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Vol. 10 No 5 - Pi Mu Epsilon

Vol. 10 No 5 - Pi Mu Epsilon

Vol. 10 No 5 - Pi Mu Epsilon

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TOMFORDE, SELF-SIMILARITY 385<strong>No</strong>te that this matrix does follow the usual matrix indexing with (0,O) at theupper left. Instead it follows the "Cartesian" pattern with (0, 0) at the bottom left.Also let Dn be generated by Dn., in the following way:where Dn is a squarematrix comprised ofb,,+, x bn+, submatrices.Then for any whole number n, when the entries of a generalized arithmeticaltriangle generated by a regularly divisible sequence are written asDn has a 1 corresponding to those elements which are not congruent to 0 modulop and a 0 corresponding to those elements which are congruent to 0 modulo p, forany prime p.Proof: This theorem can be proven by induction. It will be similar in structure tothat of a less general theorem proven by A. Jaeger and K. Saldanha in anunpublished paper [5].Base case: The proof for Do is trivial since by the definition of Do the theorem istrue.Inductive step: Assume the theorem true for Dn.,. Recall the definition of Dn and386 PI MU EPSILON JOURNALconsider the (i, j)th element from the bottom left (i.e., starting at the bottom leftcoiner, count i elements (not submatrices) over and j elements up). We can writei andj asi = x,,Bn + x,,-,Bn-,+ ... + x,B, + x,,J = ynBn + ~n-lBn-I + .. . + YIBI + YO 0 5 x,,, ~ i ^ , &+Iso that the xkYs are the digits of i and the ykYs are the digits ofj in a mixed radixsystem. <strong>No</strong>w the values of these digits tell which submatrices the (i, j)th elementfrom the bottom belongs to. For instance, this element belongs to the (x,,, yn)thsubmatrix of Dm the (x,,-,, yn.,)th submatrix of Dd, etc.It is also clear that this element corresponds to C(j, i) = C(i, j) in the generalizedarithmetical triangle. We shall look at the following two cases:Case 1: If x,, + yn s b, , then we know that the elements is in one of thesubmatrices above the diagonal in the Dn matrix. We also know that i + j mustyield at least one cany in mixed radix addition (since x,, + yn 2- bn). Therefore, bythe corollary to Knuth and Wilts theorem, C(i, j) is divisible by p. Hence C(i, j)corresponds to a 0 in the matrix Dn and we can conclude that every element abovethe diagonal corresponds to 0.Case 2: If x,, + yn < b,,, then the (i, j)th element from the bottom is on or below thediagonal submatrices of Dn . <strong>No</strong>w consider i ' and j ' wherei' = x,,-lBn-l + yn-2Bn.2 + . . . + x,B1 + x,,j' = yn-lBn-1 + yn-2Bn-2 + ... + ylBl +yo.<strong>No</strong>tice that i = x,,Bn + i' and j = yn Bn + j'. As mentionsed earlier (xn , yn )determines the location of a Dn.l submatrix and (i' j') determines the location ofan element within this submatrix.<strong>No</strong>w suppose that i' + j ' produces no cany. Since x, + yn < bn there is nocany out of the B, position so we know i + j yields no cany. On the other hand,if i' + j' produces a cany, then i + j yields at least one cany. Therefore i + j andi' + j' when added in this mixed radix system either both yield no carries or bothyield at least one cany. Thus xp(i, j) = xp (i ', j ') and the elements below diediagonal in the matrix Dn (and which are constructed by the submatrices H, )correspond to the elements of the generalized arithmetical triangle.Conclusion: By induction the matrix Dn does in fact correspond 0's to thoseelements in the generalized arithmetical triangle congruent to O(mod p) and 1's toall other elements.Theorem 7: Let Nn be the number of nonzero elements in the matrix Dn and let

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