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Fundamentals of Electric Circuits

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Review Questions 113<br />

4. A supermesh consists <strong>of</strong> two meshes that have a (dependent or<br />

independent) current source in common.<br />

5. Nodal analysis is normally used when a circuit has fewer node<br />

equations than mesh equations. Mesh analysis is normally used<br />

when a circuit has fewer mesh equations than node equations.<br />

6. Circuit analysis can be carried out using PSpice.<br />

7. DC transistor circuits can be analyzed using the techniques covered<br />

in this chapter.<br />

Review Questions<br />

3.1 At node 1 in the circuit <strong>of</strong> Fig. 3.46, applying KCL<br />

gives:<br />

(a) 2 12 v 1<br />

3<br />

(b) 2 v 1 12<br />

3<br />

(c) 2 12 v 1<br />

3<br />

(d) 2 v 1 12<br />

3<br />

v 1<br />

6 v 1 v 2<br />

4<br />

v 1<br />

6 v 2 v 1<br />

4<br />

0 v 1<br />

6<br />

0 v 1<br />

6<br />

v 1 v 2<br />

4<br />

v 2 v 1<br />

4<br />

3.3 For the circuit in Fig. 3.47, v 1 and v 2 are related as:<br />

(a) v 1 6i 8 v 2 (b) v 1 6i 8 v 2<br />

(c) v 1 6i 8 v 2 (d) v 1 6i 8 v 2<br />

v 1<br />

6 Ω<br />

8 V<br />

12 V + i<br />

− 4 Ω<br />

Figure 3.47<br />

For Review Questions 3.3 and 3.4.<br />

− +<br />

v 2<br />

12 V + −<br />

2 A<br />

8 Ω<br />

3 Ω v 1 4 Ω<br />

1 2<br />

v 2<br />

6 Ω 6 Ω<br />

3.4 In the circuit <strong>of</strong> Fig. 3.47, the voltage is:<br />

(a) 8 V (b) 1.6 V<br />

(c) 1.6 V<br />

(d) 8 V<br />

3.5 The current i in the circuit <strong>of</strong> Fig. 3.48 is:<br />

(a) 2.667 A (b) 0.667 A<br />

(c) 0.667 A<br />

(d) 2.667 A<br />

v 2<br />

Figure 3.46<br />

For Review Questions 3.1 and 3.2.<br />

3.2 In the circuit <strong>of</strong> Fig. 3.46, applying KCL at node 2<br />

gives:<br />

v 2 v 1<br />

(a)<br />

4<br />

v 1 v 2<br />

(b)<br />

4<br />

v 1 v 2<br />

(c)<br />

4<br />

(d) v 2 v 1<br />

4<br />

v 2<br />

8 v 2<br />

6<br />

v 2<br />

8 v 2<br />

6<br />

12 v 2<br />

8<br />

v 2 12<br />

8<br />

v 2<br />

6<br />

v 2<br />

6<br />

4 Ω<br />

10 V + − i<br />

+ − 6 V<br />

2 Ω<br />

Figure 3.48<br />

For Review Questions 3.5 and 3.6.<br />

3.6 The loop equation for the circuit in Fig. 3.48 is:<br />

(a) 10 4i 6 2i 0<br />

(b) 10 4i 6 2i 0<br />

(c) 10 4i 6 2i 0<br />

(d) 10 4i 6 2i 0

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