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CONTENTS - Department of Mathematics and Statistics - University ...

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SOLUTIONS<br />

−8698.33<br />

1. (a) b YX = =− 0.054<br />

160613.28<br />

ŷ = 47.67 – 0.054(x – 831.4)<br />

= 92.566 – 0.054x<br />

(b) Estimated st<strong>and</strong>ard error =<br />

∑<br />

se<br />

( x − x)<br />

i<br />

2<br />

where<br />

55.25/16<br />

That is, st<strong>and</strong>ard error = = 0.004637<br />

160613.28<br />

A 95% confidence interval for the true slope is<br />

–0.054 ± t 16 (0.004637) where t 16 = 2.120<br />

That is, –0.054 ± 0.0098<br />

giving – 0.064 < β YX < –0.044<br />

y ˆ<br />

2 i<br />

− yi<br />

e<br />

=<br />

s<br />

∑<br />

( )<br />

n − 2<br />

(c) The maximum volume <strong>of</strong> oxygen uptake is smaller for men who take longer to run 2<br />

miles.<br />

2<br />

(d)<br />

Oxygen uptake reduces by 50(0.054) = 2.7 units.<br />

The 95% confidence interval extends from 50(0.064) to 50(0.044) or a reduction from<br />

2.2 to 3.2 units.<br />

(e) When x = 660 seconds, ŷ = 92.566 – 0.054(660) = 56.93<br />

The 95% confidence interval is<br />

1<br />

56.93 ± t s 1+ +<br />

( x − x)<br />

2<br />

k<br />

16 e<br />

2<br />

n ( xi<br />

− x)<br />

∑<br />

That is, 56.93 ± 2.120<br />

or 56.93 ± 4.38<br />

52.55 < ŷ<br />

660<br />

< 61.31<br />

1 (660 − 831.4)<br />

55.25/16 1+ + 18 160613.28<br />

2<br />

372<br />

Section 9

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