11.07.2015 Views

Schaum's Outline of Theory and Problems of Beginning Calculus

Schaum's Outline of Theory and Problems of Beginning Calculus

Schaum's Outline of Theory and Problems of Beginning Calculus

SHOW MORE
SHOW LESS
  • No tags were found...

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

CHAP. 221HIGHER-ORDER DERIVATIVES163From (0), we may substitute 9 for x2 + y2,9y” - -Y3AccelerationLet an object move along a coordinate axis according to the equation s =f(t), where s is thecoordinate <strong>of</strong> the object <strong>and</strong> t is the time. From Chapter 18, the object’s velocity is given bydsU=--- -f ‘@)dtThe rate at which the velocity changes is called the acceleration a.dv d2sDefinition: a = - dt = - dt2 -f’’(t)-EXAMPLES(a) For an object in free fall, s = so + oo t - 16t2, where s, measured in feet, is positive in the upward direction <strong>and</strong>t is measured in seconds. Recall that so <strong>and</strong> oo denote the initial position <strong>and</strong> velocity; that is, the values <strong>of</strong> s<strong>and</strong> o when t = 0. Hence,dsU=-- - UO - 32tdtdoa=-= - 32dtThus, the velocity decreases by 32 feet per second every second. This is sometimes expressed by saying that the(downward) acceleration due to gravity is 32 feet per second per second, which is abbreviated as 32 ft/sec2.(b) An object moves along a straight line according to the equation s = 2t3 - 3t2 + t - 1. Then,doa=-=l2t-6dtIn this case, the acceleration is not constant. Notice that a > 0 when 12t - 6 > 0, or t > 4. This implies (byTheorem 17.3) that the velocity is increasing for t > 4.Solved <strong>Problems</strong>22.1 Describe all the derivatives (first, second, etc.) <strong>of</strong> the following functions:1 YA(a) f(x) = ; x4 - 5x - a (b) f(x) = x+l

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!