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Statistical thermodynamics 1: the concepts - W.H. Freeman

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PC8eC16 1/26/06 14:34 Page 585<br />

DISCUSSION QUESTIONS 585<br />

6<br />

1<br />

Partition function, q<br />

4<br />

2<br />

Entropy, SNk /<br />

0.5<br />

10<br />

5<br />

0<br />

/kT<br />

5 10<br />

0 0.5 1<br />

Internal energy, UN / <br />

<br />

Internal energy, UN /<br />

Entropy., SNk /<br />

1<br />

0.5<br />

10<br />

1<br />

0.5<br />

10<br />

5<br />

5<br />

0<br />

/kT<br />

0<br />

/kT<br />

Fig. 16.20 The partition function, internal energy, and entropy of<br />

a two-level system extended to negative temperatures but plotted<br />

against β = 1/kT (modified here to <strong>the</strong> dimensionless quantity ε/kT).<br />

5<br />

5<br />

10<br />

10<br />

Fig. 16.21 The variation of <strong>the</strong> entropy with internal energy for a<br />

two-level system extended to negative temperatures.<br />

to <strong>the</strong> shift towards population of <strong>the</strong> upper state alone as more<br />

energy is packed into <strong>the</strong> system.<br />

The phenomenological laws of <strong><strong>the</strong>rmodynamics</strong> survive largely<br />

intact at negative temperatures. The First Law (in essence, <strong>the</strong><br />

conservation of energy) is robust, and independent of how<br />

populations are distributed over states. The Second Law survives<br />

because <strong>the</strong> definition of entropy survives (as we have seen above).<br />

The efficiency of heat engines (Section 3.2), which is a direct<br />

consequence of <strong>the</strong> Second Law, is still given by 1 − T cold /T hot .<br />

However, if <strong>the</strong> temperature of <strong>the</strong> cold reservoir is negative, <strong>the</strong>n<br />

<strong>the</strong> efficiency of <strong>the</strong> engine may be greater than 1. This condition<br />

corresponds to <strong>the</strong> amplification of signals achieved in lasers.<br />

Alternatively, an efficiency greater than 1 implies that heat can be<br />

converted completely into work provided <strong>the</strong> heat is withdrawn from<br />

a reservoir at T < 0. If both reservoirs are at negative temperatures,<br />

<strong>the</strong>n <strong>the</strong> efficiency is less than 1, as in <strong>the</strong> <strong>the</strong>rmal equilibrium case<br />

treated in Chapter 3. The Third Law requires a slight amendment<br />

on account of <strong>the</strong> discontinuity of <strong>the</strong> populations across T = 0: it is<br />

impossible in a finite number of steps to cool any system down to<br />

+0 or to heat any system above −0.<br />

Discussion questions<br />

16.1 Describe <strong>the</strong> physical significance of <strong>the</strong> partition function.<br />

16.2 Explain how <strong>the</strong> internal energy and entropy of a system composed of<br />

two levels vary with temperature.<br />

16.3 Enumerate <strong>the</strong> ways by which <strong>the</strong> parameter β may be identified with<br />

1/kT.<br />

16.4 Distinguish between <strong>the</strong> zipper and Zimm–Bragg models of <strong>the</strong><br />

helix–coil transition.<br />

16.5 Explain what is meant by an ensemble and why it is useful in statistical<br />

<strong><strong>the</strong>rmodynamics</strong>.<br />

16.6 Under what circumstances may identical particles be regarded as<br />

distinguishable

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