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Manin obstruction to strong approximation for homogeneous spaces

Manin obstruction to strong approximation for homogeneous spaces

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<<strong>strong</strong>>Manin</<strong>strong</strong>> <<strong>strong</strong>>obstruction</<strong>strong</strong>> <<strong>strong</strong>>to</<strong>strong</strong>> <strong>strong</strong> <strong>approximation</strong> <strong>for</strong> <strong>homogeneous</strong> <strong>spaces</strong> 33and the stabilizers of the geometric points of X in G ′ are linear and connected.We have G ′ sc = G sc , hence G ′ scu = G scu (because G scu = G sc and G ′ scu = G ′ sc ).It follows from the construction in the proof of Proposition 3.1 of [7] that there isa surjective homomorphism G abvar → G ′ abvar . Since by assumption X(G abvar ) isfinite, we obtain from [7], Lemma A.3 that X(G ′ abvar ) is finite.Let us prove that if a point x ∈ X(A) is orthogonal <<strong>strong</strong>>to</<strong>strong</strong>> Br 1 (X, G), then it isorthogonal <<strong>strong</strong>>to</<strong>strong</strong>> Br 1 (X, G ′ ). More precisely, we prove that Br 1 (X, G ′ ) is a subgroupof Br 1 (X, G).By construction (see [7], proof of Proposition 3.1), there is an exact sequenceof connected algebraic groups1 → S → G ′ q−→ G1 → 1,where G 1 is the quotient of G by the central subgroup Z(G)∩H and S is a k-<<strong>strong</strong>>to</<strong>strong</strong>>rus.Consider the following natural commutative diagram Xπ ′ π 1π1 S qG ′ G 1 1where the maps π, π ′ and π 1 are the natural quotient maps. From this diagram,we deduce the following one, where the second line is exact (see the <<strong>strong</strong>>to</<strong>strong</strong>>p row ofdiagram (11)):Br(X) π ∗π ∗ 10 = Pic(S) Br(G 1 )p ∗pGπ ′∗,q ∗ Br(G ′ )Br(G) .There<strong>for</strong>e, the injectivity of the map q ∗ : Br(G 1 ) → Br(G ′ ) implies that the naturalinclusion Br 1,x0 (X, G 1 ) ⊂ Br 1,x0 (X, G ′ ) is an equality. And by func<<strong>strong</strong>>to</<strong>strong</strong>>rialityBr 1,x0 (X, G 1 ) is a subgroup of Br 1,x0 (X, G).Thus Br 1,x0 (X, G ′ ) = Br 1,x0 (X, G 1 ) is a subgroup of Br 1,x0 (X, G). It followsthat if a point x ∈ X(A) is orthogonal <<strong>strong</strong>>to</<strong>strong</strong>> Br 1 (X, G), then it is orthogonal <<strong>strong</strong>>to</<strong>strong</strong>>Br 1 (X, G ′ ).Thus if Theorem 1.4 holds <strong>for</strong> the pair (X, G ′ ), then it holds <strong>for</strong> (X, G). Wesee that we may assume in the proof of Theorem 1.4 that G lin is reductive, G ss is

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