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TMdrive®-30 Product Application Guide - Tmeic.com

TMdrive®-30 Product Application Guide - Tmeic.com

TMdrive®-30 Product Application Guide - Tmeic.com

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Inverter SpecificationsFrameWeightkg (lbs)Full LoadLosseskWControlPowervaInverterOutputKVAMotorOutput PowerkW (hp)MotorCurrentA acAllowableOverload%IGBT Inverter (TMdrive-<strong>30</strong>)2406 mm (95 in)1<strong>30</strong>02000 25 1000 2000(2860)1615(2165)924 150792 175693 200554 2501800 mm (71 in)462 <strong>30</strong>02406 mm (95 in)2<strong>30</strong>04000 50 2000 4000(5060)32<strong>30</strong>(43<strong>30</strong>)1848 1501584 1751386 2001109 250<strong>30</strong>00 mm (118 in)924 <strong>30</strong>0Inverter ExampleWhen specifying an inverter, start from the process requirements and work through the motor to the inverter.The following example illustrates this process.1Define processrequirements.kW Shaft = 1500 kW(2000 hp)The motor delivers constant torque fromzero to base speed of 900 rpm and 1500 kW(2000 hp).Duty cycle requires 175% for 10 sec. but hasrms duty cycle of 1500 kW (2000 hp).2Select motor based onprocess requirements and<strong>com</strong>pute required inverterkVA.• 1500 kW (2000 hp)• 900 rpm, 1200 V• Efficiency = 0.954• Power factor = 0.765• Service factor = 1.15Compute continuous3current requirementsfor the inverter basedon the selected motor.I ac Inverter = kW Shaft x 1000 x SF MtrEff Mtr x PF Mtr x 3 x V Motor rated voltageCurrent= 1500 x 1000 x 1.150.954 x 0.765 x 3 x 1200 VA ac13864Select inverter based oncontinuous current andoverload requirements.Scan the 175% entries in theinverter tables for a frame wherethe continuous current ratingexceeds 1138 amps.The <strong>30</strong>00 frame meets thiscriterion (1188 amps) and isappropriate for this application.11881040832693AllowableOverload %150175200250<strong>30</strong>08

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