CBSEi Class 10 Sequences (AP and GP) CORE
CBSEi Class 10 Sequences (AP and GP) CORE
CBSEi Class 10 Sequences (AP and GP) CORE
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
Here a = 2<br />
6 ( 2) = 3<br />
18 ( 6) = 3<br />
54 ( 18) = 3<br />
So, it is a <strong>GP</strong> with common ratio(r) = 3.<br />
(v) …<br />
Here a =<br />
÷ = × = …<br />
× =<br />
So, it is not a <strong>GP</strong> as ≠ .<br />
From the numerators, it appears as the numbers are in <strong>GP</strong> but in fact they are not.<br />
Example 16: Find the value of k for which 4k + 4, 6k 2, 9k 13 form a <strong>GP</strong>.<br />
Solution: Since 4k + 4, 6k 2 <strong>and</strong> 9k 13 form a <strong>GP</strong>,<br />
therefore, = (=r)<br />
(6k 2) (6k 2) = (4k + 4) (9k 13)<br />
36k 2 24k + 4 = 36k 2 52k + 36k 52<br />
= 36k 2 16k 52<br />
8k = 56<br />
k = 7<br />
55