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TMdrive-MVG Series Catalog - Tmeic.com

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Energy Savings Payback Calculations<br />

Appendix. Energy Savings Payback Calculations<br />

Replacing a mechanical speed control device with an adjustable speed drive usually produces large energy savings plus a<br />

reduction in maintenance costs. This appendix outlines how the energy savings can be calculated as follows:<br />

1. Calculate the cost of energy used by the electric drive speed control system, outlined on this page.<br />

2. Calculate the cost of energy used by the mechanical speed control system, outlined on the next page.<br />

The difference is the energy cost savings. Typical power consumption curves for pumps and fans are shown below.<br />

Power (pu)<br />

1.0<br />

0.8<br />

o<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

Pump with<br />

throttling valve<br />

Energy<br />

savings<br />

o<br />

o<br />

o<br />

o<br />

20% 40% 60% 80% 100%<br />

o<br />

Electrical<br />

ASD<br />

RPM/Flow (pu)<br />

Example: Pump power savings using electric drive (ASD)<br />

Power (pu)<br />

1.0<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

Fan with<br />

damper<br />

Energy<br />

savings<br />

Fan with inlet<br />

guide vanes<br />

Electrical<br />

ASD<br />

0% 20% 40% 60% 80% 100%<br />

RPM / Flow (pu)<br />

Example: Fan power savings using electric drive (ASD)<br />

Below is an example of the energy cost calculation for a pump driven by a motor and electric drive. The calculation for the<br />

mechanical system is similar and is described on the next page. Since energy consumption varies with speed and flow, you<br />

need the load profile table which shows the number of hours running at the various flows. Refer to the example below.<br />

Energy Cost for Electric Drive Speed Control<br />

Step 9<br />

Step 8<br />

Step 6<br />

Energy Cost<br />

Input kW<br />

$0.07/kWh<br />

1,212<br />

Energy<br />

Drive<br />

Cost<br />

Efficiency<br />

$371,500/yr<br />

96.5%<br />

Step 10<br />

Step 7<br />

Calculation<br />

details<br />

Three-Phase<br />

Electric Supply<br />

Electric<br />

Adjustable<br />

Speed<br />

Drive<br />

Motor<br />

Step 4<br />

Motor<br />

Input kW<br />

Shaft kW<br />

1,169<br />

Motor<br />

1,119<br />

Input<br />

Efficiency<br />

Shaft hp<br />

95.7%<br />

1,500<br />

Step 5<br />

Step 3<br />

Electric Motor<br />

Shaft<br />

Variable speed motor<br />

Pump<br />

Chart & Load<br />

Curve<br />

Step 2<br />

Variable speed pump<br />

Step1<br />

Desired<br />

Flow<br />

90%<br />

Start<br />

here<br />

Output Flow<br />

and Pressure<br />

Step 1<br />

Step 2<br />

Step 3<br />

Select the desired pump<br />

output flow, for example<br />

90%, and number of<br />

hours/day at this flow,<br />

for example 12.<br />

Obtain the variable<br />

speed pump<br />

performance chart and<br />

the load pressure-flow<br />

curve, which is the flow<br />

resistance of the<br />

process being fed.<br />

Find the pump input<br />

power.<br />

Percent Pressure (or Head)<br />

100<br />

Pump Performance Chart & Load Curve<br />

Load Curve<br />

(Process)<br />

Pump Chart<br />

Speed N2<br />

1,800 rpm<br />

80<br />

B<br />

1,500 hp<br />

A<br />

90 100<br />

Percent Output Flow<br />

Pump hp<br />

2,000<br />

Overlay the load pressure-flow curve on the pump<br />

chart and find the pump input shaft horsepower at<br />

the 90% flow (point B). You need the load profile.<br />

See example below.<br />

Pump input power at N2 rpm = 1,500 hp<br />

at point B, 90% flow.<br />

Daily Load Profile (example)<br />

Operation<br />

Hours/day<br />

Percent<br />

Flow<br />

5<br />

100%<br />

12<br />

90%<br />

5<br />

80%<br />

1<br />

70%<br />

1<br />

60%<br />

Step 4<br />

Convert the input shaft<br />

horsepower to shaft kW<br />

Conversion: Horsepower x 0.746 = kW<br />

Input shaft kW = 1,500 hp x 0.746 = 1,119 kW<br />

Step 5<br />

Step 6<br />

Obtain the electric<br />

motor efficiency<br />

Example: Induction motor efficiency 95.7% from<br />

manufacturer's data sheets (find at each RPM)<br />

Motor input power = 1,119 kW/0.957 Efficiency<br />

= 1,169 kW<br />

Step 7<br />

Step 8<br />

Obtain the adjustable<br />

speed drive efficiency<br />

Example: Drive efficiency 96.5% from manufacturer's<br />

data sheets (find at each RPM)<br />

Drive input power = 1,169 kW/0.965 Efficiency<br />

= 1,212 kW<br />

Step 9<br />

Step 10<br />

Obtain the electric<br />

power cost<br />

Example: Energy cost = $0.07/kWh. Calculate cost for<br />

the hours at this flow from load profile; in this example it<br />

is 12 hours/day.<br />

Energy cost = 1,212 kW x 0.07$kWh x 12 hrs/day<br />

x 365 days per year = $371,500 per year. (Repeat<br />

calculation for other flows in load profile and total).<br />

15

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