Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
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3.3 Nodal Analysis with Voltage Sources 91<br />
Find the node voltages in the circuit <strong>of</strong> Fig. 3.12. Example 3.4<br />
3 Ω<br />
+ v x −<br />
20 V<br />
3v<br />
6 Ω<br />
x<br />
2<br />
1 + − + − 4<br />
2 Ω 10 A<br />
4 Ω<br />
1 Ω<br />
Figure 3.12<br />
For Example 3.4.<br />
Solution:<br />
Nodes 1 and 2 form a supernode; so do nodes 3 and 4. We apply KCL<br />
to the two supernodes as in Fig. 3.13(a). At supernode 1-2,<br />
i 3 10 i 1 i 2<br />
Expressing this in terms <strong>of</strong> the node voltages,<br />
or<br />
At supernode 3-4,<br />
v 3 v 2<br />
6<br />
10 v 1 v 4<br />
3<br />
v 1<br />
2<br />
5v 1 v 2 v 3 2v 4 60<br />
(3.4.1)<br />
or<br />
i 1 i 3 i 4 i 5 1<br />
v 1 v 4<br />
3<br />
v 3 v 2<br />
6<br />
4v 1 2v 2 5v 3 16v 4 0<br />
v 4<br />
1 v 3<br />
4<br />
(3.4.2)<br />
3 Ω<br />
+ v<br />
i x −<br />
1<br />
i 1<br />
6 Ω<br />
v<br />
v 2 v 3 1 v 4<br />
i i<br />
i 3 3<br />
2 i 5 i 4<br />
2 Ω 10 A<br />
4 Ω 1 Ω<br />
+<br />
3 Ω<br />
v x −<br />
Loop 3<br />
20 V<br />
i 3<br />
3v x<br />
+<br />
+ −<br />
+ −<br />
+<br />
6 Ω<br />
+<br />
+<br />
v 1 Loop 1 v 2 v 3 Loop 2 v 4<br />
− − − −<br />
(a)<br />
Figure 3.13<br />
Applying: (a) KCL to the two supernodes, (b) KVL to the loops.<br />
(b)