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Series CHL/CHH - Warden Fluid Dynamics

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Catalog M1136Permissible Energy of InertiaCompact Hydraulic Cylinders<strong>Series</strong> <strong>CHL</strong> & <strong>CHH</strong>Permissible piston impact speed is limited due to the size of the load attached to the rod end. That speed should be below thebold lines on the chart.<strong>CHL</strong>10050ø 40 ø 32Speed(mm/s)ø 50ø 25 ø 20ø 80 ø 100ø 63108 1 51050100 500 1000Load (kg)<strong>CHH</strong>10050ø 80Speed(mm/s)10ø 20ø 63ø 40ø 25ø 50ø 328 1 510Load (kg)50100 500 1000Theoretical Push and Pull ForcesGeneral FormulaThe cylinder output forces are derived from the formula:F =P x A10000Where F = Force in kN.P = Pressure at the cylinder in bar.A = Effective area of cylinder piston insquare mm.If the piston rod is in compression, use the ‘Push Force’ tablebelow, as follows:1. Identify the operating pressure closest to that required.2. In the same column, identify the force required to movethe load (always rounding up).3. In the same row, look along to the cylinder bore required.Push ForceBore BoreCylinder Push Force in kNø Area 10 40 63 100 125 160mm sq. mm bar bar bar bar bar bar20 314 0.3 1.3 2.0 3.1 3.9 5.025 491 0.5 2.0 3.1 4.9 6.1 7.932 804 0.8 3.2 5.1 8.0 10.1 12.940 1257 1.3 5.0 7.9 12.6 15.7 20.150 1964 2.0 7.9 12.4 19.6 24.6 31.463 3118 3.1 12.5 19.6 31.2 39.0 49.980 5027 5.0 20.1 31.7 50.3 62.8 80.4100 7854 7.9 31.4 49.5 78.5 98.2 125.7If the cylinder envelope dimensions are too large for theapplication, increase the operating pressure, if possible,and repeat the exercise.If the piston rod is in tension, use the ‘Deduction for PullForce’ table. The procedure is the same but, due to thereduced area caused by the piston rod, the force availableon the ‘pull’ stroke will be smaller. To determine the pull force:1. Follow the procedure for ‘push’ applications asdescribed above.2. Using the ‘pull’ table, identify the force indicatedaccording to the rod and pressure selected.3. Deduct this from the original ‘push’ force. The resultant isthe net force available to move the load.If this force is not large enough, repeat the process andincrease the system operating pressure or cylinder diameterif possible. For assistance, contact your local authorizeddistributor.Deduction for Pull ForcePistonRodømmPistonRodAreasq. mmReduction in Force in kN10 40 63 100 125 160bar bar bar bar bar bar12 113 0.1 0.5 0.7 1.1 1.4 1.814 154 0.2 0.6 1.0 1.5 1.9 2.518 255 0.3 1.0 1.6 2.6 3.2 4.122 380 0.4 1.5 2.4 3.8 4.8 6.128 616 0.6 2.5 3.9 6.2 7.7 9.936 1018 1.0 4.1 6.4 10.2 12.7 16.345 1591 1.6 6.4 10.0 15.9 19.9 25.556 2463 2.5 9.9 15.5 24.6 30.8 39.417Miller <strong>Fluid</strong> PowerDes Plaines, ILToronto, Ontario Canada

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