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Schaum's Outline of Theory and Problems of Beginning Calculus

Schaum's Outline of Theory and Problems of Beginning Calculus

Schaum's Outline of Theory and Problems of Beginning Calculus

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Chapter 15The Chain RulelS.lCOMPOSITE FUNCTIONSThere are still many functions whose derivatives we do not know how to calculate; for example,(i) J- (ii) $Z7 (iii) (x2 + 3x - 1)23In case (iii), we could, <strong>of</strong> course, multiply x2 + 3x - 1 by itself 22 times <strong>and</strong> then differentiate theresulting polynomial. But without a computer, this would be extremely arduous.The above three functions have the common feature that they are combinations <strong>of</strong> simpler functions:(i) d m ’is the result <strong>of</strong> starting with the functionf(x) = x3 - x + 2 <strong>and</strong> then applying thefunction g(x) = fi to the result. Thus,Jx’ - x + 2 = g(f(x))(ii) 15 is the result <strong>of</strong> starting with the function F(x) = x + 4 <strong>and</strong> then applying the functionG(x) = fi. Thus,dZ4 = G(F(x))(iii) (x2 + 3x - 1)23 is the result <strong>of</strong> beginning with the function H(x) = x2 + 3x - 1 <strong>and</strong> then applyingthe function K(x) = x23. Thus,(x2 + 3x - 1)23 = K(H(~))Functions that are put together this way out <strong>of</strong> simpler functions are called composite functions.Definition: Iff <strong>and</strong> g are any functions, then the composition g 0 f <strong>of</strong>f <strong>and</strong> g is the function such thatThe “process” <strong>of</strong> composition is diagrammed in Fig. 15- 1.(9 O f K 4 = g(f(x))Fig. 15-1EXAMPLES(a) Letf(x) = x - 1 <strong>and</strong> g(x) = x2. Then,(9 0 fXx) = g(f(x)) = g(x - 1) = (X -On the other h<strong>and</strong>,(f O sKx) = f(g(4) =f(x2) = x2 - 1Thus,fo g <strong>and</strong> g <strong>of</strong>are not necessarily the same function (<strong>and</strong> usually they are not the same).116

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