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Finite Strain Shape Memory Alloys Modeling - Scuola di Dottorato in ...

Finite Strain Shape Memory Alloys Modeling - Scuola di Dottorato in ...

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2∂ fε =Δζ∂ X∂fεt,Δζ= ∂ Xε = 0tX , 2t,γ(6.60)It follows that:d( ε ) = E : dε(6.61)twith:X X X⎡R, XR, R ⎤Δζ, γ ⎡−C⎤⎢ Δζ Δζ Δζ⎥E =−⎡εtX ,εt, ζ0 R, XR, ζR⎢, γ0⎥⎣⎤Δ ⎦⎢ Δ ⎥ ⎢ ⎥(6.62)⎢γ γ γR, XR, ΔζR ⎥⎣⎢, γ ⎦ ⎣ 0 ⎥⎦−1In conclusion, the consistent tangent matrix assumes the follow<strong>in</strong>g form:D= C( I−E )(6.63)114

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