BENNINK. RED LIGHT, GREEN LIGHT 357block distance. The horizontal separation between the legs of the " X is the timeinterval A?, which is shown as a triangular-looking function of s in the right halfof Figure 4. As one can see from the right half of the figure, the time intervalbetween northbound and southbound trajectories is never more than half a periodsince the space "wraps around". The challenge is to determine if and how greenlight regions (solid horizontal bars marked with a "G") may be placed so as tointersect both trajectories at each intersection (thin horizontal lines).If green lights were to last at least half a period, the problem would betrivial; no matter how the intersections were translated, the green light durationwould always exceed A?. The fact that tà is short of half a period by the amount/+means there are two forbidden zones (shaded horizontal bars) where the greenregion is not long enough to catch both trajectories; i.e., where t_ < A?. Theproblem has a solution if we can translate the intersections so that none of themfalls in a forbidden zone. Geometrical analysis of Figure 4 reveals that each358 PI MU EPSILON JOURNALforbidden zone extends over a distance vmJy., on the s axis. Clearly theintersection spacing b must be at least as large as this. But since two forbiddenzones must be avoided, the condition which is sufficient to guarantee a solutionbecomes b > 2v,,,ofyet- Solving this inequality for,&,equation (3), we find that a solution exists as long asdaop s b - 2(w + L).and combining it withFigure 4.Figure 3.In practice, this is never a concern. (If you cannot stop your car in a little undera block, either you are driving too fast or you need new brakes!) For a concreteexample, letN= 4, b = 3309, UJ = 3OJ, L = 151, vmw = 30mihr = 44ft/s, andubr~ = 15p. Then T = 30s and from equation (3) we have&, s 2.5s, whichmeans tgm s 12.5s. Over every 4-block stretch of road there are two sectionsvm&, = 1 lo/? long which periodic northbound and southbound cars traverse attimes more than 12.5s apart. If the lights are scheduled properly, such cars willbe able to proceed &om intersection to intersection without having to stop for ared light.
BENNINK, RED LIGHT, GREEN LIGHT 359As it turns out, many solutions exist. The best ones seem to be obtainedwith N = 2,3,4,6, or 8. (For typical real-world parameters and N = 1, the light.change too quickly. For N > 8, the lights can take several minutes to turn, andmost people do not like to wait that long.) Acceptable solutions are optimized byadjusting the placement of intersections so that the sum of the time intervals acrossall intersections is a minimum. That way, one creates the widest green lightintervals through which caravans of many cars can proceed uninhibited. Thephase delay for each intersection is then determined by the times at which thetrajectories cross the intersection line.Figures 5 and 6 show typical timing schemes. (The vertical axis isqualitative rather than quantitative, and refers to the particular light within the N-intersection pattern. For each light, a high level represents a green light, a middlelevel indicates a yellow light, and a low level indicates a red light.) As one cansee, traffic signals are generally staggered rather than aligned. Some lights haveidentical phases, however, because northbound and southbound traffic trajectoriesare symmetrical and the optimization algorithm favors neither direction.Incidentally, Figure 5 was generated using N = 3, b = 330ft, and v = 30mi/hr =44Ws. Thus T = 7V6h = 22.5s, as shown in the graph. Figure 6 was generatedwith M, yielding the period T = 30s.360 PI MU EPSILON JOURNALA Complete Timing Schedule: Four-way traffic.Once we have determined a working time schedule for traffic signalsalong a single street (1 dimension), we can extend the schedule to accommodatecity traffic (2 dimensions). An example will suffice to show how this isaccomplished.Consider the caseN = 4. Assume that we have come up with appropriatephase delays for traffic signals along a single street, and say that northbound trafficencounters the sequence of signals with phase delays a, Q], 02, 0, , O0 , ... .(Southbound traffic encounters the same sequence in the opposite order.) If weapply this 4-element sequence to adjacent N-S streets but stagger it as shown inequation (5), then the sequence of phases holds for E-W streets as well. Columnsof the 4 x 4 lattice represent 4-intersection segments of adjacent N-S streets; rowsrepresent segments of adjacent E-W streets. <strong>No</strong>rthbound and eastbound traffic(i.e., traffic traversing the lattice up or to the right) will encounter the same phasedifferences between consecutive lights; the same holds true for southbound andwestbound traffic.5.0Typical 4-intersection Timing Scheme~ l l l l l l l l l l ~ l l l l ~ l l l l ~ l l l l ~ l l l l ~ l l l l ~ l l ll.ok-l'0.02'-!0 <strong>10</strong> 20 30 40 50 60 70 60 SOtime (s)Figure 5Figure 6.
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