomial functions, their domains are the same,<br />

that is, the set of real numbers. The difference function h(x) is also a<br />

polynomial function, and its domain is also the set of real numbers.<br />

For any two functions, the y-values can only be added or subtracted when<br />

the x-values are common. For any polynomial function, the domain is the set<br />

of real numbers, so the difference, or sum, function will have the same<br />

domain, the set of real numbers. However, the range of f (x) ± g(x) must be<br />

determined each time.<br />

<strong>1.3</strong> CREATING NEW POLYNOMIAL FUNCTIONS: AN INTRODUCTION TO COMPOSITION 29


EXAMINING THE CONCEPT<br />

Multiplying Two <strong>Polynomial</strong> <strong>Functions</strong><br />

What is the result when two polynomial functions are multiplied<br />

Example 2<br />

Multiplying Two <strong>Polynomial</strong> <strong>Functions</strong><br />

Let f (x) x 3 and g(x) x 2 5, x ∈ R.<br />

(a) Sketch each graph on the same axes.<br />

(b) Make a table for 3 ≤ x ≤ 3, and determine the corresponding values of<br />

h(x) f (x) g(x).<br />

(c) Use the table <strong>to</strong> sketch h(x) on the same axes. Describe the shape of the<br />

graph.<br />

(d) Determine the algebraic model for h(x). What is its degree<br />

(e) What is the domain of h(x) How does this domain compare with the<br />

domains of f (x) and g(x)<br />

10<br />

8<br />

6<br />

4<br />

2<br />

–5 –4 –3 –2 –1<br />

–2<br />

y = h(x)<br />

18<br />

15<br />

12<br />

9<br />

6<br />

y<br />

–4<br />

–6<br />

–8<br />

–10<br />

3<br />

x<br />

–3 –2 –1 1 2 3<br />

–3<br />

–6<br />

y = g(x)<br />

–9<br />

y<br />

Solution<br />

y = f(x)<br />

1 2 3 4 5<br />

y = f(x)<br />

y = g(x)<br />

x<br />

(a) Use intercepts <strong>to</strong> sketch the graphs.<br />

The graph of function f (x) is linear with slope 1 and<br />

y-intercept 3.<br />

The graph of function g(x) is quadratic with vertex (0, 5).<br />

The parabola opens down.<br />

(b)<br />

f (x) x 3 g(x) x 2 5 h(x) f (x) g(x)<br />

3 0 4 0 (4) 0<br />

2 1 1 1 1 1<br />

1 2 4 2 4 8<br />

0 3 5 3 5 15<br />

1 4 4 4 4 16<br />

2 5 1 5 1 5<br />

3 6 4 6 (4) 24<br />

(c) The graph of h(x) is a cubic polynomial.<br />

(d) h(x) f (x) g(x)<br />

(x 3)(x 2 5)<br />

x 3 3x 2 5x 15<br />

This polynomial function has degree 3.<br />

(e) The domain of h(x) is the set of real numbers, which is the same as the<br />

domains of f (x) and g(x).<br />

30 CHAPTER 1 POLYNOMIAL FUNCTION MODELS


Adding, Subtracting, and Multiplying<br />

<strong>Polynomial</strong> <strong>Functions</strong><br />

For the polynomial functions f and g,<br />

• the sum is ( f g)(x) f (x) g(x)<br />

• the difference is ( f g)(x) f (x) g(x)<br />

• the product is ( fg)(x) f (x) g(x)<br />

The domain of f ± g and fg is the set of all x, for which both f and g are<br />

defined. <strong>An</strong>y x belonging <strong>to</strong> the domain of f and <strong>to</strong> the domain of g belongs<br />

<strong>to</strong> the domain of f (x) ± g(x) or f (x) g(x).<br />

EXAMINING THE CONCEPT<br />

input → output<br />

x → g(x) → f (g(x))<br />

g f<br />

input → output<br />

The Composition of <strong>Functions</strong><br />

What happens when the output of one function is the input of another<br />

You can think of a function as an input-output machine. The input set<br />

is the domain of the function, and the output set is the range of the function.<br />

In the first step of the diagram, the x is an input and g(x) is an output.<br />

In the second step, g(x) is an input and f (g(x)) is an output.<br />

Combining two functions in this way is called composition. Composition is<br />

the result of substituting the output of one function in<strong>to</strong> another. The new<br />

function is called the composite of f and g and is written f g.<br />

Example 3<br />

Determining the Equation of a Composite Function<br />

Recall the situation in Setting the Stage. Rhona earns a daily wage according <strong>to</strong><br />

R(h) 28h 22. The job site where Rhona works requires all employees <strong>to</strong><br />

become members of a union. Rhona then pays 1.5% of her daily earnings as<br />

union dues. Determine the function that represents her daily union dues.<br />

Hours Worked<br />

h<br />

1<br />

2<br />

3<br />

.<br />

.<br />

.<br />

.<br />

8<br />

R<br />

Daily Earnings<br />

R(h)<br />

50<br />

78<br />

106<br />

.<br />

.<br />

.<br />

.<br />

246<br />

Solution<br />

U<br />

Union Dues<br />

U(R(h))<br />

0.75<br />

1.17<br />

1.59<br />

.<br />

.<br />

.<br />

.<br />

3.69<br />

This situation involves two functions,<br />

Daily Earnings: R(h) 28h 22<br />

Daily Union Dues: U(R(h)) 0.015 R(h)<br />

Examine the mapping that shows how the number of<br />

hours worked per day is related <strong>to</strong> the daily union dues.<br />

The domain for Rhona’s daily earnings is the number of<br />

hours worked. But the domain for the daily union dues<br />

are her daily earnings, not the number of hours worked.<br />

In other words, the domain of the substitution function is<br />

the range of the substituted function.<br />

<strong>1.3</strong> CREATING NEW POLYNOMIAL FUNCTIONS: AN INTRODUCTION TO COMPOSITION 31


Find the composite of the two functions.<br />

U(R(h)) 0.015(R(h))<br />

0.015(28h 22)<br />

0.42h 0.33<br />

The function U(R(h)) 0.42h 0.33 represents Rhona’s daily union dues.<br />

Composite <strong>Functions</strong><br />

For two functions f and g, the composite function f (g(x)) is formed by<br />

evaluating f at g(x). This new function is defined as f g. The domain of f g<br />

is a subset of the domain of g and is found by examining f g and comparing<br />

the domain of f with the range of g.<br />

Example 4<br />

Determining the Value of a Composite Function<br />

For the functions f {(4, 1), (3, 2), (2, 3)} and g {(1, 5), (2, 4), (4, 2)},<br />

determine each value.<br />

(a) f (g(4)) (b) g( f (4))<br />

Solution<br />

(a) First find the value of g where x 4. In the ordered pair (4, 2), x 4.<br />

Therefore, g(4) 2.<br />

Then f (g(4)) f (2). Now find the value of f where x 2.<br />

In the ordered pair (2, 3), x 2.<br />

So f (g(4)) f (2)<br />

3<br />

(b) Find the value of f where x 4. In the ordered pair (4, 1), x 4.<br />

Therefore, f (4) 1.<br />

Then g( f (4)) g(1). Now find the value of g where x 1.<br />

In the ordered pair (1, 5), x 1.<br />

So<br />

g( f (4)) g(1)<br />

5<br />

Example 5<br />

Applying a Composite Function<br />

Ali buys a pair of shoes and has a coupon for $15 off. The day he buys the<br />

shoes, the s<strong>to</strong>re has a sale offering 20% off the price of all shoes.<br />

(a) Write a function <strong>to</strong> represent the cost, C, of a pair of shoes at price, p, if just<br />

the coupon reduction is applied <strong>to</strong> the cost of the shoes. Write a function that<br />

represents the cost, D, if just the discount is applied <strong>to</strong> the cost.<br />

32 CHAPTER 1 POLYNOMIAL FUNCTION MODELS


(b) What does the function D(C(p)) represent if a pair of shoes has a regular<br />

price of $80 Determine D(C(80)).<br />

(c) What does the function C D represent for a pair of shoes with a regular<br />

price of $80 Determine C D for the same pair of shoes.<br />

(d) Does C D D C Justify your answer.<br />

Solution<br />

(a) C(p) p 15 and D(p) 0.8p<br />

(b) D(C(p)) means the coupon is applied first and then the<br />

discount is applied <strong>to</strong> the cost of the shoes. So, when p 80,<br />

D(C(80)) D(80 15)<br />

D(65)<br />

0.8(65)<br />

52<br />

(c) C D means the discount is taken first and then the coupon reduction is<br />

applied. When p 80,<br />

(C D)(x) C(D(80))<br />

C(0.8(80))<br />

C(64)<br />

64 15<br />

49<br />

(d) In this case, C D ≠ D C. The order of composition makes a difference.<br />

When p 80, D(C(80)) 52 and C(D(80)) 49. In fact, these two<br />

functions are different.<br />

(C D)(p) C(0.8p) (D C)(p) D(p 15)<br />

0.8p 15 0.8(p 15)<br />

0.8p 12<br />

CHECK, CONSOLIDATE, COMMUNICATE<br />

1. Explain how a new polynomial function can be made from two<br />

polynomial functions by addition, by subtraction, and by multiplication.<br />

2. State ( f g)(x), ( f g)(x), ( f g)(x), and f (g(x)) for<br />

f {(1, 4), (0, 5), (6, 3)} and g {(1, 6), (0, 9), (4, 2)}.<br />

3. Determine ( f g)(x), ( f g)(x), ( f g)(x), and f (g(x)) for<br />

f (x) x 2 3x 2 and g(x) x 3.<br />

<strong>1.3</strong> CREATING NEW POLYNOMIAL FUNCTIONS: AN INTRODUCTION TO COMPOSITION 33


KEY IDEAS<br />

• <strong>New</strong> polynomial functions can be made from other polynomial functions<br />

through addition, subtraction, multiplication, and composition.<br />

• The domain of a polynomial function that is the result of adding,<br />

subtracting, or multiplying other polynomial functions is the same as the<br />

common domain of the original polynomial functions.<br />

• For two functions f and g, the composite function f g f (g(x)) is formed<br />

by evaluating f at g. For f g, the domain of f is the range of g, provided<br />

that g is defined.<br />

<strong>1.3</strong> Exercises<br />

A<br />

1. Knowledge and Understanding: Let f {(4, 4), (2, 4), (1, 3), (3, 5),<br />

(4, 6)} and g {(4, 2), (2, 1), (0, 2), (1, 2), (2, 2), (4, 4)}. Determine<br />

(a) f g (b) f g (c) g f (d) fg<br />

2. Use the graph of f and g <strong>to</strong> sketch the graph of f g.<br />

(a)<br />

y<br />

(b)<br />

f<br />

7<br />

6<br />

5<br />

4<br />

3<br />

2<br />

g 1<br />

x<br />

–5 –4 –3 –2 –1 0<br />

–1<br />

1 2 3 4 5<br />

–2<br />

f<br />

7<br />

6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

–5 –4 –3 –2 –1 0 1 2 3 4 5<br />

–1<br />

–2<br />

y<br />

g<br />

x<br />

3. Use the graph of f and g <strong>to</strong> sketch the graph of f g.<br />

(a)<br />

y<br />

7<br />

6<br />

5<br />

4<br />

f 3<br />

2<br />

1<br />

x<br />

–5 –4 –3 –2 –1 0 1 2 3 4 5<br />

g –1<br />

–2<br />

(b)<br />

y<br />

7<br />

6<br />

f<br />

5<br />

4<br />

3 g<br />

2<br />

1<br />

–5 –4 –3 –2 –1 0<br />

–1<br />

1 2 3 4 5<br />

–2<br />

x<br />

34 CHAPTER 1 POLYNOMIAL FUNCTION MODELS


4. Use the graph of f and g <strong>to</strong> sketch the graph of fg.<br />

(a)<br />

y<br />

7<br />

6<br />

f<br />

5<br />

4<br />

g<br />

3<br />

(b)<br />

2<br />

1<br />

x<br />

–3 –2 –1 0<br />

–1<br />

1 2 3 4 5 6 7<br />

–4 –3<br />

–2<br />

y<br />

7<br />

g 6<br />

5<br />

4<br />

3<br />

2<br />

1<br />

–2 –1 0<br />

–1<br />

1 2<br />

–2<br />

3<br />

f<br />

4<br />

x<br />

B<br />

5. Let f {(3, 2), (5, 1), (7, 4), (9, 3), (11, 5)} and<br />

g {(1, 3), (2, 5), (3, 7), (4, 9), (5, 11)}. Determine<br />

(a) f (g(3)) (b) g( f (9))<br />

6. Let f {(1, 3), (0, 2), (1, 3), (2, 6)} and<br />

g {(1, 0), (0, 1), (1, 2), (2, 3)}. Determine<br />

(a) f (g(x))<br />

(b) g( f (x))<br />

7. Let f (x) 3x 2 and g(x) 2x 4, x ∈ R. Determine an expression for<br />

each case, and state the domain of the expression.<br />

(a) ( f g)(x) (b) (g f )(x) (c) ( f g)(x) (d) ( fg)(x)<br />

8. Let f (x) 3x 1, 0 ≤ x ≤ 6, and g(x) x 2 6x, 1 ≤ x ≤ 4.<br />

Determine an expression for each case, and state the domain of<br />

the expression.<br />

(a) ( f g)(x) (b) ( f g)(x) (c) (g f )(x) (d) ( fg)(x)<br />

9. Let f (x) x 2 4 and g(x) 3x. Determine<br />

(a) f (g(1)) (b) g( f (2)) (c) g(g(1)) (d) f ( f (2))<br />

10. Communication: Consider two functions f and g.<br />

(a) Explain why the domains of f and g must be the same in order <strong>to</strong> add,<br />

subtract, or multiply the functions.<br />

(b) Explain why the domain of f is the range of g for f (g(x)).<br />

11. Let f {(1, 4), (0, 2), (1, 0), (2, 2)}.<br />

(a) Give an example of g if f g {(1, 6), (0, 4), (1, 2), ( 2, 0)}.<br />

(b) Give an example of g if fg {(1, 12), (0, 6), (1, 0), (2, 6)}.<br />

12. Let f (x) 3x 2, 2 ≤ x ≤ 4, and g(x) 4x 1, 3 ≤ x ≤ 5.<br />

(a) Graph f and g on the same axes.<br />

(b) Use appropriate ordered pairs <strong>to</strong> sketch the graph of f g.<br />

What is the domain of f g<br />

<strong>1.3</strong> CREATING NEW POLYNOMIAL FUNCTIONS: AN INTRODUCTION TO COMPOSITION 35


13. In each case, determine f (x) g(x) and draw its graph.<br />

(a) f (x) 2x 3, x ∈ R, and g(x) 3x 4, x ∈ R<br />

(b) f (x) 3x 2, x ∈ R, and g(x) x 2 3, x ∈ R<br />

(c) f (x) x 2 2, x ∈ R, and g(x) 2x 2 1, x ∈ R<br />

14. In each case, functions f and g are defined for x ∈ R. For each pair of<br />

functions, determine the expression and the domain for f (g(x)) and g( f (x)).<br />

Graph each result.<br />

(a) f (x) 3x 2 , g(x) x 1<br />

(b) f (x) 2x 2 x, g(x) x 2 1<br />

(c) f (x) 2x 3 3x 2 x 1, g(x) 2x 1<br />

(d) f (x) x 4 x 2 , g(x) x 1<br />

15. In each case, x ∈ R for f (x) and g(x). Graph f (x) and g(x) on the same axes<br />

and use this graph <strong>to</strong> graph h(x) f (x) g(x).<br />

(a) f (x) x 2 1 and g(x) 3<br />

(b) f (x) 2x 2 2 and g(x) 2x 2 1<br />

(c) f (x) (x 1)(x 2)(x 4) and g(x) (x 1)(x 4)(x 6)<br />

16. Verify your work in question 15 using a graphing calcula<strong>to</strong>r.<br />

17. Repeat question 15 for h(x) f (x) g(x).<br />

18. A company produces a product for $9.45 per unit, plus a fixed operating<br />

cost of $52 000. The company sells the product for $15.80 per unit.<br />

(a) Determine a function, C(x), <strong>to</strong> represent the cost of producing x units.<br />

(b) Determine a function, S(x), <strong>to</strong> represent sales of x units.<br />

(c) Determine a function that represents profit.<br />

19. Steve earns $24.39/h operating an industrial plasma <strong>to</strong>rch at a rail car<br />

manufacturing plant. He receives $0.58/h more for working the night shift,<br />

as well as $0.39/h for working weekends.<br />

(a) Write a function that describes Steve’s regular pay.<br />

(b) What function shows his night shift premium<br />

(c) What function shows his weekend premium<br />

(d) What function represents his earnings for the night shift on Saturday<br />

(e) How much does Steve earn for working 11 h on Saturday night, if he<br />

earns time and a half on that day’s rate for more than 8 h of work<br />

20. A circle has radius r.<br />

(a) Write a function for the circle’s area in terms of r.<br />

(b) Write a function for the radius in terms of the circumference, C.<br />

(c) Determine A(r(C)).<br />

(d) A tree’s circumference is 3.6 m. What is the area of the cross section<br />

36 CHAPTER 1 POLYNOMIAL FUNCTION MODELS


Johann Peter Gustav<br />

Lejeune Dirichlet<br />

(1805–1859)<br />

Originally, the<br />

definition of a function<br />

was much less precise<br />

than it is <strong>to</strong>day.<br />

Dirichlet was<br />

responsible for the<br />

definition of a function<br />

that we use <strong>to</strong>day.<br />

21. Application: A solar panel is used <strong>to</strong> power an overhead sign on a highway.<br />

Each square metre of solar panel receives about 200 W of solar power. This<br />

solar panel converts about 15% of the solar energy <strong>to</strong> electrical power.<br />

(a) Write a function for the solar power, S(A), measured in watts (W) for<br />

any given area, A, in square metres.<br />

(b) Write a function for the <strong>to</strong>tal electrical power, P(S), in watts (W) this<br />

solar panel can generate.<br />

(c) How large must the solar panel be if the sign uses 6 W of electrical<br />

energy<br />

22. Refrigeration slows down the growth of bacteria in food. The number of<br />

bacteria in a certain food is approximated by B(T) 15T 2 70T 600,<br />

where T represents the temperature in degrees Celsius and 3 ≤ T ≤ 12.<br />

Once the food is removed from refrigeration, the temperature, T(t),<br />

is given by T(t) 3.5t 3, where t is the time in hours and 0 ≤ t ≤ 3.<br />

(a) Write the expression for the number of bacteria in the food, t hours<br />

after it is removed from refrigeration.<br />

(b) At 1.5 h, about how many bacteria are in the food<br />

(c) When will the bacteria count reach about 1200<br />

23. A franchise owner operates two coffee shops. The sales, S 1<br />

, in thousands of<br />

dollars, for shop one are represented by S 1<br />

(t) 700 1.4t 2 , where t 0<br />

corresponds <strong>to</strong> the year 2000. Similarly, the sales for shop two are<br />

represented by S 2<br />

(t) t 3 3t 2 500.<br />

(a) Which shop is showing an increase in sales after the year 2000<br />

(b) Determine a function that represents the <strong>to</strong>tal sales for the two<br />

coffee shops.<br />

(c) What are the expected <strong>to</strong>tal sales for the year 2006<br />

(d) If sales continue according <strong>to</strong> the individual functions, what would you<br />

recommend that the owner do Explain.<br />

C<br />

24. Thinking, Inquiry, Problem Solving: Let f (x) mx 2 2x 5 and<br />

g(x) 2x 2 nx 2. The functions are combined <strong>to</strong> form the new function<br />

h(x) f (x) g(x). Points (1, 40) and (1, 24) satisfy the new function.<br />

Determine f (x) and g(x).<br />

25. Let h(k) 3k 2, g(t) 3t 2, and f (x) 3x 2.<br />

(a) Determine C(k) f (g(h(k))).<br />

(b) Show in a diagram how k 4 carries through <strong>to</strong> its final value.<br />

<strong>1.3</strong> CREATING NEW POLYNOMIAL FUNCTIONS: AN INTRODUCTION TO COMPOSITION 37


ADDITIONAL ACHIEVEMENT CHART QUESTIONS<br />

Knowledge and Understanding: Let f (x) x 2 3x 1 and g(x) 2x 5.<br />

Determine<br />

(a) f (x) g(x) (b) f (x) g(x) (c) f (x) g(x) (d) f (g(x))<br />

Application: The temperature of the Earth’s crust is a linear function of the depth<br />

below the surface. The function T(d) 0.01d 20 gives the temperature, T(d),<br />

in degrees Celsius d metres below the Earth’s surface. <strong>An</strong> eleva<strong>to</strong>r goes down a<br />

mine shaft at 7.5 m/s. Express the temperature as a function of the time<br />

travelled.<br />

Amount ($1000s)<br />

990<br />

900<br />

810<br />

720<br />

630<br />

540<br />

450<br />

360<br />

270<br />

180<br />

Income<br />

Expense<br />

Profit<br />

Thinking, Inquiry, Problem Solving: If f (x) ax b,<br />

g(x) cx d, and f g(x) g f (x), determine the relation<br />

among a, b, c, and d.<br />

Communication: The graph on the left shows two functions and<br />

the function that represents the difference between the two<br />

functions. Identify and describe the two original functions and<br />

the difference function.<br />

90<br />

–90<br />

–180<br />

1 2 3 4 5 6 7 8 9 10<br />

Number of Units (1000s)<br />

The Chapter Problem<br />

Developing a Model for Canada’s Population<br />

In this section, you learned about creating new polynomial functions.<br />

Apply what you learned <strong>to</strong> answer these questions about The Chapter<br />

Problem on page 2.<br />

CP9.<br />

Refer <strong>to</strong> the two different polynomial models that you created for<br />

question CP5 (section 1.2). Write the linear and quadratic<br />

functions <strong>to</strong> model the population of Canada.<br />

CP10. Graph both functions on the same axes.<br />

CP11. Determine the polynomial function that represents the average of<br />

the previous models, and graph the new function.<br />

CP12. Use the new function <strong>to</strong> estimate the population of Canada in<br />

2001, 2006, and 2016. Compare your results with other data on<br />

the Internet. How do they compare<br />

38 CHAPTER 1 POLYNOMIAL FUNCTION MODELS

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