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Lecture 3 Pseudo-random number generation

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We are going to apply this result for the case where A = [0, 1] 2<br />

and f(x) = 1 for all x ∈ A (i.e. we start with a two-dimensional<br />

uniformly distributed <strong>random</strong> variable) and choose the<br />

transformation<br />

x ↦→ h(x) =<br />

�√−2 �<br />

ln x1 cos(2πx2),<br />

√<br />

−2 ln x1 sin(2πx2).<br />

The inverse of this transformation is given by<br />

y ↦→ h −1 �<br />

exp(−�y�<br />

(y) =<br />

2 �<br />

/2),<br />

arctan(y2/y1)/2π.<br />

Computational Finance – p. 26

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