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Page 1 PROBLEM 3.1 KNOWN: One-dimensional, plane wall ...

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<strong>PROBLEM</strong> 3.36 (Cont.)q =( )( − )55 20 Cln 0.417 0.392 1+2π0.026 W m K 0.784 m 2 W m K 2 0.417 m 0.784 m( ⋅ ) 2( ⋅ ) π ( )$+( − )2 55 20 C0.025 m 1+2 22( 0.026 W m ⋅ K) π 4( 0.784 m) ( 2 W m ⋅ K) π 4( 0.784 m)( )$$( )$35 C2 35 Cq = + = ( 48.2 + 2<strong>3.1</strong>)W = 71.3 W0.483 + 0.243 K W 1.992 + 1.036 K WThe annual energy loss is therefore( )−3( )( )( )Qannual= 71.3W 365days 24 h day 10 kW W = 625 kWhWith a unit electric power cost of $0.08/kWh, the annual cost of the heat loss isC = ($0.08/kWh)625 kWh = $50.00Hence, an insulation thickness ofδ = 25 mm

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