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Fundamentals of Electric Circuits

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3.4 Mesh Analysis 97<br />

But at node A, I o i 1 i 2 , so that<br />

4(i 1 i 2 ) 12(i 3 i 1 ) 4(i 3 i 2 ) 0<br />

or<br />

i 1 i 2 2i 3 0<br />

(3.6.3)<br />

In matrix form, Eqs. (3.6.1) to (3.6.3) become<br />

We obtain the determinants as<br />

¢ <br />

418 30 10 114 22 50 192<br />

12 5 6<br />

0 19 2<br />

¢ 1 5 0 1 25<br />

456 24 432<br />

12 5 6 <br />

<br />

<br />

0 19 2 <br />

<br />

¢ 2 <br />

¢ 3 <br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

<br />

11 5 6<br />

£ 5 19 2<br />

1 1 2<br />

11 5 12<br />

5 19 0<br />

5 1 1 05<br />

11 5 12<br />

5 19 0<br />

We calculate the mesh currents using Cramer’s rule as<br />

i 1 ¢ 1<br />

,<br />

¢ 432<br />

192 2.25 A, i 2 ¢ 2<br />

¢ 144<br />

192 0.75 A<br />

Thus, I o i 1 i 2 1.5 A.<br />

11 5 6<br />

5 19 2<br />

5 1 1 25<br />

11 5 6<br />

5 19 2<br />

11 12 6<br />

5 0 2<br />

5 1 0 25<br />

11 12 6<br />

5 0 2<br />

i 1<br />

§ £ i 2 § £<br />

i 3<br />

<br />

<br />

<br />

i 3 ¢ 3<br />

¢ 288<br />

192 1.5 A<br />

12<br />

0 §<br />

0<br />

24 120 144<br />

<br />

<br />

<br />

60 228 288

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