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Fundamentals of Electric Circuits

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3.9 Applications: DC Transistor <strong>Circuits</strong> 111<br />

For the BJT circuit in Fig. 3.43, and V BE 0.7 V. Find v o .<br />

b 150 Example 3.13<br />

Solution:<br />

1 kΩ<br />

1. Define. The circuit is clearly defined and the problem is clearly<br />

stated. There appear to be no additional questions that need to<br />

be asked.<br />

2. Present. We are to determine the output voltage <strong>of</strong> the circuit<br />

shown in Fig. 3.43. The circuit contains an ideal transistor with<br />

b 150 and V BE 0.7 V.<br />

3. Alternative. We can use mesh analysis to solve for v o . We can<br />

replace the transistor with its equivalent circuit and use nodal<br />

analysis. We can try both approaches and use them to check<br />

each other. As a third check, we can use the equivalent circuit<br />

and solve it using PSpice.<br />

4. Attempt.<br />

+<br />

2 V<br />

−<br />

100 kΩ<br />

Figure 3.43<br />

For Example 3.13.<br />

200 kΩ<br />

+<br />

v o<br />

−<br />

16 V<br />

+<br />

−<br />

■ METHOD 1<br />

Working with Fig. 3.44(a), we start with the first loop.<br />

2 100kI 1 200k(I 1 I 2 ) 0<br />

or<br />

3I 1 2I 2 2 10 5<br />

(3.13.1)<br />

1 kΩ<br />

+<br />

2 V<br />

−<br />

+<br />

2 V<br />

−<br />

+<br />

100 kΩ<br />

v o I 3<br />

−<br />

I 1 200 kΩ I2<br />

(a)<br />

1 kΩ<br />

100 kΩ V 1 I B<br />

150I B +<br />

+<br />

v o<br />

200 kΩ 0.7 V<br />

−<br />

−<br />

16 V<br />

+<br />

−<br />

16 V<br />

+<br />

−<br />

(b)<br />

R1<br />

700.00mV<br />

14.58 V<br />

R 3<br />

100k<br />

+<br />

2 V<br />

−<br />

R2 200k<br />

+<br />

0.7 V<br />

−<br />

F1<br />

1k<br />

16 V<br />

+<br />

−<br />

F<br />

(c)<br />

Figure 3.44<br />

Solution <strong>of</strong> the problem in Example 3.13: (a) Method 1, (b) Method 2,<br />

(c) Method 3.

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