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Exercises with Magnetic Monopoles - Kurt Nalty

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The magnitude of torsion in three dimensions is<br />

τ =<br />

⃗j · (⃗a × ⃗v)<br />

(⃗a × ⃗v) · (⃗a × ⃗v)<br />

⃗j = d⃗a<br />

dt<br />

F<br />

⃗a = ⃗ m = µq eq m<br />

4π<br />

⃗j = µq eq m<br />

4πm<br />

= µq eq m<br />

4πm<br />

= µq eq m<br />

4πm<br />

= µq eq m<br />

4πm<br />

1<br />

[ m<br />

⃗a × ⃗r<br />

r 3<br />

⃗v × ⃗r<br />

r 3<br />

− 3 r 4 dr<br />

dt (⃗v × ⃗r) ]<br />

[ ⃗a × ⃗r<br />

− 3 ]<br />

⃗r · ⃗v<br />

r 3 r 4 r (⃗v × ⃗r) [ ⃗a × ⃗r<br />

− 3 ]<br />

× ⃗r)<br />

(⃗r · ⃗v)(⃗v<br />

r 3 r2 r<br />

[ ]<br />

3<br />

⃗a × ⃗r 3(⃗r · ⃗v)<br />

− ⃗a<br />

r 3 r 2<br />

Before proceding, I want to comment on these jerk terms. The left portion,<br />

⃗a × ⃗r, is a turning term, bring ⃗ J perpendicular to ⃗a and resulting in<br />

constant acceleration for the electron. The right hand term, −3⃗a(⃗r · ⃗v)/r 2 ,<br />

is a strong damping term for radial motion. I’ll do some simulations shortly,<br />

but at first glance, the jerk should quickly circularize the electron in a flat<br />

orbit.<br />

Simplifying a bit, since ⃗a ⊥ ⃗v,<br />

τ =<br />

⃗j · (⃗a × ⃗v)<br />

(⃗a × ⃗v) · (⃗a × ⃗v)<br />

= ⃗ j · (⃗a × ⃗v)<br />

a 2 v 2<br />

Continuing <strong>with</strong> our development for the torsion term, ⃗a×⃗v is perpendicular<br />

to ⃗a, so the second term in the jerk formula will drop out.<br />

22

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